在下面的例子中,我试图在我的数据库中创建一个生物,每个生物都有许多属性,所以我创建了一个具有许多不同的字符串和CreatureAttribute字段的Int。如何将该类型附加到生物类型变异?
mutation{
createCreature(data: {
creature_name: "Drake"
creature_type: "Dragon"
creature_size: "Huge"
description: "description Text..."
habitat: "habitat text..."
combat: "combat text..."
additional_info: "additional info text..."
attributes: ********this is where I would like to bring in my CreatureAttributes Type********
)
{
creature_name
creature_type
description
habitat
combat
additional_info
attributes
}
}
提前感谢您的回答:)
发布于 2019-02-11 22:26:41
根据我的理解,你想创建一个“生物有可能的属性”的关系。所以属性应该接受数组,如下面的示例所示。
type Creature {
id: ID! @unique
creature_name: String!
creature_type: String!
creature_size: String!
description: String!
habitat: String!
combat: String!
additional_info: String!
attributes: [CreatureAttributes]!
}
type CreatureAttributes {
strength: Int!
health: Int!
stamina: Int!
mana: Int!
reaction: Int!
...}
Ref - https://graphql.org/learn/schema/#object-types-and-fields
https://stackoverflow.com/questions/54600611
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