显示完整的x-轴，即使没有点可绘制。
显示完整的x-轴，即使没有点可绘制。
提问于 2020-03-03 10:51:41
我正在巧妙地用line+markers绘制散点图。问题是，我有一个明确的x轴，我想修复它的所有情节的全范围静态。
下面是示例代码：
import(plotly)
x_group <- c('[8-9]','[9-10]','[10-11]','[11-12]','[12-13]','[13-14]','[14-15]','[16-17]','[17-18]','[18-19]','[19-20]')
total <- c('22','17','27','8 ','16','4 ','17','12','15','2 ','22')
example_df <- as.data.frame(list(hour_bin_grp= x_group, total = total))
m <- list(
l = 50,
r = 50,
b = 100,
t = 100,
pad = 4
)
hour_bins <- c("[0-7]","[7-8]","[8-9]","[9-10]","[10-11]", "[11-12]","[12-13]", "[13-14]", "[14-15]", "[15-16]","[16-17]", "[17-18]","[18-19]", "[19-20]", "[20-21]","[21-22]")
p <- plot_ly(example_df, x = ~hour_bin_grp, y = ~total, type = 'scatter', mode = 'markers+lines') %>%
layout(autosize = T, margin = m,
xaxis = list(
type='category',
categoryorder= 'array',
showgrid = TRUE,
autorange = FALSE,
showticklabels = TRUE,
categoryarray= unique(hour_bins)
),
yaxis = list(
showgrid = TRUE,
autorange = TRUE,
showline = TRUE,
showticklabels = TRUE,
rangemode = "tozero",
))
p这个图似乎没问题，但我想把x轴的范围修正为hour_bins的值。
我已经查过一些同样的文章，但在我的情况下似乎行不通：
Plotly.js: Cannot show full categorical x-axis
https://community.plot.ly/t/cannot-re-arrange-x-axis-when-axis-type-is-category/1274/3
回答 1
Stack Overflow用户
回答已采纳
发布于 2020-03-10 11:20:09
作为一种解决办法，我建议使用带有字符ticktext的数字滴答：
library(plotly)
bin_df <- data.frame(hour_bins = c("[0-7]","[7-8]","[8-9]","[9-10]","[10-11]", "[11-12]","[12-13]", "[13-14]", "[14-15]", "[15-16]","[16-17]", "[17-18]","[18-19]", "[19-20]", "[20-21]","[21-22]"))
bin_df$hour_bin_grp <- seq_len(nrow(bin_df))
example_df <- data.frame(hour_bin_grp = bin_df$hour_bin_grp[bin_df$hour_bins %in% c('[8-9]','[9-10]','[10-11]','[11-12]','[12-13]','[13-14]','[14-15]','[16-17]','[17-18]','[18-19]','[19-20]')], total = as.numeric(c('22','17','27','8','16','4','17','12','15','2','22')))
p <- plot_ly(example_df, x = ~hour_bin_grp, y = ~total, type = 'scatter', mode = 'markers+lines') %>%
layout(xaxis = list(
tickmode = "array",
tickvals = bin_df$hour_bin_grp,
ticktext = example_df$hour_bins,
range = list(min(bin_df$hour_bin_grp), max(bin_df$hour_bin_grp))
))
p
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/60505584
复制相关文章
相似问题
腾讯云开发者
