我正在构建一个laravel应用程序,我已经创建了一个FakerServiceProvider来填充工厂以进行测试和本地开发。
<?php
namespace App\Providers;
use Faker\Factory;
use Faker\Generator;
use Faker\Provider\en_GB\Address;
use Faker\Provider\en_GB\Person;
use Faker\Provider\en_GB\PhoneNumber;
use Illuminate\Contracts\Support\DeferrableProvider;
use Illuminate\Support\ServiceProvider;
/**
* Class FakerServiceProvider
* @package App\Providers
*/
class FakerServiceProvider extends ServiceProvider implements DeferrableProvider
{
/**
*
*/
public function register()
{
$this->app->singleton(Generator::class, function ($app) {
$factory = Factory::create('en_GB');
$factory->addProvider(Person::class);
$factory->addProvider(Address::class);
$factory->addProvider(PhoneNumber::class);
return $factory;
});
}
/**
* @return array
*/
public function provides()
{
return [Generator::class];
}
}
我创建了一个地址工厂:
<?php
use App\Address;
use App\Country;
$factory->define(Address::class, function (Faker\Generator $faker) {
return [
'line_1' => $faker->secondaryAddress,
'line_2' => $faker->streetAddress,
'town' => $faker->city,
'county' => $faker->county,
'country_id' => factory(Country::class)->make()->id,
'postcode' => $faker->postcode,
'phone' => $faker->phoneNumber,
];
});
当我尝试使用这个工厂时,我得到以下错误:ErrorException: call_user_func_array() expects parameter 1 to be a valid callback, non-static method Faker\Provider\Address::streetAddress() should not be called statically
我已经检查了Faker库的源代码,并且有一个streetAddress方法这里
我试着同时调用$faker->streetAddress
和$faker->streetAddress
‘或类似的东西。
有人能帮我弄清楚这件事吗
发布于 2020-03-20 14:36:48
删除Faker服务提供程序中添加的提供程序修复了该问题
https://stackoverflow.com/questions/60727650
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