我知道以前有人问过这个问题,但我的问题与其他问题略有不同。
我编写了一个python脚本来读取随机地址并返回它们的位置ID。
这是我的密码:
from googleplaces import GooglePlaces
import pandas as pd
import time
import xlrd
YOUR_API_KEY = <my_key>
google_places = GooglePlaces(YOUR_API_KEY)
loc = r"C:\Users\user\Desktop\test.xlsx"
wb = xlrd.open_workbook(loc)
sheet = wb.sheet_by_index(0)
for i in range(1,sheet.nrows):
read_address = sheet.cell_value(i,0)
query_result = google_places.text_search(
query=''+read_address)
for place in query_result.places:
print(place.name)
print(place.place_id)
控制台输出:
C:\Users\csjeemah\PycharmProjects\googleplaces\venv\Scripts\python.exe C:/Users/csjeemah/PycharmProjects/googleplaces/googleplaceID.py
777 Brockton Ave
ChIJmf-3TW6b5IkR1rx0eohvqPQ
30 Memorial Dr
ChIJXa_KpmGD5IkRYtpt2IsXmqg
Traceback (most recent call last):
File "C:/Users/csjeemah/PycharmProjects/googleplaces/googleplaceID.py", line 27, in <module>
query_result = google_places.text_search(
File "C:\Users\csjeemah\PycharmProjects\googleplaces\venv\lib\site-packages\googleplaces\__init__.py", line 353, in text_search
_validate_response(url, places_response)
File "C:\Users\csjeemah\PycharmProjects\googleplaces\venv\lib\site-packages\googleplaces\__init__.py", line 175, in _validate_response
raise GooglePlacesError(error_detail)
googleplaces.GooglePlacesError: Request to URL https://maps.googleapis.com/maps/api/place/textsearch/json?query=250+Hartford+Avenue%2C+Bellingham+MA+2019&radius=3200&language=en&key=mykey&sensor=false failed with response code: OVER_QUERY_LIMIT
在上面的控制台屏幕截图中,它返回前两个地址的结果,然后是错误occurs.Now --我理解这个错误的原因是,我可以发出的请求数量受到限制,但正如您从上面的图像中看到的:
它现在在失败之前检索更多的地址:
C:\Users\csjeemah\PycharmProjects\googleplaces\venv\Scripts\python.exe C:/Users/csjeemah/PycharmProjects/googleplaces/googleplaceID.py
777 Brockton Ave
ChIJmf-3TW6b5IkR1rx0eohvqPQ
30 Memorial Dr
ChIJt_pwFGsUc2sR-ve6pnT9DlA
30 Memorial Dr
ChIJJatf08pZIWsRr2u-ppt2CyI
250 Hartford Ave
ChIJk567q-Jx5IkRGxbCzkmYU7A
Traceback (most recent call last):
File "C:/Users/csjeemah/PycharmProjects/googleplaces/googleplaceID.py", line 27, in <module>
query_result = google_places.text_search(
File "C:\Users\csjeemah\PycharmProjects\googleplaces\venv\lib\site-packages\googleplaces\__init__.py", line 353, in text_search
_validate_response(url, places_response)
File "C:\Users\csjeemah\PycharmProjects\googleplaces\venv\lib\site-packages\googleplaces\__init__.py", line 175, in _validate_response
raise GooglePlacesError(error_detail)
googleplaces.GooglePlacesError: Request to URL https://maps.googleapis.com/maps/api/place/textsearch/json?query=700+Oak+Street&radius=3200&language=en&key=mykey&sensor=false failed with response code: OVER_QUERY_LIMIT
我还试着在每次查询之后添加几秒钟的睡眠,但是它失败了,有人能告诉我问题出在哪里吗?
发布于 2020-01-23 04:04:09
图像中的错误json清楚地指出,您已经超出了places的每日请求配额。
如果您希望继续,您需要将您的GCP项目与计费帐户相关联。
发布于 2020-01-23 07:40:23
直接来自文档Google平台Web服务的使用限制
您可以通过以下方式超过Google平台web服务的使用限制:
在收到状态代码OVER_QUERY_LIMIT的响应后,应用程序应该确定已经超过了哪个使用限制。这可以通过暂停2秒并重新发送相同的请求来完成。如果状态代码仍然是OVER_QUERY_LIMIT,则应用程序每天发送的请求太多。否则,应用程序每秒发送的请求太多。
url = "MAPS_API_WEBSERVICE_URL"
attempts = 0
success = False
while success != True and attempts < 3:
raw_result = urllib.urlopen(url).read()
attempts += 1
# The GetStatus function parses the answer and returns the status code
# This function is out of the scope of this example (you can use a SDK).
status = GetStatus(raw_result)
if status == "OVER_QUERY_LIMIT":
time.sleep(2)
# retry
continue
success = True
if attempts == 3:
# send an alert as this means that the daily limit has been reached
print "Daily limit has been reached"
https://stackoverflow.com/questions/59871191
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