如何在Javascript中的字符串中添加逗号
如何在Javascript中的字符串中添加逗号
提问于 2020-10-22 21:27:07
我试图在括号中的名字和姓氏之间添加逗号。
//Input:
s = "Fred:Corwill;Wilfred:Corwill;Barney:Tornbull;Betty:Tornbull;Bjon:Tornbull;Raphael:Corwill;Alfred:Corwill";
//Expected output: "(CORWILL, ALFRED)(CORWILL, FRED)(CORWILL, RAPHAEL)(CORWILL, WILFRED)(TORNBULL, BARNEY)(TORNBULL, BETTY)(TORNBULL, BJON)"我的代码是当前输出：
(CORWILL ALFRED) (CORWILL FRED) (CORWILL RAPHAEL) (CORWILL WILFRED) (TORNBULL BARNEY) (TORNBULL BETTY) (TORNBULL BJON)我尝试过许多方法，比如在重新分配s(字符串)时，首先更改字符的替换方式，这样我一开始就不会删除逗号，然后必须替换them...but，当我这样做时，我的正则表达式就不再起作用了，我不知道为什么会这样。所以我试着找另一个正则表达式，这样我就可以解决这个问题，但这同样是一个痛苦，所以我决定坚持用这样的方法来解决:试图找到一种方法，在括号中的第一个和姓氏之间找到逗号。
完整问题和代码：
/*Could you make a program that
• makes this string uppercase
• gives it sorted in alphabetical order by last name.
When the last names are the same, sort them by first name. Last name and first name of a guest come in the result between parentheses separated by a comma.
*/
function meeting(s) {
s = s.replace(/:/g, ", ").toUpperCase();
//order alphabetically based on Last, then first name
const semicolon = ';'
let testArr = s.split(semicolon)
testArr.sort(function compare(a, b) {
var splitA = a.split(",");
var splitB = b.split(",");
var firstA = splitA[0]
var firstB = splitB[0]
var lastA = splitA[splitA.length - 1];
var lastB = splitB[splitB.length - 1];
if (lastA < lastB) return -1;
if (lastA > lastB) return 1;
if (firstA < firstB) return -1; //sort first names alphabetically
if (firstA > firstB) return 1;
return 0; //if they are equal
})
//print last names before first names with regex
let newArr = [];
for (let i = 0; i < testArr.length; i++) {
let variable = (testArr[i].replace(/([\w ]+), ([\w ]+)/g, "$2 $1"))
let comma = ","
newArr.push(`(${variable})`)
}
let finalStr;
finalStr = newArr.toString().replace(/[ ,.]/g, " ").toUpperCase();
// finalStr = finalStr.replace(/" "/g, ", ")
return finalStr
}
s = "Fred:Corwill;Wilfred:Corwill;Barney:Tornbull;Betty:Tornbull;Bjon:Tornbull;Raphael:Corwill;Alfred:Corwill";
console.log(meeting(s))
// expected result: "(CORWILL, ALFRED)(CORWILL, FRED)(CORWILL, RAPHAEL)(CORWILL, WILFRED)(TORNBULL, BARNEY)(TORNBULL, BETTY)(TORNBULL, BJON)"任何帮助都将不胜感激，我在这个problem.The正则表达式上花费了大约5个小时，我使用的是用名字的位置切换姓氏的位置( Fred ) --> ( Corwill )。如果有一个regex给我，而不是你建议的那个，也许我也可以用这种方式解决这个问题，到目前为止，我尝试过的其他方法都没有奏效。
回答 3
Stack Overflow用户
回答已采纳
发布于 2020-10-22 21:33:02
这看起来比需要的复杂得多。在被;s拆分后，将每个单独的元素按相反顺序映射到其单词，然后连接：
const s = "Fred:Corwill;Wilfred:Corwill;Barney:Tornbull;Betty:Tornbull;Bjon:Tornbull;Raphael:Corwill;Alfred:Corwill";
const output = s
.toUpperCase()
.split(';')
.sort((a, b) => {
const [aFirst, aLast] = a.split(':');
const [bFirst, bLast] = b.split(':');
return aLast.localeCompare(bLast) || aFirst.localeCompare(bFirst);
})
.map((name) => {
const [first, last] = name.split(':');
return `(${last}, ${first})`;
})
.join('');
console.log(output);
Stack Overflow用户
发布于 2020-10-22 21:30:58
与映射和排序一起使用拆分
var s = "Fred:Corwill;Wilfred:Corwill;Barney:Tornbull;Betty:Tornbull;Bjon:Tornbull;Raphael:Corwill;Alfred:Corwill";
var res = s.split(/;/) // split into people
.map(x => x.split(/:/).reverse()) // split names, put last first
.sort((a, b) => a[0] === b[0] ? a[1].localeCompare(b[1]) : a[0].localeCompare(b[0])) // sort by last name, first name
.map(x => `(${x.join(', ')})`) // create the new format
.join(' ') // join the array back into a string
console.log(res);
Stack Overflow用户
发布于 2020-10-22 22:28:08
这就是你需要的：
const str = 'Fred:Corwill;Wilfred:Corwill;Barney:Tornbull;Betty:Tornbull;Bjon:Tornbull;Raphael:Corwill;Alfred:Corwill';
function formatString(string) {
const modifiedString = string.toUpperCase().replace(/(\w+):(\w+)/g, '($2, $1)');
const sortedString = modifiedString.split(';').sort().join('');
return sortedString;
}
console.log(formatString(str))
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/64490780
复制相关文章
相似问题
腾讯云开发者
Copyright © 2013 - 2026 Tencent Cloud. All Rights Reserved. 腾讯云 版权所有
深圳市腾讯计算机系统有限公司 ICP备案/许可证号：粤B2-20090059 
粤公网安备44030502008569号
腾讯云计算（北京）有限责任公司 京ICP证150476号 | 京ICP备11018762号