Firestore的颤振搜索代表
Firestore的颤振搜索代表
提问于 2019-10-28 08:30:31
我正在使用颤振搜索代理实现搜索特性，数据存储在Firestore中。我不知道为什么会出现这个错误。
Widget buildSuggestions(BuildContext context) {
return StreamBuilder(
stream: Firestore.instance.collection('todos').snapshots(),
builder: (context, snapshot) {
if (!snapshot.hasData) return new Text('Loading...');
final results =
snapshot.data.documents.where((a) => a['title'].contains(query));
return ListView(
children: results.map<Widget>((a) => Text(a['title'])).toList(),
);
},
);
}错误：
type '(dynamic) => dynamic' is not a subtype of type '(DocumentSnapshot) => bool' of 'test'
回答 2
Stack Overflow用户
回答已采纳
发布于 2019-10-28 09:06:13
更换线路
final results = snapshot.data.documents.where((a) => a['title'].contains(query));至
final results = snapshot.data.documents.where((DocumentSnapshot a) => a.data['title'].contains(query));还有这条线
children: results.map<Widget>((a) => Text(a['title'])).toList()至
children: results.map<Widget>((a) => Text(a.data['title'])).toList()Stack Overflow用户
发布于 2021-03-06 06:44:23
更换线路
builder: (context, snapshot) {
....使用
builder: (BuildContext context, AsyncSnapshot<QuerySnapshot> snapshot) {
.....最后代码是：
Widget buildSuggestions(BuildContext context) {
return StreamBuilder(
stream: FirebaseFirestore.instance.collection('todos').snapshots(),
builder: (BuildContext context, AsyncSnapshot<QuerySnapshot> snapshot) {
if (!snapshot.hasData) return new Text('Loading...');
final results =
snapshot.data.docs.where((a) => a['title'].contains(query));
return ListView(
children: results.map<Widget>((a) => Text(a['title'])).toList(),
);
},
);
}页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/58587696
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