如何在使用end='‘时打印两个不同的字符串？
如何在使用end='‘时打印两个不同的字符串？
提问于 2019-11-03 15:48:21
我试图交替打印这两个字符串，但如果不使用end='‘，就无法找到绕过它的方法。我试图使用尽可能小的字符串，我的目标是只使用两个字符串。
num_of_stars = int(input("How many stars would you like on each line?:
"))
lines1 = 0
lines2 = 0
alternator = 0
def line1(num_of_stars):
for i in range(num_of_stars):
print("*", end=' ')
def line2(num_of_stars):
for i in range(num_of_stars):
print(" *", end='')
while lines1 <= 4 and lines2 <= 4:
if alternator == 0:
line1(num_of_stars)
lines1 += 1
alternator = 1
elif alternator == 1:
line2(num_of_stars)
lines2 += 1
alternator = 0我的结果是：** *
回答 2
Stack Overflow用户
回答已采纳
发布于 2019-11-03 16:04:47
你想要什么还不清楚。但是您可能不想使用代码中显示的print( ... , end=...)技术。
分配会简单得多
stars = ['*'] * num_of_stars
line = ' '.join(stars)然后
for i in range(4):
indent = ' '[:i % 2]
print(indent + line)根据我是偶数还是奇数，indent字符串将为空或空。
Stack Overflow用户
发布于 2019-11-07 23:25:25
首先，第2行函数的末尾只是一个空白，这就解释了为什么有2颗恒星的群间隔在一起。试试这个：
num_of_stars = int(input("How many stars would you like on each line?: "))
lines1 = 0
lines2 = 0
alternator = 0
def line1(num_of_stars):
for i in range(num_of_stars):
print("*", end="")
print("\n")
def line2(num_of_stars):
for i in range(num_of_stars):
print("*", end="")
print("\n")
while lines1 <= 4 and lines2 <= 4:
if alternator == 0:
line1(num_of_stars)
lines1 += 1
alternator = 1
elif alternator == 1:
line2(num_of_stars)
lines2 += 1
alternator = 0页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/58681815
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