blocks|key|1022509|text|我认为这不是最干净的解决方案，但它应该有效:)|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1022510|​|1022511|const+items+=+[...Array(20).keys()];

let+currentIndex+=+1;
const+data+=+{
++flexbox1:+[],
++flexbox2:+[],
++flexbox3:+[],
++flexbox4:+[]
};

for+(const+item+in+items)+{
++data[`flexbox${currentIndex}`].push(item);
++currentIndex+=+currentIndex+===+4+?+1+:+currentIndex+%2B+1;
}

console.log(data);|code-block|syntax|javascript|1022512|1022513|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|L|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|M|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|N|8|@]|9|@]|A|$G|H]]|$1|I|3|C|5|6|7|O|8|@]|9|@]|A|$]]|$1|J|3|-4|5|6|7|P|8|@]|9|@]|A|$]]]|K|$]]

<p>I think it is not the cleanest solution, but it should work :)</p>

<p><div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>const items = [...Array(20).keys()];

let currentIndex = 1;
const data = {
  flexbox1: [],
  flexbox2: [],
  flexbox3: [],
  flexbox4: []
};

for (const item in items) {
  data[`flexbox${currentIndex}`].push(item);
  currentIndex = currentIndex === 4 ? 1 : currentIndex + 1;
}

console.log(data);</code></pre>
</div>
</div>
</p>


blocks|key|2034727|text|​|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2034728|const+items+=+['a1','a2','a3','a4','a5','a6','a7','a8','a9','a10','a11','a12']

const+flexbox1+=+[];
const+flexbox2+=+[];
const+flexbox3+=+[];
const+flexbox4+=+[];



items.forEach((item,index)=>+{
++if(+index%254+==0+)+{+flexbox1.push(item)+}
++else+if(+index%254+==1+)+{+flexbox2.push(item)+}
++else+if(+index%254+==2+)+{+flexbox3.push(item)+}
++else+if(+index%254+==3+)+{+flexbox4.push(item)+}
})


console.log(flexbox1);
console.log(flexbox2);
console.log(flexbox3);
console.log(flexbox4);|code-block|syntax|javascript|2034729|2034730|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|J|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|K|8|@]|9|@]|A|$E|F]]|$1|G|3|4|5|6|7|L|8|@]|9|@]|A|$]]|$1|H|3|-4|5|6|7|M|8|@]|9|@]|A|$]]]|I|$]]

<p><div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>const items = ['a1','a2','a3','a4','a5','a6','a7','a8','a9','a10','a11','a12']

const flexbox1 = [];
const flexbox2 = [];
const flexbox3 = [];
const flexbox4 = [];



items.forEach((item,index)=&gt; {
  if( index%4 ==0 ) { flexbox1.push(item) }
  else if( index%4 ==1 ) { flexbox2.push(item) }
  else if( index%4 ==2 ) { flexbox3.push(item) }
  else if( index%4 ==3 ) { flexbox4.push(item) }
})


console.log(flexbox1);
console.log(flexbox2);
console.log(flexbox3);
console.log(flexbox4);</code></pre>
</div>
</div>
</p>


blocks|key|1022539|text|下面是使用模运算符将项放入4个桶中的一种方法。这个解决方案可以扩展到任何数量的桶。片段中的函数allocateFlexboxes正是实现了这一点。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1022540|一旦for循环结束，您就可以通过索引访问所需的flexbox。|1022541|​|1022542|const+items+=+[1,+2,+3,+4,+5,+6,+7,+8,+9,+10,+11,+12]


let+flexBoxes+=+[[],+[],+[],+[]];

for+(let+i=0;+i<items.length;+i%2B%2B)+{
++const+bucketIndex+=+i+%25+4;

++flexBoxes[bucketIndex].push(items[i]);
}

console.log("Bucket+size:+4");
console.log(flexBoxes);

//+Generic+function+that+can+accommodate+for+any+number
const+allocateFlexboxes+=+(items,+flexBoxCount)+=>+{
++let+flexBoxes+=+[...new+Array(flexBoxCount)].map(x+=>+[])
++
++items.forEach((item,+index)+=>+{
++++const+bucketIndex+=+index+%25+flexBoxCount;
++++
++++flexBoxes[bucketIndex].push(item);
++});
++
++return+flexBoxes;
}|code-block|syntax|javascript|1022543|1022544|entityMap^0|1B|H|0|2|3|0|0|0|0^^$0|@$1|2|3|4|5|6|7|R|8|@$9|S|A|T|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|U|8|@$9|V|A|W|B|C]]|D|@]|E|$]]|$1|H|3|I|5|6|7|X|8|@]|D|@]|E|$]]|$1|J|3|K|5|L|7|Y|8|@]|D|@]|E|$M|N]]|$1|O|3|I|5|6|7|Z|8|@]|D|@]|E|$]]|$1|P|3|-4|5|6|7|10|8|@]|D|@]|E|$]]]|Q|$]]

<p>Below is one approach to put items into the 4 buckets using the modulo operator. This solution can be extended to account for any number of buckets. The function <code>allocateFlexboxes</code> in the snippet achieves just that.</p>

<p>Once the <code>for</code> loop ends, you can access desired flexbox by the index.</p>

<p><div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>const items = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12]


let flexBoxes = [[], [], [], []];

for (let i=0; i&lt;items.length; i++) {
  const bucketIndex = i % 4;

  flexBoxes[bucketIndex].push(items[i]);
}

console.log("Bucket size: 4");
console.log(flexBoxes);

// Generic function that can accommodate for any number
const allocateFlexboxes = (items, flexBoxCount) =&gt; {
  let flexBoxes = [...new Array(flexBoxCount)].map(x =&gt; [])
  
  items.forEach((item, index) =&gt; {
    const bucketIndex = index % flexBoxCount;
    
    flexBoxes[bucketIndex].push(item);
  });
  
  return flexBoxes;
}</code></pre>
</div>
</div>
</p>


blocks|key|2034814|text|使用一个简单的for循环，将计数器递增4：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|2034815|​|2034816|const+items+=+Array.from({+length:+40+},+(_,+i)+=>+"a"+%2B+(i%2B1));

const+flexbox1+=+[];
const+flexbox2+=+[];
const+flexbox3+=+[];
const+flexbox4+=+[];

for+(let+i+=+0;+i+<+items.length;+i+%2B=+4)+{
++flexbox1.push(items[i]);
++flexbox2.push(items[i+%2B+1]);
++flexbox3.push(items[i+%2B+2]);
++flexbox4.push(items[i+%2B+3]);
}

console.log({
++flexbox1,
++flexbox2,
++flexbox3,
++flexbox4
});|code-block|syntax|javascript|2034817|2034818|entityMap^0|7|3|0|0|0|0^^$0|@$1|2|3|4|5|6|7|P|8|@$9|Q|A|R|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|S|8|@]|D|@]|E|$]]|$1|H|3|I|5|J|7|T|8|@]|D|@]|E|$K|L]]|$1|M|3|G|5|6|7|U|8|@]|D|@]|E|$]]|$1|N|3|-4|5|6|7|V|8|@]|D|@]|E|$]]]|O|$]]

<p>use a simple <code>for</code> loop incrementing the counter by 4 :</p>

<p><div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>const items = Array.from({ length: 40 }, (_, i) =&gt; "a" + (i+1));

const flexbox1 = [];
const flexbox2 = [];
const flexbox3 = [];
const flexbox4 = [];

for (let i = 0; i &lt; items.length; i += 4) {
  flexbox1.push(items[i]);
  flexbox2.push(items[i + 1]);
  flexbox3.push(items[i + 2]);
  flexbox4.push(items[i + 3]);
}

console.log({
  flexbox1,
  flexbox2,
  flexbox3,
  flexbox4
});</code></pre>
</div>
</div>
</p>


blocks|key|2034820|text|​|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2034821|let+r1+=+[],+r2+=+[],+r3+=+[],+r4+=+[];
let+x+=+0;
const+items+=+["a1",+"a2",+"a3",+"a4",+"a5",+"a6",+"a7",+"a8",+"a9"];
for+(let+i+=+0;+i+<+items.length+-+1;+i%2B%2B)+{
if+(x+%25+4+===+0)+{
++++r1.push(items[i]);
++++x%2B%2B;
}+else+if+(x+%25+4+===+1)+{
++++r2.push(items[i]);
++++x%2B%2B;
}+else+if+(x+%25+4+===+2)+{
++++r3.push(items[i]);
++++x%2B%2B;
}+else+if+(x+%25+4+===+3)+{
++++r4.push(items[i]);
++++x%2B%2B;
}
}
console.log(r1,+r2,+r3,+r4);|code-block|syntax|javascript|2034822|2034823|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|J|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|K|8|@]|9|@]|A|$E|F]]|$1|G|3|4|5|6|7|L|8|@]|9|@]|A|$]]|$1|H|3|-4|5|6|7|M|8|@]|9|@]|A|$]]]|I|$]]

<p><div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>let r1 = [], r2 = [], r3 = [], r4 = [];
let x = 0;
const items = ["a1", "a2", "a3", "a4", "a5", "a6", "a7", "a8", "a9"];
for (let i = 0; i &lt; items.length - 1; i++) {
if (x % 4 === 0) {
    r1.push(items[i]);
    x++;
} else if (x % 4 === 1) {
    r2.push(items[i]);
    x++;
} else if (x % 4 === 2) {
    r3.push(items[i]);
    x++;
} else if (x % 4 === 3) {
    r4.push(items[i]);
    x++;
}
}
console.log(r1, r2, r3, r4);</code></pre>
</div>
</div>
</p>


blocks|key|290472|text|一种方法可以是这样的：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|290473|for+(var+i+=+0;+i+<+items.length;+i%2B%2B)+{
++flexbox1.push(items[4+*+i]);
++flexbox2.push(items[4+*+i+%2B+1]);
++flexbox3.push(items[4+*+i+%2B+2]);
++flexbox4.push(items[4+*+i+%2B+3]);

}|code-block|syntax|javascript|290474|​|290475|const+items+=+["a1",+"a2",+"a3",+"a4",+"a5",+"a6",+"a7",+"a8",+"a9"]

const+flexbox1+=+[];
const+flexbox2+=+[];
const+flexbox3+=+[];
const+flexbox4+=+[];


for+(var+i+=+0;+i+<+items.length;+i%2B%2B)+{
++flexbox1.push(items[4+*+i]);
++flexbox2.push(items[4+*+i+%2B+1]);
++flexbox3.push(items[4+*+i+%2B+2]);
++flexbox4.push(items[4+*+i+%2B+3]);

}

document.querySelector('.foo').innerHTML+=+flexbox1+%2B+"<br>"+%2B+flexbox2+%2B+"<br>"+%2B+flexbox3+%2B+"<br>"+%2B+flexbox4;|290476|<div+class="foo"></div>|290477|290478|这个方法并不完美，因为它在到达items.length之前一直在数组中添加元素，但是应该足够实现这个目标。|offset|length|style|CODE|290479|entityMap^0|0|0|0|0|0|0|F|C|0^^$0|@$1|2|3|4|5|6|7|V|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|W|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|X|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|Y|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|D|7|Z|8|@]|9|@]|A|$E|F]]|$1|M|3|H|5|6|7|10|8|@]|9|@]|A|$]]|$1|N|3|O|5|6|7|11|8|@$P|12|Q|13|R|S]]|9|@]|A|$]]|$1|T|3|-4|5|6|7|14|8|@]|9|@]|A|$]]]|U|$]]

<p>An approach could be something like this:</p>

<pre><code>for (var i = 0; i &lt; items.length; i++) {
  flexbox1.push(items[4 * i]);
  flexbox2.push(items[4 * i + 1]);
  flexbox3.push(items[4 * i + 2]);
  flexbox4.push(items[4 * i + 3]);

}
</code></pre>

<p><div class="snippet" data-lang="js" data-hide="true" data-console="true" data-babel="false">
<div class="snippet-code snippet-currently-hidden">
<pre class="snippet-code-js lang-js prettyprint-override"><code>const items = ["a1", "a2", "a3", "a4", "a5", "a6", "a7", "a8", "a9"]

const flexbox1 = [];
const flexbox2 = [];
const flexbox3 = [];
const flexbox4 = [];


for (var i = 0; i &lt; items.length; i++) {
  flexbox1.push(items[4 * i]);
  flexbox2.push(items[4 * i + 1]);
  flexbox3.push(items[4 * i + 2]);
  flexbox4.push(items[4 * i + 3]);

}

document.querySelector('.foo').innerHTML = flexbox1 + "&lt;br&gt;" + flexbox2 + "&lt;br&gt;" + flexbox3 + "&lt;br&gt;" + flexbox4;</code></pre>
<pre class="snippet-code-html lang-html prettyprint-override"><code>&lt;div class="foo"&gt;&lt;/div&gt;</code></pre>
</div>
</div>
</p>

<p>This method isn't perfect as it keeps adding elements in the array until the <code>items.length</code> is reached, but should be enough to get the idea.</p>


blocks|key|1022622|text|由于您希望在4个不同的数组中分配项，所以可以根据它们的索引模块4将每个项推送到不同的数组中。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1022623|​|1022624|const+items+=+['a1',+'a2',+'a3',+'a4',+'a5',+'a6',+'a7',+'a8',+'a9',+'a10']

const+flexbox1+=+[];
const+flexbox2+=+[];
const+flexbox3+=+[];
const+flexbox4+=+[];

const+flexboxes+=+[flexbox1,+flexbox2,+flexbox3,+flexbox4];

items.map((item,+index)+=>+{
++flexboxes[index%254].push(item);
});|code-block|syntax|javascript|1022625|1022626|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|L|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|M|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|N|8|@]|9|@]|A|$G|H]]|$1|I|3|C|5|6|7|O|8|@]|9|@]|A|$]]|$1|J|3|-4|5|6|7|P|8|@]|9|@]|A|$]]]|K|$]]

<p>Since you want to allocate items in 4 different arrays, you can push each item to a different array according to their index modulo 4.</p>

<p><div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>const items = ['a1', 'a2', 'a3', 'a4', 'a5', 'a6', 'a7', 'a8', 'a9', 'a10']

const flexbox1 = [];
const flexbox2 = [];
const flexbox3 = [];
const flexbox4 = [];

const flexboxes = [flexbox1, flexbox2, flexbox3, flexbox4];

items.map((item, index) =&gt; {
  flexboxes[index%4].push(item);
});</code></pre>
</div>
</div>
</p>


blocks|key|2034914|text|我很久以前就不得不这么做了。这是我最后写的函数。它所采用的方法与将项推到数组中的方法略有不同。我不知道它是否更快，但是所有数组大小都是通过这种方法预先知道的。它还处理剩馀列和填补所有行的项目太少。|type|unstyled|depth|inlineStyleRanges|offset|length|style|BOLD|entityRanges|data|2034915|​|2034916|let+to2D+=+(items,+n)+=>+[...Array(Math.min(items.length,+n))].map(
++(_,+row)+=>+[...Array((items.length+%2B+n+-+1+-+row)+/+n+>>>+0)].map(
++++(_,+column)+=>+items[column+*+n+%2B+row]
++)
);


let+exampleItems+=+[...Array(17).keys()].map(i+=>+`a${i+%2B+1}`);
console.log(to2D(exampleItems,+4))|code-block|syntax|javascript|2034917|2034918|FYI产出：|2034919|[
++[+'a1',+'a5',+'a9',+'a13',+'a17'+],
++[+'a2',+'a6',+'a10',+'a14'+],
++[+'a3',+'a7',+'a11',+'a15'+],
++[+'a4',+'a8',+'a12',+'a16'+]
]|2034920|entityMap^0|1N|J|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|T|8|@$9|U|A|V|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|W|8|@]|D|@]|E|$]]|$1|H|3|I|5|J|7|X|8|@]|D|@]|E|$K|L]]|$1|M|3|G|5|6|7|Y|8|@]|D|@]|E|$]]|$1|N|3|O|5|6|7|Z|8|@]|D|@]|E|$]]|$1|P|3|Q|5|J|7|10|8|@]|D|@]|E|$K|L]]|$1|R|3|-4|5|6|7|11|8|@]|D|@]|E|$]]]|S|$]]

<p>I had to do this once upon a time.  Here's the function I wound up writing.  It takes a slightly different approach than pushing items into an array.  I have no idea if it's faster, but <strong>all the array sizes are known up front</strong> with this approach.  It also handles having leftover columns and having too few items to fill all rows.</p>

<p><div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>let to2D = (items, n) =&gt; [...Array(Math.min(items.length, n))].map(
  (_, row) =&gt; [...Array((items.length + n - 1 - row) / n &gt;&gt;&gt; 0)].map(
    (_, column) =&gt; items[column * n + row]
  )
);


let exampleItems = [...Array(17).keys()].map(i =&gt; `a${i + 1}`);
console.log(to2D(exampleItems, 4))</code></pre>
</div>
</div>
</p>

<p>FYI Output:</p>

<pre><code>[
  [ 'a1', 'a5', 'a9', 'a13', 'a17' ],
  [ 'a2', 'a6', 'a10', 'a14' ],
  [ 'a3', 'a7', 'a11', 'a15' ],
  [ 'a4', 'a8', 'a12', 'a16' ]
]
</code></pre>


<p>I wonder the title is right or not, </p>

<p>anyway what I wonder is how can do thing like this</p>

<pre><code>const items = [a1,a2,a3,a4,a5,a6,a7,a8,a9 .. and so on ]

const flexbox1 = [];
const flexbox2 = [];
const flexbox3 = [];
const flexbox4 = [];



for (const item in items) {

// what I wonder is this part. 

      }


==&gt; result:

const flexbox1 = [a1,a5,a9,a13 .. and so on];
const flexbox2 = [a2,a6,a10,a14 .. and so on];
const flexbox3 = [a3,a7,a11,a15 .. and so on];
const flexbox4 = [a4,a8,a12,a16 ... and so on];



</code></pre>

<p>How can I get the results above??</p>

<p>I've been trying for two days to find the answer in the book and on the internet, but I couldn't find it.</p>

<p>please help .... </p>

<p>Thanks in advance.</p>


how to put items in an array sequentially?(javascript)

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我想知道这个标题是否正确，不管怎样，我想知道的是，怎样才能做到这样的事情？const items = [a1,a2,a3,a4,a5,a6,a7,a8,a9 .. and so on ]const flexbox1 = [];const flexbox2 = [];const flexbox3 = [];const f...

问如何顺序地将项放入数组中？(Javascript)
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问如何顺序地将项放入数组中？(Javascript)EN