代码的第18行( SyntaxError )\x{e76f}\x{e76f}\x{e76f}
代码的第18行( SyntaxError )\x{e76f}\x{e76f}\x{e76f}
提问于 2021-04-08 06:50:43
我正在创建预付费票系统，但是我在第18行有问题，它给了我一个语法错误。请在你的IDE里试一试，帮我
@bot.event
async def on_raw_reaction_add(payload):
if payload.member.id != bot.user.id and payload.emoji== u"\U0001F3AB":
msg_id, channel_id, category_id= bot.ticket_configs[payload.guild_id]
if payload.message_id == msg_id:
guild= bot.get_guild(payload.guild_id)
for category in guild.categories:
if category.id == category_id:
break
channel = guild.get_channel(channel_id)
ticket_num= 1 if len(category.channels) == 0 else int(category.channels.split("-")[-1]) + 1
ticket_channel= await category.create_text_channel(f"Ticket {ticket_num}", topic= f"Channel for ticket number {ticket_num}.", permission_synced= True)
await ticket_channel.set_permissions(payload.member, read_messages= True, send_messages= True)
message= await channel.fetch_message(msg_id)
await message.remove_reaction(payload.emoji, payload.member)
await ticket_channel.send(f"{payload.member.mention} Thank You! for creating this ticket staff will contact you soon. Type **-close** to close the ticket.")
try:
await bot.wait_for("message", check=lamda m: m.channel== ticket_channel and m.author== payload.member and m.content == "-close", timeout= 3600)
except asyncio.TimeoutError:
await ticket_channel.delete()
else:
await ticket_channel.deleted()回答 1
Stack Overflow用户
回答已采纳
发布于 2021-04-08 07:04:40
你的线路上有个错误
await bot.wait_for("message", check=lamda m: m.channel== ticket_channel and m.author== payload.member and m.content == "-close", timeout= 3600)它应该是lambda，即：
await bot.wait_for(
"message",
check=lambda m: m.channel == ticket_channel and m.author == payload.member and m.content == "-close",
timeout=3600,
)页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/66998675
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