blocks|key|335231|text|您可以将控制器或视图(以创建手势识别器为准)设置为UITapGestureRecognizer的委托。然后，在委托中可以实现-gestureRecognizer:shouldReceiveTouch:。在您的实现中，您可以测试触摸是否属于新的子视图，如果属于，则指示手势识别器忽略它。如下所示：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|335232|-+(BOOL)gestureRecognizer:(UIGestureRecognizer+*)gestureRecognizer+shouldReceiveTouch:(UITouch+*)touch+{
++++//+test+if+our+control+subview+is+on-screen
++++if+(self.controlSubview.superview+!=+nil)+{
++++++++if+([touch.view+isDescendantOfView:self.controlSubview])+{
++++++++++++//+we+touched+our+control+surface
++++++++++++return+NO;+//+ignore+the+touch
++++++++}
++++}
++++return+YES;+//+handle+the+touch
}|code-block|syntax|javascript|335233|entityMap^0|P|M|1Q|12|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]|$9|P|A|Q|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|R|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|S|8|@]|D|@]|E|$]]]|L|$]]

You can set your controller or view (whichever creates the gesture recognizer) as the delegate of the <code>UITapGestureRecognizer</code>. Then in the delegate you can implement <code>-gestureRecognizer:shouldReceiveTouch:</code>. In your implementation you can test if the touch belongs to your new subview, and if it does, instruct the gesture recognizer to ignore it. Something like the following:

<pre><code>- (BOOL)gestureRecognizer:(UIGestureRecognizer *)gestureRecognizer shouldReceiveTouch:(UITouch *)touch {
 // test if our control subview is on-screen
 if (self.controlSubview.superview != nil) {
 if ([touch.view isDescendantOfView:self.controlSubview]) {
 // we touched our control surface
 return NO; // ignore the touch
 }
 }
 return YES; // handle the touch
}
</code></pre>

blocks|key|335267|text|作为凯文·巴拉德答案的后续，我遇到了同样的问题，最后使用了以下代码：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|335268|-+(BOOL)gestureRecognizer:(UIGestureRecognizer+*)gestureRecognizer+shouldReceiveTouch:(UITouch+*)touch+{
++++if+([touch.view+isKindOfClass:[UIButton+class]]){
++++++++return+NO;
++++}
++++return+YES;
}|code-block|syntax|javascript|335269|它具有相同的效果，但在任何视图深度上都可以工作(我的UIButton有几个视图深度，UIGestureRecognizer的委托没有引用它)。|335270|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

As a follow up to Kevin Ballard's answer, I had this same problem and ended up using this code:

<pre><code>- (BOOL)gestureRecognizer:(UIGestureRecognizer *)gestureRecognizer shouldReceiveTouch:(UITouch *)touch {
 if ([touch.view isKindOfClass:[UIButton class]]){
 return NO;
 }
 return YES;
}
</code></pre>

It has the same effect but this will work on any UIButton at any view depth (my UIButton was several views deep and the UIGestureRecognizer's delegate didn't have a reference to it.)

blocks|key|335338|text|从这里中找到了另一种方法。它检测触摸是否在每个按钮内。|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|335339|(1)+内点:withEvent：+(2)+locationInView：|335340|-+(BOOL)gestureRecognizer:(UIGestureRecognizer+*)gestureRecognizer+
+++++++shouldReceiveTouch:(UITouch+*)touch+{
++++//+Don't+recognize+taps+in+the+buttons
++++return+(![self.button1+pointInside:[touch+locationInView:self.button1]+withEvent:nil]+&&
++++++++++++![self.button2+pointInside:[touch+locationInView:self.button2]+withEvent:nil]+&&
++++++++++++![self.button3+pointInside:[touch+locationInView:self.button3]+withEvent:nil]);
}|code-block|syntax|javascript|335341|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/questions/4329028/uitapgesturerecognizer-waiting-for-second-tap-buttons-slow|1|http://developer.apple.com/library/ios/#documentation/uikit/reference/UIView_Class/UIView/UIView.html#//apple_ref/occ/cl/UIView|2|http://developer.apple.com/library/ios/#documentation/uikit/reference/UITouch_Class/Reference/Reference.html#//apple_ref/doc/c_ref/UITouch^0|1|2|0|0|4|D|1|M|F|2|0|0^^$0|@$1|2|3|4|5|6|7|W|8|@]|9|@$A|X|B|Y|1|Z]]|C|$]]|$1|D|3|E|5|6|7|10|8|@]|9|@$A|11|B|12|1|13]|$A|14|B|15|1|16]]|C|$]]|$1|F|3|G|5|H|7|17|8|@]|9|@]|C|$I|J]]|$1|K|3|-4|5|6|7|18|8|@]|9|@]|C|$]]]|L|$M|$5|N|O|P|C|$Q|R]]|S|$5|N|O|P|C|$Q|T]]|U|$5|N|O|P|C|$Q|V]]]]

Found another way to do it from <a href="https://stackoverflow.com/questions/4329028/uitapgesturerecognizer-waiting-for-second-tap-buttons-slow">here</a>. It detects the touch whether inside each button or not. 

(1) <a href="http://developer.apple.com/library/ios/#documentation/uikit/reference/UIView_Class/UIView/UIView.html#//apple_ref/occ/cl/UIView" rel="nofollow noreferrer">pointInside:withEvent:</a>
(2) <a href="http://developer.apple.com/library/ios/#documentation/uikit/reference/UITouch_Class/Reference/Reference.html#//apple_ref/doc/c_ref/UITouch" rel="nofollow noreferrer">locationInView:</a>

<pre><code>- (BOOL)gestureRecognizer:(UIGestureRecognizer *)gestureRecognizer 
 shouldReceiveTouch:(UITouch *)touch {
 // Don't recognize taps in the buttons
 return (![self.button1 pointInside:[touch locationInView:self.button1] withEvent:nil] &amp;&amp;
 ![self.button2 pointInside:[touch locationInView:self.button2] withEvent:nil] &amp;&amp;
 ![self.button3 pointInside:[touch locationInView:self.button3] withEvent:nil]);
}
</code></pre>

blocks|key|335347|text|作为凯西对凯文·巴拉德答案的后续跟进：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|335348|-+(BOOL)gestureRecognizer:(UIGestureRecognizer+*)gestureRecognizer+shouldReceiveTouch:(UITouch+*)touch+{
++++++++if+([touch.view+isKindOfClass:[UIControl+class]])+{
++++++++++++//+we+touched+a+button,+slider,+or+other+UIControl
++++++++++++return+NO;+//+ignore+the+touch
++++++++}
++++return+YES;+//+handle+the+touch
}|code-block|syntax|javascript|335349|这基本上使所有用户输入类型的控件(如按钮、滑块等)都能工作。|335350|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

As a follow up to Casey's follow up to Kevin Ballard's answer:

<pre><code>- (BOOL)gestureRecognizer:(UIGestureRecognizer *)gestureRecognizer shouldReceiveTouch:(UITouch *)touch {
 if ([touch.view isKindOfClass:[UIControl class]]) {
 // we touched a button, slider, or other UIControl
 return NO; // ignore the touch
 }
 return YES; // handle the touch
}
</code></pre>

This basically makes all user input types of controls like buttons, sliders, etc. work

blocks|key|1531795|text|在这里找到了这个答案：链接|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|1531796|您也可以使用|1531797|tapRecognizer.cancelsTouchesInView+=+NO;|code-block|syntax|javascript|1531798|，这将防止抽头识别器成为唯一捕获所有抽头的程序。|1531799|迈克尔提到了指向描述此属性的文档的链接：cancelsTouchesInView|1531800|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/a/3372440/580173|1|https://stackoverflow.com/users/122780/michael-van-der-westhuizen|2|http://developer.apple.com/library/ios/documentation/UIKit/Reference/UIGestureRecognizer_Class/Reference/Reference.html#//apple_ref/occ/instp/UIGestureRecognizer/cancelsTouchesInView^0|B|2|0|0|0|0|0|0|3|1|K|K|2|0^^$0|@$1|2|3|4|5|6|7|10|8|@]|9|@$A|11|B|12|1|13]]|C|$]]|$1|D|3|E|5|6|7|14|8|@]|9|@]|C|$]]|$1|F|3|G|5|H|7|15|8|@]|9|@]|C|$I|J]]|$1|K|3|L|5|6|7|16|8|@]|9|@]|C|$]]|$1|M|3|N|5|6|7|17|8|@]|9|@$A|18|B|19|1|1A]|$A|1B|B|1C|1|1D]]|C|$]]|$1|O|3|-4|5|6|7|1E|8|@]|9|@]|C|$]]]|P|$Q|$5|R|S|T|C|$U|V]]|W|$5|R|S|T|C|$U|X]]|Y|$5|R|S|T|C|$U|Z]]]]

Found this answer here: <a href="https://stackoverflow.com/a/3372440/580173">link</a>

You can also use 

<pre><code>tapRecognizer.cancelsTouchesInView = NO;
</code></pre>

Which prevents the tap recognizer to be the only one to catch all the taps

UPDATE - <a href="https://stackoverflow.com/users/122780/michael-van-der-westhuizen">Michael</a> mentioned the link to the documentation describing this property: <a href="http://developer.apple.com/library/ios/documentation/UIKit/Reference/UIGestureRecognizer_Class/Reference/Reference.html#//apple_ref/occ/instp/UIGestureRecognizer/cancelsTouchesInView" rel="noreferrer">cancelsTouchesInView</a>

blocks|key|1888035|text|通过设置以下布尔值，可以阻止UITapGestureRecognizer取消其他事件(例如按钮上的点击)：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1888036|++++[tapRecognizer+setCancelsTouchesInView:NO];|code-block|syntax|javascript|1888037|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

You can stop the UITapGestureRecognizer from cancelling other events (such as the tap on your button) by setting the following boolean:

<pre><code> [tapRecognizer setCancelsTouchesInView:NO];
</code></pre>

blocks|key|335413|text|如果您的场景是这样的：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|335414|您有一个简单的视图和一些作为子视图添加到该视图中的UIButtons、UITextField控件。现在，除了控件(添加的子视图)之外，当您触摸视图上的其他任何位置时，都要关闭键盘。|335415|然后解决办法是：|335416|将以下方法添加到您的XYZViewController.m(它有您的视图)|335417|-+(void)touchesBegan:(NSSet+*)touches+withEvent:(UIEvent+*)event
{
++++[self.view+endEditing:YES];
}|code-block|syntax|javascript|335418|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|P|8|@]|9|@]|A|$]]|$1|D|3|E|5|6|7|Q|8|@]|9|@]|A|$]]|$1|F|3|G|5|6|7|R|8|@]|9|@]|A|$]]|$1|H|3|I|5|J|7|S|8|@]|9|@]|A|$K|L]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

<h2>If your scenario is like this:</h2>

You have a simple view and some UIButtons,UITextField controls added as subviews to that view. Now you want to dismiss the keyboard when you touch anywhere else on the view except on the controls(subviews you added)

<h2>Then Solution is:</h2>

Add the following method to your XYZViewController.m(which has your view)

<pre><code>- (void)touchesBegan:(NSSet *)touches withEvent:(UIEvent *)event
{
 [self.view endEditing:YES];
}
</code></pre>

blocks|key|335432|text|这些答案是不完整的。关于如何使用此布尔操作，我必须阅读多个帖子。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|335433|在*.h文件中添加以下内容|335434|@interface+v1ViewController+:+UIViewController+<UIGestureRecognizerDelegate>|code-block|syntax|javascript|335435|在*.m文件中添加以下内容|335436|-+(BOOL)gestureRecognizer:(UIGestureRecognizer+*)gestureRecognizer+shouldReceiveTouch:(UITouch+*)touch+{

++++NSLog(@"went+here+...");

++++if+([touch.view+isKindOfClass:[UIControl+class]])
++++{
++++++++//+we+touched+a+button,+slider,+or+other+UIControl
++++++++return+NO;+//+ignore+the+touch
++++}
++++return+YES;+//+handle+the+touch
}
-+(void)viewDidLoad
{
++++[super+viewDidLoad];
++++//+Do+any+additional+setup+after+loading+the+view,+typically+from+a+nib.



++++//tap+gestrure
++++UITapGestureRecognizer+*tapGestRecog+=+[[UITapGestureRecognizer+alloc]+initWithTarget:self+action:@selector(screenTappedOnce)];
++++[tapGestRecog+setNumberOfTapsRequired:1];
++++[self.view+addGestureRecognizer:tapGestRecog];


//+This+line+is+very+important.+if+You+don't+add+it+then+your+boolean+operation+will+never+get+called
tapGestRecog.delegate+=+self;

}


-(IBAction)+screenTappedOnce
{
++++NSLog(@"screenTappedOnce+...");

}|335437|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|P|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|Q|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|6|7|R|8|@]|9|@]|A|$]]|$1|K|3|L|5|F|7|S|8|@]|9|@]|A|$G|H]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

These answers were incomplete. I had to read multiple posts as to how to use this boolean operation.

In your *.h file add this

<pre><code>@interface v1ViewController : UIViewController &lt;UIGestureRecognizerDelegate&gt;
</code></pre>

In your *.m file add this

<pre><code>- (BOOL)gestureRecognizer:(UIGestureRecognizer *)gestureRecognizer shouldReceiveTouch:(UITouch *)touch {

 NSLog(@"went here ...");

 if ([touch.view isKindOfClass:[UIControl class]])
 {
 // we touched a button, slider, or other UIControl
 return NO; // ignore the touch
 }
 return YES; // handle the touch
}
- (void)viewDidLoad
{
 [super viewDidLoad];
 // Do any additional setup after loading the view, typically from a nib.



 //tap gestrure
 UITapGestureRecognizer *tapGestRecog = [[UITapGestureRecognizer alloc] initWithTarget:self action:@selector(screenTappedOnce)];
 [tapGestRecog setNumberOfTapsRequired:1];
 [self.view addGestureRecognizer:tapGestRecog];


// This line is very important. if You don't add it then your boolean operation will never get called
tapGestRecog.delegate = self;

}


-(IBAction) screenTappedOnce
{
 NSLog(@"screenTappedOnce ...");

}
</code></pre>

blocks|key|1888114|text|在iOS+6.0及更高版本中，默认控制操作防止重叠手势识别器行为。例如，按钮的默认操作是单个点击。如果在按钮的父视图上附加了一个点击手势识别器，并且用户点击按钮，则按钮的操作方法将接收触摸事件而不是手势识别器。这仅适用于与控件的默认操作重叠的手势识别，该操作包括：.|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1888115|来自苹果的API文档|offset|length|1888116|entityMap|0|LINK|mutability|MUTABLE|url|https://developer.apple.com/library/ios/documentation/EventHandling/Conceptual/EventHandlingiPhoneOS/GestureRecognizer_basics/GestureRecognizer_basics.html#//apple_ref/doc/uid/TP40009541-CH2-SW4^0|0|0|A|0|0^^$0|@$1|2|3|4|5|6|7|N|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|O|8|@]|9|@$D|P|E|Q|1|R]]|A|$]]|$1|F|3|-4|5|6|7|S|8|@]|9|@]|A|$]]]|G|$H|$5|I|J|K|A|$L|M]]]]

In iOS 6.0 and later, default control actions prevent overlapping gesture recognizer behavior. For example, the default action for a button is a single tap. If you have a single tap gesture recognizer attached to a button’s parent view, and the user taps the button, then the button’s action method receives the touch event instead of the gesture recognizer. This applies only to gesture recognition that overlaps the default action for a control, which includes:.....

<a href="https://developer.apple.com/library/ios/documentation/EventHandling/Conceptual/EventHandlingiPhoneOS/GestureRecognizer_basics/GestureRecognizer_basics.html#//apple_ref/doc/uid/TP40009541-CH2-SW4">From Apple's API doc</a>

blocks|key|335500|text|优化cdasher的答案，你会得到|type|unstyled|depth|inlineStyleRanges|entityRanges|data|335501|-+(BOOL)gestureRecognizer:(UIGestureRecognizer+*)gestureRecognizer
+++++++shouldReceiveTouch:(UITouch+*)touch+
{
++++return+![touch.view+isKindOfClass:[UIControl+class]];
}|code-block|syntax|javascript|335502|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Optimizing cdasher's answer, you get

<pre><code>- (BOOL)gestureRecognizer:(UIGestureRecognizer *)gestureRecognizer
 shouldReceiveTouch:(UITouch *)touch 
{
 return ![touch.view isKindOfClass:[UIControl class]];
}
</code></pre>

blocks|key|1532010|text|以下是对我有用的Swift版本的莉莉·巴拉德的回答：|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|1532011|func+gestureRecognizer(gestureRecognizer:+UIGestureRecognizer,+shouldReceiveTouch+touch:+UITouch)+->+Bool+{
++++if+(scrollView.superview+!=+nil)+{
++++++++if+((touch.view?.isDescendantOfView(scrollView))+!=+nil)+{+return+false+}
++++}
++++return+true
}|code-block|syntax|javascript|1532012|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/a/3348532/525576^0|G|9|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@$A|R|B|S|1|T]]|C|$]]|$1|D|3|E|5|F|7|U|8|@]|9|@]|C|$G|H]]|$1|I|3|-4|5|6|7|V|8|@]|9|@]|C|$]]]|J|$K|$5|L|M|N|C|$O|P]]]]

Here's the Swift version of <a href="https://stackoverflow.com/a/3348532/525576">Lily Ballard's answer</a> that worked for me:

<pre><code>func gestureRecognizer(gestureRecognizer: UIGestureRecognizer, shouldReceiveTouch touch: UITouch) -&gt; Bool {
 if (scrollView.superview != nil) {
 if ((touch.view?.isDescendantOfView(scrollView)) != nil) { return false }
 }
 return true
}
</code></pre>

blocks|key|335618|text|Swift+5|type|unstyled|depth|inlineStyleRanges|offset|length|style|BOLD|entityRanges|data|335619|在超级视图上按下按钮|335620|+func+gestureRecognizer(_+gestureRecognizer:+UIGestureRecognizer,+shouldReceive+touch:+UITouch)+->+Bool+{
++++if+let+_+=+touch.view+as?+UIButton+{+return+false+}
++++return+true
}|code-block|syntax|javascript|335621|在我的例子中，实现hitTest为我工作。我有带按钮的集合视图|335622|该方法通过调用每个子视图的point(inside:with:)方法来遍历视图层次结构，以确定哪个子视图应该接收触摸事件。如果point(inside:with:)返回true，则子视图的层次结构类似地遍历，直到找到包含指定点的最前端视图。|CODE|335623|override+func+hitTest(_+point:+CGPoint,+with+event:+UIEvent?)+->+UIView?+{
++++guard+isUserInteractionEnabled+else+{+return+nil+}

++++guard+!isHidden+else+{+return+nil+}

++++guard+alpha+>=+0.01+else+{+return+nil+}

++++guard+self.point(inside:+point,+with:+event)+else+{+return+nil+}

++++for+eachImageCell+in+collectionView.visibleCells+{
++++++++for+eachImageButton+in+eachImageCell.subviews+{
++++++++++++if+let+crossButton+=+eachImageButton+as?+UIButton+{
++++++++++++++++if+crossButton.point(inside:+convert(point,+to:+crossButton),+with:+event)+{
++++++++++++++++++++return+crossButton
++++++++++++++++}
++++++++++++}
++++++++}
++++}
++++return+super.hitTest(point,+with:+event)
}|335624|entityMap^0|0|7|0|0|0|9|7|0|D|J|1R|J|0|0^^$0|@$1|2|3|4|5|6|7|V|8|@$9|W|A|X|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|Y|8|@]|D|@]|E|$]]|$1|H|3|I|5|J|7|Z|8|@]|D|@]|E|$K|L]]|$1|M|3|N|5|6|7|10|8|@$9|11|A|12|B|C]]|D|@]|E|$]]|$1|O|3|P|5|6|7|13|8|@$9|14|A|15|B|Q]|$9|16|A|17|B|Q]]|D|@]|E|$]]|$1|R|3|S|5|J|7|18|8|@]|D|@]|E|$K|L]]|$1|T|3|-4|5|6|7|19|8|@]|D|@]|E|$]]]|U|$]]

Swift 5

Button on superview with tapgesture

<pre><code> func gestureRecognizer(_ gestureRecognizer: UIGestureRecognizer, shouldReceive touch: UITouch) -&gt; Bool {
 if let _ = touch.view as? UIButton { return false }
 return true
}
</code></pre>

In my case implementing hitTest worked for me. I had collection view with button

This method traverses the view hierarchy by calling the <code>point(inside:with:)</code> method of each subview to determine which subview should receive a touch event. If <code>point(inside:with:)</code> returns true, then the subview’s hierarchy is similarly traversed until the frontmost view containing the specified point is found. 

<pre><code>override func hitTest(_ point: CGPoint, with event: UIEvent?) -&gt; UIView? {
 guard isUserInteractionEnabled else { return nil }

 guard !isHidden else { return nil }

 guard alpha &gt;= 0.01 else { return nil }

 guard self.point(inside: point, with: event) else { return nil }

 for eachImageCell in collectionView.visibleCells {
 for eachImageButton in eachImageCell.subviews {
 if let crossButton = eachImageButton as? UIButton {
 if crossButton.point(inside: convert(point, to: crossButton), with: event) {
 return crossButton
 }
 }
 }
 }
 return super.hitTest(point, with: event)
}
</code></pre>

I have view with a <code>UITapGestureRecognizer</code>. So when I tap on the view another view appears above this view. This new view has three buttons. When I now press on one of these buttons I don't get the buttons action, I only get the tap gesture action. So I'm not able to use these buttons anymore. What can I do to get the events through to these buttons? The weird thing is that the buttons still get highlighted.

I can't just remove the UITapGestureRecognizer after I received it's tap. Because with it the new view can also be removed. Means I want a behavior like the fullscreen vide controls.

UIButton inside a view that has a UITapGestureRecognizer

参与人人有奖，腾讯云大模型知识引擎×DeepSeek最佳实践有奖征文正在进行中！点击查看活动详情：<a href="https://cloud.tencent.com/developer/article/2496399" target="_blank">https://cloud.tencent.com/developer/article/2496399</a> 
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我有一个UITapGestureRecognizer视图。因此，当我点击视图时，另一个视图出现在此视图之上。这个新视图有三个按钮。当我现在按下其中一个按钮时，我没有按钮动作，我只得到点击手势动作。所以我不能再用这些按钮了。我该怎么做才能让这些事件转到这些按钮上呢？奇怪的是按钮仍然被突出显示。我不能在收到UITapGes...

问UIButton在具有UITapGestureRecognizer的视图中
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