Zend框架:如何从twitter获取我的状态
Zend框架:如何从twitter获取我的状态
提问于 2009-12-30 12:23:58
我想在我的网站上展示我在twitter上的最后5或10个状态。现在，我正在使用下面的代码来获取我的twitter状态。
public function getOrganizationsTwitterUpdates(){
$twitter = new Zend_Service_Twitter('myusername', 'mypassword');
$response = $twitter->status->userTimeline();
return $response;
}我必须跟踪以上代码的响应。
Zend_Rest_Client_Result Object ( [_sxml:protected] => SimpleXMLElement Object ( [@attributes] => Array ( [type] => array ) [status] => Array ( [0] => SimpleXMLElement Object ( [created_at] => Wed Dec 30 11:02:13 +0000 2009 [id] => 7192975030 [text] => This is my 2nd tweet. [source] => web [truncated] => false [in_reply_to_status_id] => SimpleXMLElement Object ( ) [in_reply_to_user_id] => SimpleXMLElement Object ( ) [favorited] => false [in_reply_to_screen_name] => SimpleXMLElement Object ( ) [user] => SimpleXMLElement Object ( [id] => 100469557 [name] => naveed [screen_name] => naveedriksof [location] => SimpleXMLElement Object ( ) [description] => SimpleXMLElement Object ( ) [profile_image_url] => http://s.twimg.com/a/1262113883/images/default_profile_6_normal.png [url] => SimpleXMLElement Object ( ) [protected] => false [followers_count] => 0 [profile_background_color] => 9ae4e8 [profile_text_color] => 000000 [profile_link_color] => 0000ff [profile_sidebar_fill_color] => e0ff92 [profile_sidebar_border_color] => 87bc44 [friends_count] => 0 [created_at] => Wed Dec 30 10:59:31 +0000 2009 [favourites_count] => 0 [utc_offset] => SimpleXMLElement Object ( ) [time_zone] => SimpleXMLElement Object ( ) [profile_background_image_url] => http://s.twimg.com/a/1262113883/images/themes/theme1/bg.png [profile_background_tile] => false [notifications] => false [geo_enabled] => false [verified] => false [following] => false [statuses_count] => 2 ) [geo] => SimpleXMLElement Object ( ) ) [1] => SimpleXMLElement Object ( [created_at] => Wed Dec 30 11:01:43 +0000 2009 [id] => 7192966364 [text] => This is my 1st tweet [source] => web [truncated] => false [in_reply_to_status_id] => SimpleXMLElement Object ( ) [in_reply_to_user_id] => SimpleXMLElement Object ( ) [favorited] => false [in_reply_to_screen_name] => SimpleXMLElement Object ( ) [user] => SimpleXMLElement Object ( [id] => 100469557 [name] => naveed [screen_name] => naveedriksof [location] => SimpleXMLElement Object ( ) [description] => SimpleXMLElement Object ( ) [profile_image_url] => http://s.twimg.com/a/1262113883/images/default_profile_6_normal.png [url] => SimpleXMLElement Object ( ) [protected] => false [followers_count] => 0 [profile_background_color] => 9ae4e8 [profile_text_color] => 000000 [profile_link_color] => 0000ff [profile_sidebar_fill_color] => e0ff92 [profile_sidebar_border_color] => 87bc44 [friends_count] => 0 [created_at] => Wed Dec 30 10:59:31 +0000 2009 [favourites_count] => 0 [utc_offset] => SimpleXMLElement Object ( ) [time_zone] => SimpleXMLElement Object ( ) [profile_background_image_url] => http://s.twimg.com/a/1262113883/images/themes/theme1/bg.png [profile_background_tile] => false [notifications] => false [geo_enabled] => false [verified] => false [following] => false [statuses_count] => 1 ) [geo] => SimpleXMLElement Object ( ) ) ) ) )我有两个问题：
Q1。如何将上述对象转换为数组。在上面的对象中，我可以看到我的两个状态，但是如何将我的状态存储到这样的变量中。
$firstStatus =“这是我的第一条推特”；$firstStatusTime =“下午4:30 12-12-09"；$secondStatus =”这是我的第二条推特“；$secondStatusTime =”9:30 my 12-12-09"；
Q2。我可以获得我的所有状态没有我的密码(我们可以看到任何人的状态在网上)。我不想使用RSS。
Stack Overflow用户
发布于 2009-12-30 12:45:08
我已经将字符串转换为SimpleXML对象/数组，如
$array=(阵列)simplexml_load_string($stroq)；
我不知道在这种情况下这对你是否有效。这是为了从我从API获得的XML字符串中获取一个数组。说到这一点，是否可以将Twitter提要作为json并在其上使用json_decode？这将比使用XML容易得多。
不管怎样，看起来你的推特的路径是
$firstStatusTime=$response->status[1]->created_at
$firstStatus=$response->status[1]->text但是，如果没有物体本身或更清晰的打印，就很难说了。
对Q2来说，是的，你可以在没有密码的情况下从推特上获取任何人的消息(如果没有保护的话)。
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原文链接：
https://stackoverflow.com/questions/1979933
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