blocks|key|724657|text|添加第一个uri的斜杠结束，URI将忽略多个斜杠(/)|type|unstyled|depth|inlineStyleRanges|entityRanges|data|724658|var+a+=+new+Uri("file:///C:/Some/Dirs/");|code-block|syntax|javascript|724659|编辑：|offset|length|style|BOLD|724660|var+a+=+new+Uri("file:///C:/Some/Dirs");
var+b+=+new+Uri("some.file",++UriKind.Relative);
var+c+=+new+Uri(Path.Combine(a.ToString(),+b.ToString()));
MessageBox.Show(c.AbsoluteUri);|724661|entityMap^0|0|0|0|3|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|S|8|@$I|T|J|U|K|L]]|9|@]|A|$]]|$1|M|3|N|5|D|7|V|8|@]|9|@]|A|$E|F]]|$1|O|3|-4|5|6|7|W|8|@]|9|@]|A|$]]]|P|$]]

add a slash end of your first uri, URI will ignore more than one slash (/)

<pre><code>var a = new Uri("file:///C:/Some/Dirs/");
</code></pre>

EDIT:

<pre><code>var a = new Uri("file:///C:/Some/Dirs");
var b = new Uri("some.file", UriKind.Relative);
var c = new Uri(Path.Combine(a.ToString(), b.ToString()));
MessageBox.Show(c.AbsoluteUri);
</code></pre>

blocks|key|894492|text|为什么不直接从Uri继承并使用它呢？在构造函数中，您需要做些什么来修复它？重构是很便宜的，假设这是装配内部的或者可以实现的。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|894493|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|D|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|E|8|@]|9|@]|A|$]]]|C|$]]

Why not just inherit from Uri and use that, ie. do in constructor what you need to do to fix it up? Refactoring is cheap assuming this is internal to assembly or within reach..

blocks|key|724688|text|您可以尝试这个扩展方法！总是工作！-)|type|unstyled|depth|inlineStyleRanges|entityRanges|data|724689|+public+static+class+StringExtension
++++{
++++++++public+static+string+UriCombine(this+string+str,+string+param)
++++++++{
++++++++++++if+(!str.EndsWith("/"))
++++++++++++{
++++++++++++++++str+=+str+%2B+"/";
++++++++++++}
++++++++++++var+uri+=+new+Uri(str);
++++++++++++return+new+Uri(uri,+param).AbsoluteUri;
++++++++}
++++}|code-block|syntax|javascript|724690|安杰洛·阿莱桑德罗|724691|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

You can try this extension method! Works always! ;-)

<pre><code> public static class StringExtension
 {
 public static string UriCombine(this string str, string param)
 {
 if (!str.EndsWith("/"))
 {
 str = str + "/";
 }
 var uri = new Uri(str);
 return new Uri(uri, param).AbsoluteUri;
 }
 }
</code></pre>

Angelo, Alessandro

blocks|key|894518|text|这应该对你有好处：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|894519|var+baseUri+=+new+Uri("http://www.briankeating.net");
var+absoluteUri+=+new+Uri(baseUri,+"/api/GetDefinitions");|code-block|syntax|javascript|894520|这个构造函数遵循标准的相对URI规则，因此/很重要：|offset|length|style|CODE|894521|http://example.net+%2B+foo+=+http://example.net/foo|unordered-list-item|894522|http://example.net/foo/bar+%2B+baz+=+http://example.net/foo/baz|894523|http://example.net/foo/+%2B+bar+=+http://example.net/foo/bar|894524|http://example.net/foo+%2B+bar+=+http://example.net/bar|894525|http://example.net/foo/bar/+%2B+/baz+=+http://example.net/baz|894526|entityMap|0|LINK|mutability|MUTABLE|url|https://msdn.microsoft.com/en-us/library/vstudio/9hst1w91(v=vs.100).aspx^0|0|0|L|1|2|4|0|0|0|I|L|3|R|M|0|0|Q|T|3|Z|Q|0|0|N|Q|3|W|Q|0|0|M|P|3|V|M|0|0|R|U|4|11|M|0^^$0|@$1|2|3|4|5|6|7|15|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|16|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|17|8|@$I|18|J|19|K|L]]|9|@$I|1A|J|1B|1|1C]]|A|$]]|$1|M|3|N|5|O|7|1D|8|@$I|1E|J|1F|K|L]|$I|1G|J|1H|K|L]|$I|1I|J|1J|K|L]]|9|@]|A|$]]|$1|P|3|Q|5|O|7|1K|8|@$I|1L|J|1M|K|L]|$I|1N|J|1O|K|L]|$I|1P|J|1Q|K|L]]|9|@]|A|$]]|$1|R|3|S|5|O|7|1R|8|@$I|1S|J|1T|K|L]|$I|1U|J|1V|K|L]|$I|1W|J|1X|K|L]]|9|@]|A|$]]|$1|T|3|U|5|O|7|1Y|8|@$I|1Z|J|20|K|L]|$I|21|J|22|K|L]|$I|23|J|24|K|L]]|9|@]|A|$]]|$1|V|3|W|5|O|7|25|8|@$I|26|J|27|K|L]|$I|28|J|29|K|L]|$I|2A|J|2B|K|L]]|9|@]|A|$]]|$1|X|3|-4|5|6|7|2C|8|@]|9|@]|A|$]]]|Y|$Z|$5|10|11|12|A|$13|14]]]]

This should do the trick for you:

<pre><code>var baseUri = new Uri("http://www.briankeating.net");
var absoluteUri = new Uri(baseUri, "/api/GetDefinitions");
</code></pre>

This <a href="https://msdn.microsoft.com/en-us/library/vstudio/9hst1w91(v=vs.100).aspx" rel="noreferrer">constructor</a> follow the standard relative URI rules so the <code>/</code> are important :

<ul>
<li><code>http://example.net</code> + <code>foo</code> = <code>http://example.net/foo</code></li>
<li><code>http://example.net/foo/bar</code> + <code>baz</code> = <code>http://example.net/foo/baz</code></li>
<li><code>http://example.net/foo/</code> + <code>bar</code> = <code>http://example.net/foo/bar</code></li>
<li><code>http://example.net/foo</code> + <code>bar</code> = <code>http://example.net/bar</code></li>
<li><code>http://example.net/foo/bar/</code> + <code>/baz</code> = <code>http://example.net/baz</code></li>
</ul>

I have two Uri objects passed into some code, one is a directory and the other is a filename (or a relative path)

<pre><code>var a = new Uri("file:///C:/Some/Dirs");
var b = new Uri("some.file");
</code></pre>

when I try and combine them like this:

<pre><code>var c = new Uri(a,b);
</code></pre>

I get 

<blockquote>
 <code>file:///C:/Some/some.file</code>
</blockquote>

where I wold expect to get the same effect as with <code>Path.Combine</code> (as that is the old code I need to replace):

<blockquote>
 <code>file:///C:/Some/Dirs/some.file</code>
</blockquote>

I can't think of a clean solution to this.

The ugly solution being to add a <code>/</code> to the Uri if it's not there

<pre><code>string s = a.OriginalString;
if(s[s.Length-1] != '/')
 a = new Uri(s + "/");
</code></pre>

How to combine URIs

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我有两个Uri对象传递到一些代码中，一个是目录，另一个是文件名(或相对路径)。var a = new Uri("file:///C:/Some/Dirs");var b = new Uri("some.file");当我试着像这样组合它们时：var c = new Uri(a,b);我得到了file:///C:/Som...

问如何结合URI
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