问如何在发送时不显示推送消息而运行该函数？

EN

    @available(iOS 10, *)
    func userNotificationCenter(_ center: UNUserNotificationCenter,
                                didReceive response: UNNotificationResponse,
                                withCompletionHandler completionHandler: @escaping () -> Void) {
        let data = response.notification.request.content.userInfo

        guard
            let push = data[AnyHashable("push")] as? String,
            let getdata = data[AnyHashable("getdata")] as? String,
            let pushdata = data[AnyHashable("pushdata")] as? String
            else {
                print("it's not good data")
                return
        }
        print(push)
        print(getdata)
        print(pushdata)
}

   @available(iOS 10.0, *)
    func userNotificationCenter(_ center: UNUserNotificationCenter,
                                willPresent notification: UNNotification,
                                withCompletionHandler completionHandler: @escaping (UNNotificationPresentationOptions) -> Void)
    {
        completionHandler([.alert, .badge, .sound])
    }

 func application(_ application: UIApplication, didFinishLaunchingWithOptions launchOptions: [UIApplication.LaunchOptionsKey: Any]?) -> Bool {

        self.window = UIWindow(frame: UIScreen.main.bounds)
        // Override point for customization after application launch.
        //create the notificationCenter
        Messaging.messaging().delegate = self
        FirebaseApp.configure()

        //Register App For Push Notification
        //        self.registerAppForPushNotificaition()
        let center = UNUserNotificationCenter.current()
        let inviteCategory = UNNotificationCategory(identifier: "Notification", actions: [], intentIdentifiers: [], options: UNNotificationCategoryOptions.customDismissAction)
        let categories = NSSet(objects: inviteCategory)

        center.delegate = self
        center.setNotificationCategories(categories as! Set<UNNotificationCategory>)
        DispatchQueue.main.async(execute: {
            UIApplication.shared.registerForRemoteNotifications()
        })
        application.registerForRemoteNotifications()
        self.updateAppViewUI()
        self.window?.makeKeyAndVisible()
        return true
 }
   func application(_ application: UIApplication, didReceiveRemoteNotification userInfo: [AnyHashable: Any]) {
        // If you are receiving a notification message while your app is in the background,
        // this callback will not be fired till the user taps on the notification launching the application.
        // TODO: Handle data of notification

        // With swizzling disabled you must let Messaging know about the message, for Analytics

         Messaging.messaging().appDidReceiveMessage(userInfo)

        // Print message ID.
        if let messageID = userInfo[gcmMessageIDKey] {
            print("Message ID: \(messageID)")
        }

        // Print full message.
        print(userInfo)
    }

    func application(_ application: UIApplication, didReceiveRemoteNotification userInfo: [AnyHashable: Any],
                     fetchCompletionHandler completionHandler: @escaping (UIBackgroundFetchResult) -> Void) {
        Messaging.messaging().appDidReceiveMessage(userInfo)
        if Auth.auth().canHandleNotification(userInfo) {
            completionHandler(UIBackgroundFetchResult.noData)
            return
        }
        completionHandler(UIBackgroundFetchResult.newData)
    }