blocks|key|1253897|text|域存储在$_SERVER['HTTP_HOST']中。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1253898|编辑:我相信这将返回整个域。要获得顶级域，您可以这样做：|1253899|//+Add+all+your+wanted+subdomains+that+act+as+top-level+domains,+here+(e.g.+'co.cc'+or+'co.uk')
//+As+array+key,+use+the+last+part+('cc'+and+'uk'+in+the+above+examples)+and+the+first+part+as+sub-array+elements+for+that+key
$allowed_subdomains+=+array(
++++'cc'++++=>+array(
++++++++'co'
++++),
++++'uk'++++=>+array(
++++++++'co'
++++)
);

$domain+=+$_SERVER['HTTP_HOST'];
$parts+=+explode('.',+$domain);
$top_level+=+array_pop($parts);

//+Take+care+of+allowed+subdomains
if+(isset($allowed_subdomains[$top_level]))
{
++++if+(in_array(end($parts),+$allowed_subdomains[$top_level]))
++++++++$top_level+=+array_pop($parts).'.'.$top_level;
}

$top_level+=+array_pop($parts).'.'.$top_level;|code-block|syntax|javascript|1253900|entityMap^0|4|L|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@$9|P|A|Q|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|R|8|@]|D|@]|E|$]]|$1|H|3|I|5|J|7|S|8|@]|D|@]|E|$K|L]]|$1|M|3|-4|5|6|7|T|8|@]|D|@]|E|$]]]|N|$]]

The domain is stored in <code>$_SERVER['HTTP_HOST']</code>.

EDIT: I believe this returns the whole domain. To just get the top-level domain, you could do this:

<pre><code>// Add all your wanted subdomains that act as top-level domains, here (e.g. 'co.cc' or 'co.uk')
// As array key, use the last part ('cc' and 'uk' in the above examples) and the first part as sub-array elements for that key
$allowed_subdomains = array(
 'cc' =&gt; array(
 'co'
 ),
 'uk' =&gt; array(
 'co'
 )
);

$domain = $_SERVER['HTTP_HOST'];
$parts = explode('.', $domain);
$top_level = array_pop($parts);

// Take care of allowed subdomains
if (isset($allowed_subdomains[$top_level]))
{
 if (in_array(end($parts), $allowed_subdomains[$top_level]))
 $top_level = array_pop($parts).'.'.$top_level;
}

$top_level = array_pop($parts).'.'.$top_level;
</code></pre>

blocks|key|1255185|text|我想你需要一个域名后面所有后缀的列表。http://publicsuffix.org/list/提供了目前使用的所有后缀的最新(或他们声称的)。这个列表实际上是这里，现在的想法是将该列表解析为一个结构，其中不同的级别被点分割，从结束级别开始：|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|1255186|例如，对于域:+com.la+com.tr+com.lc|1255187|你最终会：|1255188|[la]=>[com]
[lc]=>[com]|code-block|syntax|javascript|1255189|等等。|1255190|然后您将从base_url+(通过使用parse_url)获得主机，然后用圆点将其炸开。然后开始将值与结构匹配起来，从最后一个开始：|1255191|所以对于google.com.tr，你首先要匹配的是tr，然后是com，然后一旦你到达谷歌，你就找不到匹配的了，这就是你想要的.|1255192|entityMap|0|LINK|mutability|MUTABLE|url|http://publicsuffix.org/list/|1|http://mxr.mozilla.org/mozilla-central/source/netwerk/dns/src/effective_tld_names.dat?raw=1^0|J|T|0|28|2|1|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|12|8|@]|9|@$A|13|B|14|1|15]|$A|16|B|17|1|18]]|C|$]]|$1|D|3|E|5|6|7|19|8|@]|9|@]|C|$]]|$1|F|3|G|5|6|7|1A|8|@]|9|@]|C|$]]|$1|H|3|I|5|J|7|1B|8|@]|9|@]|C|$K|L]]|$1|M|3|N|5|6|7|1C|8|@]|9|@]|C|$]]|$1|O|3|P|5|6|7|1D|8|@]|9|@]|C|$]]|$1|Q|3|R|5|6|7|1E|8|@]|9|@]|C|$]]|$1|S|3|-4|5|6|7|1F|8|@]|9|@]|C|$]]]|T|$U|$5|V|W|X|C|$Y|Z]]|10|$5|V|W|X|C|$Y|11]]]]

I reckon you'll need a list of all suffixes used after a domain name.
<a href="http://publicsuffix.org/list/" rel="nofollow noreferrer">http://publicsuffix.org/list/</a> provides an up-to-date (or so they claim) of all suffixes in use currently.
The list is actually <a href="http://mxr.mozilla.org/mozilla-central/source/netwerk/dns/src/effective_tld_names.dat?raw=1" rel="nofollow noreferrer">here</a> 
Now the idea would be for you to parse up that list into a structure, with different levels split by the dot, starting by the end levels:

so for instance for the domains:
com.la
com.tr
com.lc

you'd end up with:

<pre><code>[la]=&gt;[com]
[lc]=&gt;[com]
</code></pre>

etc...

Then you'd get the host from base_url (by using parse_url), and you'd explode it by dots. and you start matching up the values against your structure, starting with the last one:

so for google.com.tr you'd start by matching tr, then com, then you won't find a match once you get to google, which is what you want...

blocks|key|1253938|text|Regex和parse_url()不是您的解决方案。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1253939|您需要使用公共后缀列表的包，只有这样，您才能正确地提取具有两级、三级TLDs+(co.uk、a.bg、b.bg等)的域。我推荐使用TLD提取液。|offset|length|1253940|下面是代码示例：|1253941|$extract+=+new+LayerShifter\TLDExtract\Extract();

$result+=+$extract->parse('http://subsub.sub.google.com.tr');
$result->getRegistrableDomain();+//+will+return+(string)+'google.com.tr'|code-block|syntax|javascript|1253942|entityMap|0|LINK|mutability|MUTABLE|url|https://publicsuffix.org/|1|https://github.com/layershifter/TLDExtract^0|0|5|6|0|1T|6|1|0|0|0^^$0|@$1|2|3|4|5|6|7|W|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|X|8|@]|9|@$D|Y|E|Z|1|10]|$D|11|E|12|1|13]]|A|$]]|$1|F|3|G|5|6|7|14|8|@]|9|@]|A|$]]|$1|H|3|I|5|J|7|15|8|@]|9|@]|A|$K|L]]|$1|M|3|-4|5|6|7|16|8|@]|9|@]|A|$]]]|N|$O|$5|P|Q|R|A|$S|T]]|U|$5|P|Q|R|A|$S|V]]]]

Regex and parse_url() aren't solution for you.

You need package that uses <a href="https://publicsuffix.org/" rel="nofollow">Public Suffix List</a>, only in this way you can correctly extract domains with two-, third-level TLDs (co.uk, a.bg, b.bg, etc.). I recomend use <a href="https://github.com/layershifter/TLDExtract" rel="nofollow">TLD Extract</a>.

Here example of code:

<pre><code>$extract = new LayerShifter\TLDExtract\Extract();

$result = $extract-&gt;parse('http://subsub.sub.google.com.tr');
$result-&gt;getRegistrableDomain(); // will return (string) 'google.com.tr'
</code></pre>

How I can parse a domain from URL in PHP? It seems that I need a country domain database.

Examples:

<blockquote>
 <a href="http://mail.google.com/hfjdhfjd/jhfjd.html" rel="nofollow noreferrer">http://mail.google.com/hfjdhfjd/jhfjd.html</a> -> google.com 
 <a href="http://www.google.bg/jhdjhf/djfhj.html" rel="nofollow noreferrer">http://www.google.bg/jhdjhf/djfhj.html</a> -> google.bg 
 <a href="http://www.google.co.uk/djhdjhf.php" rel="nofollow noreferrer">http://www.google.co.uk/djhdjhf.php</a> -> google.co.uk 
 <a href="http://www.tsk.tr/jhjgc.aspx" rel="nofollow noreferrer">http://www.tsk.tr/jhjgc.aspx</a> -> tsk.tr <a href="http://subsub.sub.nic.tr/" rel="nofollow noreferrer">http://subsub.sub.nic.tr/</a>
 -> nic.tr <a href="http://subsub.sub.google.com.tr" rel="nofollow noreferrer">http://subsub.sub.google.com.tr</a> -> google.com.tr <a href="http://subsub.sub.itoy.info.tr" rel="nofollow noreferrer">http://subsub.sub.itoy.info.tr</a> -> itoy.info.tr
</blockquote>

Can it be done with whois request?

Edit: There are few domain names with <code>.tr</code> (<code>www.nic.tr</code>, <code>www.tsk.tr</code>) the others are as you know: <code>www.something.com.tr</code>, <code>www.something.org.tr</code>

Also there is no <code>www.something.com.bg</code>, <code>www.something.org.bg</code>. They are <code>www.something.bg</code> like the Germans' <code>.de</code>

But there are <code>www.something.a.bg</code>, <code>www.something.b.bg</code> thus <code>a.bg</code>, <code>b.bg</code>, <code>c.bg</code> and so on. (<code>a.bg</code> is like <code>co.uk</code>)

There on the net must be list of these top domain names.

Check how is coloured the url <code>http://www.agrotehnika97.a.bg/</code> in Internet Explorer.
Check also 

<pre><code>www.google.co.uk&lt;br&gt;
www.google.com.tr&lt;br&gt;
www.nic.tr&lt;br&gt;
www.tsk.tr
</code></pre>

Parsing Domainname From URL In PHP

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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如何在PHP中从URL解析域？看来我需要一个国家域数据库。示例： -> google.com -> google.bg -> google.co.uk -> tsk.tr -> nic.tr -> google.com.tr -> itoy.info.tr能不能用她的请求来完成？编辑:几乎没有.tr (www.nic....

问从PHP中的URL解析域名
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