我知道这个错误:
3674 The spatial index on column 'position' will not be used by the
query optimizer since the column does not have an SRID attribute.
Consider adding an SRID attribute to the column.
因此,在阅读了本文:https://mysqlserverteam.com/geographic-indexes-in-innodb/之后,我决定将SRID添加到专栏中,我也试着阅读文档,但我仍然不明白这是什么。所以我照课文说的做,然后添加如下:
DROP DATABASE IF EXISTS `gis`;
CREATE DATABASE IF NOT EXISTS `gis`
DEFAULT CHARACTER SET utf8
DEFAULT COLLATE utf8_general_ci;
USE `gis`;
DROP TABLE IF EXISTS user;
CREATE TABLE IF NOT EXISTS user (
id INT UNSIGNED NOT NULL AUTO_INCREMENT PRIMARY KEY,
firstname VARCHAR(48) NOT NULL,
gender ENUM('male', 'female') NOT NULL,
age TINYINT UNSIGNED NOT NULL,
position POINT NOT NULL SRID 4326
);
ALTER TABLE user ADD SPATIAL INDEX(position);
然后我尝试添加一些行:
INSERT INTO user (firstname, gender, age, position) VALUES ('Alexander', 'male', 34, POINT(63.429909, 10.393035));
INSERT INTO user (firstname, gender, age, position) VALUES ('Dina', 'female', 21, POINT(63.426300, 10.392481));
INSERT INTO user (firstname, gender, age, position) VALUES ('Martin', 'male', 32, POINT(63.422304, 10.432027));
INSERT INTO user (firstname, gender, age, position) VALUES ('Tina', 'female', 19, POINT(63.430603, 10.373038));
INSERT INTO user (firstname, gender, age, position) VALUES ('Kristin', 'female', 20, POINT(63.434858, 10.411359));
INSERT INTO user (firstname, gender, age, position) VALUES ('Mette', 'female', 33, POINT(63.420422, 10.403811));
INSERT INTO user (firstname, gender, age, position) VALUES ('Andres', 'male', 34, POINT(63.419488, 10.395722));
INSERT INTO user (firstname, gender, age, position) VALUES ('Sandra', 'female', 25, POINT(63.432053, 10.408738));
INSERT INTO user (firstname, gender, age, position) VALUES ('Kine', 'female', 29, POINT(63.432302, 10.412643));
INSERT INTO user (firstname, gender, age, position) VALUES ('Henrik', 'male', 25, POINT(63.421055, 10.443288));
但我错了:
Error Code: 3643. The SRID of the geometry does not match the SRID of the column 'position'.
The SRID of the geometry is 0, but the SRID of the column is 4326.
Consider changing the SRID of the geometry or the SRID property of the column.
如果我删除SRID,那么当我使用EXPLAIN执行这样的查询时,索引就不能工作了:
SET @distance = 3.5;
SET @my_place_lng = 63.431592;
SET @my_place_lat = 10.396210;
EXPLAIN SELECT
id,
firstname,
gender,
age,
ST_Distance_Sphere(Point(@my_place_lng, @my_place_lat), position) AS distance_from_me
FROM user
WHERE
ST_Contains(ST_MakeEnvelope(
Point((@my_place_lng+(@distance/111)), (@my_place_lat+(@distance/111))),
Point((@my_place_lng-(@distance/111)), (@my_place_lat-(@distance/111)))
), position)
ORDER BY distance_from_me ASC;
我能做什么?我甚至不知道在哪里读更多,没有看到任何我理解的例子。
发布于 2020-04-01 16:00:31
使用ST_SRID
函数指定几何图形的SRID值,即
包装点定义
... , 34, POINT(63.429909, 10.393035 ));
就像这样:
... , 34, ST_SRID( POINT(63.429909, 10.393035) ,4326) );
^^^^^^^^ ^^^^^^
注意,几何图形的SRID值也需要在示例查询中设置。
MySQL参考手册指出,在SRID0中创建几何学,然后将其转换为SRID4326,更好的选择是直接在SRID4326中创建几何学。
... , 34, ST_PointFromText('POINT(63.429909, 10.393035)',4326) ));
^^^^^^^^^^^^^^^^^^ ^^^^^^^
如果我们不想这样做,那么另一个(不太理想的)选择是将列的SRID值设置为默认值0,而不是4326。当我们不设置SRID值时,MySQL使用默认值0。但这样我们就可以在无单位平面坐标系下工作了。如果我们希望将点几何处理为GPS、地球度、纬度/经度坐标,那就不好了。
参考资料:
https://dev.mysql.com/doc/refman/8.0/en/gis-general-property-functions.html#function_st-srid
https://stackoverflow.com/questions/60974497
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