blocks|key|317502|text|我假设您的代码(mwe)如下所示：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|317503|const+myAsyncFunction+=+async(function*+(promise)+{
++const+data+=+yield+promise;
++console.log(data);
});

myAsyncFunction(Promise.resolve("Hello+world"));+//+console:+‘Hello+world!’`

function+async(cb)+{
++return+cb().next();
}|code-block|syntax|javascript|317504|当您运行它时，您确实得到了错误TypeError:+myAsyncFunction+is+not+a+function。但是，当您调整以使用文章中复制的函数时：|offset|length|style|CODE|317505|const+myAsyncFunction+=+async(function*+(promise)+{
++const+data+=+yield+promise;
++console.log(data);
});

myAsyncFunction(Promise.resolve("Hello+world"));+//+console:+‘Hello+world!’`

function+async(cb)+{
+return+function+()+{
++let+generator+=+cb.apply(this,+arguments);

++function+handle(result)+{
+++if+(result.done)+return+Promise.resolve(result.value);

+++return+Promise.resolve(result.value).then(
++++function+(res)+{
++++++return+handle(generator.next(res));
++++},
++++function+(err)+{
++++++return+handle(generator.throw(err));
++++}
+++);
++}
+};
}|317506|你不会明白错误的。这是因为本文中的代码返回异步定义中的一个函数，因此您可以在行中给出的args中应用它。|317507|myAsyncFunction(Promise.resolve("Hello+world"));+//+console:+‘Hello+world!’`|317508|在最初的定义中，async定义不返回函数，因此上述调用失败。|317509|根据您的下一篇文章，并试图了解您想要的内容，下面的内容将使用生成器函数中的控制台行打印字符串，但仍然不太确定您要实现的是什么：|317510|function+async(gen)+{
++++return+function+(cb)+{
++++++++g+=+gen.apply(this,+[cb])
++++++++g.next()
++++++++cb.then(res+=>+{
++++++++++++g.next(res);
++++++++});
++++}
}|317511|entityMap^0|0|0|F|18|0|0|0|0|8|5|0|0|0^^$0|@$1|2|3|4|5|6|7|10|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|11|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|12|8|@$I|13|J|14|K|L]]|9|@]|A|$]]|$1|M|3|N|5|D|7|15|8|@]|9|@]|A|$E|F]]|$1|O|3|P|5|6|7|16|8|@]|9|@]|A|$]]|$1|Q|3|R|5|D|7|17|8|@]|9|@]|A|$E|F]]|$1|S|3|T|5|6|7|18|8|@$I|19|J|1A|K|L]]|9|@]|A|$]]|$1|U|3|V|5|6|7|1B|8|@]|9|@]|A|$]]|$1|W|3|X|5|D|7|1C|8|@]|9|@]|A|$E|F]]|$1|Y|3|-4|5|6|7|1D|8|@]|9|@]|A|$]]]|Z|$]]

I'm assuming your code (mwe) looks like this:
<pre class="lang-js prettyprint-override"><code>const myAsyncFunction = async(function* (promise) {
 const data = yield promise;
 console.log(data);
});

myAsyncFunction(Promise.resolve(&quot;Hello world&quot;)); // console: ‘Hello world!’`

function async(cb) {
 return cb().next();
}


</code></pre>
And when you run it, you do indeed get the error <code>TypeError: myAsyncFunction is not a function</code>. However, when you adjust to use the copied function from the article:
<pre class="lang-js prettyprint-override"><code>const myAsyncFunction = async(function* (promise) {
 const data = yield promise;
 console.log(data);
});

myAsyncFunction(Promise.resolve(&quot;Hello world&quot;)); // console: ‘Hello world!’`

function async(cb) {
 return function () {
 let generator = cb.apply(this, arguments);

 function handle(result) {
 if (result.done) return Promise.resolve(result.value);

 return Promise.resolve(result.value).then(
 function (res) {
 return handle(generator.next(res));
 },
 function (err) {
 return handle(generator.throw(err));
 }
 );
 }
 };
}

</code></pre>
You don't get the error. This is because the code from the article returns a function in the async definition, and thus you are able to apply it with the args given in the line
<pre class="lang-js prettyprint-override"><code>myAsyncFunction(Promise.resolve(&quot;Hello world&quot;)); // console: ‘Hello world!’`
</code></pre>
In your original defintion, the <code>async</code> definition does not return a function so the invocation above fails.
Following on from your next post, and trying to understand what you want, the following will print the string using the console line in the generator function, but still not quite sure what it is you are trying to achieve:
<pre class="lang-js prettyprint-override"><code>function async(gen) {
 return function (cb) {
 g = gen.apply(this, [cb])
 g.next()
 cb.then(res =&gt; {
 g.next(res);
 });
 }
}

</code></pre>

blocks|key|1104624|text|解决办法是|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1104625|function+async(cb)+{
++return+async+function+()+{
++++const+generator+=+cb.apply(this,+arguments);
++++const+nextResult+=+generator.next();
++++const+value+=+await+nextResult.value;
++++generator.next(value);
++};
}

const+myAsyncFunction+=+async(function*+(promise)+{
++const+data+=+yield+promise;
++console.log(data);
});

myAsyncFunction(Promise.resolve("Hello+World"));|code-block|syntax|javascript|1104626|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

solution is
<pre><code>function async(cb) {
 return async function () {
 const generator = cb.apply(this, arguments);
 const nextResult = generator.next();
 const value = await nextResult.value;
 generator.next(value);
 };
}

const myAsyncFunction = async(function* (promise) {
 const data = yield promise;
 console.log(data);
});

myAsyncFunction(Promise.resolve(&quot;Hello World&quot;));
</code></pre>

I have to write async function for:
<pre><code>const myAsyncFunction = async(function* (promise) {
 const data = yield promise;
 console.log(data);
});

myAsyncFunction(Promise.resolve(&quot;Hello world&quot;)); // console: ‘Hello world!’`
</code></pre>
result should be - console: ‘Hello world!’
I thought it would be a right implementation:
<pre><code>function async(cb) {
 return cb().next();
}

const myAsyncFunction = async(function* (promise) {
 const data = yield promise;
 console.log(data);
});

myAsyncFunction(Promise.resolve(&quot;Hello world&quot;)); // console: ‘Hello world!’`
</code></pre>
but I nave a type error:
TypeError: myAsyncFunction is not a function
I found some example <a href="https://www.promisejs.org/generators/" rel="nofollow noreferrer">generator forwards with the results of any promises it has yielded</a>
but I cannt understand how it works and where is my mistake:
<pre><code>function async(cb) {
 return function () {
 let generator = cb.apply(this, arguments);

 function handle(result) {
 if (result.done) return Promise.resolve(result.value);

 return Promise.resolve(result.value).then(
 function (res) {
 return handle(generator.next(res));
 },
 function (err) {
 return handle(generator.throw(err));
 }
 );
 }
 };
}
</code></pre>
please, explain what Im doing wrongly?

Function generator with Promise

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我必须编写异步函数，以便：const myAsyncFunction = async(function* (promise) {  const data = yield promise;  console.log(data);});myAsyncFunction(Promise.resolve("Hello world...

问有承诺的函数发生器
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