这个问题是我要问的,但答案并没有详细说明_token是如何派生出来的。它似乎只使用WindowsIdentity.GetCurrent().Token
,因此不会发生模拟。
下一个问题有相互矛盾的答案,被接受的一个问题有一个评论:“我开始怀疑我的问题在别处。”没什么用。
下一个问题似乎意味着它是不可能的,但它涉及两个领域,所以我不确定它是否相关。
我真正的问题是:
到目前为止,我尝试的是使用来自http://msdn.microsoft.com/en-us/library/chf6fbt4%28v=VS.80%29.aspx的代码
bool returnValue = LogonUser(user, domain, password,
LOGON32_LOGON_NETWORK, LOGON32_PROVIDER_DEFAULT,
ref tokenHandle);
// after this point, returnValue = false
Win32错误是
登录失败:用户名未知或密码错误
发布于 2012-03-12 15:19:34
很少有帖子建议使用LOGON_TYPE_NEW_CREDENTIALS
而不是LOGON_TYPE_NETWORK
或LOGON_TYPE_INTERACTIVE
。我有一个模拟问题,一个机器连接到一个域,而另一个没有,这修复了它。这个职位中的最后一个代码片段表明,在林中模拟确实有效,但它并没有具体说明建立信任的问题。所以这可能是值得一试的:
const int LOGON_TYPE_NEW_CREDENTIALS = 9;
const int LOGON32_PROVIDER_WINNT50 = 3;
bool returnValue = LogonUser(user, domain, password,
LOGON_TYPE_NEW_CREDENTIALS, LOGON32_PROVIDER_WINNT50,
ref tokenHandle);
MSDN说,LOGON_TYPE_NEW_CREDENTIALS
只在使用LOGON32_PROVIDER_WINNT50
时才能工作。
发布于 2013-06-20 15:02:54
对我来说,这是一个完整的例子(我希望更多的人这样做):
//logon impersonation
using System.Runtime.InteropServices; // DllImport
using System.Security.Principal; // WindowsImpersonationContext
using System.Security.Permissions; // PermissionSetAttribute
...
class Program {
// obtains user token
[DllImport("advapi32.dll", SetLastError = true)]
public static extern bool LogonUser(string pszUsername, string pszDomain, string pszPassword,
int dwLogonType, int dwLogonProvider, ref IntPtr phToken);
// closes open handes returned by LogonUser
[DllImport("kernel32.dll", CharSet = CharSet.Auto)]
public extern static bool CloseHandle(IntPtr handle);
public void DoWorkUnderImpersonation() {
//elevate privileges before doing file copy to handle domain security
WindowsImpersonationContext impersonationContext = null;
IntPtr userHandle = IntPtr.Zero;
const int LOGON32_PROVIDER_DEFAULT = 0;
const int LOGON32_LOGON_INTERACTIVE = 2;
string domain = ConfigurationManager.AppSettings["ImpersonationDomain"];
string user = ConfigurationManager.AppSettings["ImpersonationUser"];
string password = ConfigurationManager.AppSettings["ImpersonationPassword"];
try {
Console.WriteLine("windows identify before impersonation: " + WindowsIdentity.GetCurrent().Name);
// if domain name was blank, assume local machine
if (domain == "")
domain = System.Environment.MachineName;
// Call LogonUser to get a token for the user
bool loggedOn = LogonUser(user,
domain,
password,
LOGON32_LOGON_INTERACTIVE,
LOGON32_PROVIDER_DEFAULT,
ref userHandle);
if (!loggedOn) {
Console.WriteLine("Exception impersonating user, error code: " + Marshal.GetLastWin32Error());
return;
}
// Begin impersonating the user
impersonationContext = WindowsIdentity.Impersonate(userHandle);
Console.WriteLine("Main() windows identify after impersonation: " + WindowsIdentity.GetCurrent().Name);
//run the program with elevated privileges (like file copying from a domain server)
DoWork();
} catch (Exception ex) {
Console.WriteLine("Exception impersonating user: " + ex.Message);
} finally {
// Clean up
if (impersonationContext != null) {
impersonationContext.Undo();
}
if (userHandle != IntPtr.Zero) {
CloseHandle(userHandle);
}
}
}
private void DoWork() {
//everything in here has elevated privileges
//example access files on a network share through e$
string[] files = System.IO.Directory.GetFiles(@"\\domainserver\e$\images", "*.jpg");
}
}
发布于 2011-10-07 20:28:55
我也有同样的问题。不知道你是否解决了这个问题,但我真正想要做的是用AD凭证访问一个网络共享。在这种情况下,需要使用WNetAddConnection2()
。
https://stackoverflow.com/questions/5023607
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