blocks|key|990631|text|当排序时，seven_segment字典中没有等于'adeg‘、'abed’或'‘的值，因此"if+(templist+==+sorted_state)“行：”从不为真“。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|990632|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|D|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|E|8|@]|9|@]|A|$]]]|C|$]]

<p>There is no value in the seven_segment dictionary that equals 'adeg' or 'abed' or '' when sorted, so the line with "if (templist == sorted_state):" never is true</p>


blocks|key|2003072|text|解决方案|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2003073|我想这就是你想要的：|2003074|seven_segment+=+{'0':+{'a',+'c',+'d',+'e',+'b',+'f'},
+++++++++++++++++'1':+{'c',+'b'},
+++++++++++++++++'2':+{'a',+'d',+'e',+'b',+'g'},
+++++++++++++++++'3':+{'a',+'c',+'d',+'b',+'g'},
+++++++++++++++++'4':+{'g',+'c',+'f',+'b'},
+++++++++++++++++'5':+{'a',+'c',+'d',+'g',+'f'},
+++++++++++++++++'6':+{'a',+'c',+'d',+'e',+'g',+'f'},
+++++++++++++++++'7':+{'a',+'c',+'b'},
+++++++++++++++++'8':+{'a',+'c',+'d',+'e',+'b',+'g',+'f'},
+++++++++++++++++'9':+{'a',+'c',+'d',+'b',+'g',+'f'}}


def+guess_damaged(display,+state,+damaged):
++++return+{
++++++++key
++++++++for+key,+value+in+display.items()
++++++++if+set(state)+==+(value+-+set(damaged))
++++}


print(guess_damaged(seven_segment,+'adeg',+'bf'))
print(guess_damaged(seven_segment,+'abed',+'cf'))
print(guess_damaged(seven_segment,+'',+'abcdefg'))|code-block|syntax|javascript|2003075|产出：|2003076|{'2'}
{'0'}
{'7',+'1',+'5',+'0',+'9',+'4',+'2',+'6',+'3',+'8'}|2003077|2003078|解释|2003079|set是非常强大的内置类.reference+page+about+set|offset|length|style|CODE|2003080|您可以使用set执行|2003081|2003082|union(%7C)|unordered-list-item|2003083|intersect(&)|2003084|difference(-)|2003085|symmetric+difference(%5E)|2003086|subset关系(<=，<，>，>=)|2003087|equality(==，!=)|2003088|+)|2003089|entityMap|0|LINK|mutability|MUTABLE|url|https://docs.python.org/3.8/library/stdtypes.html#set^0|0|0|0|0|0|0|0|0|3|Y|3|D|O|0|0|5|3|0|0|6|1|0|A|1|0|B|1|0|L|1|0|9|2|C|1|E|1|G|2|0|9|2|C|2|0|0^^$0|@$1|2|3|4|5|6|7|1L|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|1M|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|1N|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|6|7|1O|8|@]|9|@]|A|$]]|$1|K|3|L|5|F|7|1P|8|@]|9|@]|A|$G|H]]|$1|M|3|-4|5|6|7|1Q|8|@]|9|@]|A|$]]|$1|N|3|O|5|6|7|1R|8|@]|9|@]|A|$]]|$1|P|3|Q|5|6|7|1S|8|@$R|1T|S|1U|T|U]|$R|1V|S|1W|T|U]]|9|@$R|1X|S|1Y|1|1Z]]|A|$]]|$1|V|3|W|5|6|7|20|8|@$R|21|S|22|T|U]]|9|@]|A|$]]|$1|X|3|-4|5|6|7|23|8|@]|9|@]|A|$]]|$1|Y|3|Z|5|10|7|24|8|@$R|25|S|26|T|U]]|9|@]|A|$]]|$1|11|3|12|5|10|7|27|8|@$R|28|S|29|T|U]]|9|@]|A|$]]|$1|13|3|14|5|10|7|2A|8|@$R|2B|S|2C|T|U]]|9|@]|A|$]]|$1|15|3|16|5|10|7|2D|8|@$R|2E|S|2F|T|U]]|9|@]|A|$]]|$1|17|3|18|5|10|7|2G|8|@$R|2H|S|2I|T|U]|$R|2J|S|2K|T|U]|$R|2L|S|2M|T|U]|$R|2N|S|2O|T|U]]|9|@]|A|$]]|$1|19|3|1A|5|10|7|2P|8|@$R|2Q|S|2R|T|U]|$R|2S|S|2T|T|U]]|9|@]|A|$]]|$1|1B|3|1C|5|6|7|2U|8|@]|9|@]|A|$]]|$1|1D|3|-4|5|6|7|2V|8|@]|9|@]|A|$]]]|1E|$1F|$5|1G|1H|1I|A|$1J|1K]]]]

<h3>Solution</h3>

<p>I think this is what you want:</p>

<pre class="lang-py prettyprint-override"><code>seven_segment = {'0': {'a', 'c', 'd', 'e', 'b', 'f'},
                 '1': {'c', 'b'},
                 '2': {'a', 'd', 'e', 'b', 'g'},
                 '3': {'a', 'c', 'd', 'b', 'g'},
                 '4': {'g', 'c', 'f', 'b'},
                 '5': {'a', 'c', 'd', 'g', 'f'},
                 '6': {'a', 'c', 'd', 'e', 'g', 'f'},
                 '7': {'a', 'c', 'b'},
                 '8': {'a', 'c', 'd', 'e', 'b', 'g', 'f'},
                 '9': {'a', 'c', 'd', 'b', 'g', 'f'}}


def guess_damaged(display, state, damaged):
    return {
        key
        for key, value in display.items()
        if set(state) == (value - set(damaged))
    }


print(guess_damaged(seven_segment, 'adeg', 'bf'))
print(guess_damaged(seven_segment, 'abed', 'cf'))
print(guess_damaged(seven_segment, '', 'abcdefg'))
</code></pre>

<p>output:</p>

<pre class="lang-py prettyprint-override"><code>{'2'}
{'0'}
{'7', '1', '5', '0', '9', '4', '2', '6', '3', '8'}
</code></pre>

<hr>

<h3>Explaination</h3>

<p><code>set</code> is very powerful built-in class. <a href="https://docs.python.org/3.8/library/stdtypes.html#set" rel="nofollow noreferrer">reference page about <code>set</code></a><br>
You can perform with <code>set</code>:</p>

<ul>
<li>union(<code>|</code>)</li>
<li>intersect(<code>&amp;</code>)</li>
<li>difference(<code>-</code>)</li>
<li>symmetric difference(<code>^</code>)</li>
<li>subset relations(<code>&lt;=</code>, <code>&lt;</code>, <code>&gt;</code>, <code>&gt;=</code>)</li>
<li>equality(<code>==</code>, <code>!=</code>)</li>
</ul>


<p>This is my dictionary:</p>

<pre><code>seven_segment = {'0': {'a','c','d','e','b','f'},
                 '1': {'c','b'},
                 '2': {'a','d','e','b','g'},
                 '3': {'a','c','d','b','g'},
                 '4': {'g','c','f','b'},
                 '5': {'a','c','d','g','f'},
                 '6': {'a','c','d','e','g','f'},
                 '7': {'a','c','b'},
                 '8': {'a','c','d','e','b','g','f'},
                 '9': {'a','c','d','b','g','f'}}
</code></pre>

<p>I have a function created:</p>

<pre><code>def guess_damaged(display, state, damaged):
    sorted_state = ''.join(sorted(state))
    sorted_damaged = ''.join(sorted(damaged))
    for key in display:
        templist = list(display[key])
        templist = sorted(templist)
        templist = ''.join(templist)
        if(templist == sorted_state):
            return {key for key,value in display.items() if all(sorted_damaged in value for sorted_damaged in sorted_state)}


print(guess_damaged(seven_segment, 'adeg', 'bf'))
print(guess_damaged(seven_segment, 'abed', 'cf'))
print(guess_damaged(seven_segment, '', 'abcdefg'))
</code></pre>

<p>My current output is shown below:</p>

<pre><code>None
None
None
</code></pre>

<p>However, this is my desired output:</p>

<pre><code>{'2'}
{'0'}
{'4', '5', '1', '8', '7', '6', '3', '0', '2', '9'}
</code></pre>

<p>How can I get the desired output?</p>


Function to return values in dictionary

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

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这是我的字典：seven_segment = {'0': {'a','c','d','e','b','f'},                 '1': {'c','b'},                 '2': {'a','d','e','b','g'},                 '3': {'a','c...

问函数返回字典中的值。
EN

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问函数返回字典中的值。EN