blocks|key|3050805|text|在sed中合并行是可能的，但就我个人而言，我认为需要更改行，这意味着是时候放弃sed，转而使用更强大的语言了。您需要的是一行perl：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3050806|perl+-e+'undef+$/;+while+(<>)+{+s/\n/\\n/g;+s/\r/\\r/g;+print+$_,+"\n"+}'|code-block|syntax|javascript|3050807|或者12行python：|3050808|#!+/usr/bin/python
import+fileinput
from+sys+import+stdout
first+=+True
for+line+in+fileinput.input(mode="rb"):
++++if+fileinput.isfirstline()+and+not+first:
++++++++stdout.write("\n")
++++if+line.endswith("\r\n"):+stdout.write(line[:-2]+%2B+"\\r\\n")
++++elif+line.endswith("\n"):+stdout.write(line[:-1]+%2B+"\\n")
++++elif+line.endswith("\r"):+stdout.write(line[:-1]+%2B+"\\r")
++++first+=+False
if+not+first:+stdout.write("\n")|3050809|或者用10行C代码来完成这项工作，但是由于您必须自己处理argv，所以还需要大量的代码：|offset|length|style|CODE|3050810|#include+<stdio.h>

void+process_one(FILE+*fp)
{
++++int+c;
++++while+((c+=+getc(fp))+!=+EOF)
++++++++if+(c+==+'\n')+fputs("\\n",+stdout);
++++++++else+if+(c+==+'\r')+fputs("\\r",+stdout);
++++++++else+putchar(c);
++++fclose(fp);
++++putchar('\n');
}

int+main(int+argc,+char+**argv)
{
++++FILE+*cur;
++++int+i,+consumed_stdin+=+0,+rv+=+0;
++++if+(argc+==+1)+/*+no+arguments+*/
++++{
++++++++process_one(stdin);
++++++++return+0;
++++}

++++for+(i+=+1;+i+<+argc;+i%2B%2B)
++++{
++++++++if+(argc[i][0]+==+'-'+&&+argc[i][1]+==+0)
++++++++{
++++++++++++if+(consumed_stdin)
++++++++++++{
++++++++++++++++fputs("cannot+read+stdin+twice\n",+stderr);
++++++++++++++++rv+=+1;
++++++++++++++++continue;
++++++++++++}
++++++++++++cur+=+stdin;
++++++++++++consumed_stdin+=+1;
++++++++}
++++++++else
++++++++{
++++++++++++cur+=+fopen(ac[i],+"rb");
++++++++++++if+(!cur)
++++++++++++{
++++++++++++++++perror(ac[i]);
++++++++++++++++rv+=+1;
++++++++++++++++continue;
++++++++++++}
++++++++}
++++++++process_one(cur);
+++++}
+++++return+rv;
+}|3050811|entityMap^0|0|0|0|0|S|4|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|V|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|W|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|X|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|Y|8|@$M|Z|N|10|O|P]]|9|@]|A|$]]|$1|Q|3|R|5|D|7|11|8|@]|9|@]|A|$E|F]]|$1|S|3|-4|5|6|7|12|8|@]|9|@]|A|$]]]|T|$]]

It's possible to merge lines in sed, but personally, I consider needing to change line breaks a sign that it's time to give up on sed and use a more powerful language instead. What you want is one line of perl:

<pre><code>perl -e 'undef $/; while (&lt;&gt;) { s/\n/\\n/g; s/\r/\\r/g; print $_, "\n" }'
</code></pre>

or 12 lines of python:

<pre><code>#! /usr/bin/python
import fileinput
from sys import stdout
first = True
for line in fileinput.input(mode="rb"):
 if fileinput.isfirstline() and not first:
 stdout.write("\n")
 if line.endswith("\r\n"): stdout.write(line[:-2] + "\\r\\n")
 elif line.endswith("\n"): stdout.write(line[:-1] + "\\n")
 elif line.endswith("\r"): stdout.write(line[:-1] + "\\r")
 first = False
if not first: stdout.write("\n")
</code></pre>

or 10 lines of C to do the job, but then a whole bunch more because you have to process <code>argv</code> yourself:

<pre><code>#include &lt;stdio.h&gt;

void process_one(FILE *fp)
{
 int c;
 while ((c = getc(fp)) != EOF)
 if (c == '\n') fputs("\\n", stdout);
 else if (c == '\r') fputs("\\r", stdout);
 else putchar(c);
 fclose(fp);
 putchar('\n');
}

int main(int argc, char **argv)
{
 FILE *cur;
 int i, consumed_stdin = 0, rv = 0;
 if (argc == 1) /* no arguments */
 {
 process_one(stdin);
 return 0;
 }

 for (i = 1; i &lt; argc; i++)
 {
 if (argc[i][0] == '-' &amp;&amp; argc[i][1] == 0)
 {
 if (consumed_stdin)
 {
 fputs("cannot read stdin twice\n", stderr);
 rv = 1;
 continue;
 }
 cur = stdin;
 consumed_stdin = 1;
 }
 else
 {
 cur = fopen(ac[i], "rb");
 if (!cur)
 {
 perror(ac[i]);
 rv = 1;
 continue;
 }
 }
 process_one(cur);
 }
 return rv;
 }
</code></pre>

blocks|key|3050831|text|这两个命令一起执行您想做的事情：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3050832|sed+':a;N;$!ba;s/\r/\\r/g'
sed+':a;N;$!ba;s/\n/\\n/g'|code-block|syntax|javascript|3050833|把你的输入文件都传递出去，以得到你想要的输出。可能有一种方法可以将它们组合成一个表达式。|3050834|从这个问题中窃取和修改：|3050835|How+can+I+replace+a+newline+(\n)+using+sed?|offset|length|3050836|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/questions/1251999/sed-how-can-i-replace-a-newline-n^0|0|0|0|0|0|17|0|0^^$0|@$1|2|3|4|5|6|7|W|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|X|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Y|8|@]|9|@]|A|$]]|$1|I|3|J|5|6|7|Z|8|@]|9|@]|A|$]]|$1|K|3|L|5|6|7|10|8|@]|9|@$M|11|N|12|1|13]]|A|$]]|$1|O|3|-4|5|6|7|14|8|@]|9|@]|A|$]]]|P|$Q|$5|R|S|T|A|$U|V]]]]

These two commands together should do what you want:

<pre><code>sed ':a;N;$!ba;s/\r/\\r/g'
sed ':a;N;$!ba;s/\n/\\n/g'
</code></pre>

Pass your input file through both to get the output you want. Theres probably a way to combine them into a single expression.

Stolen and Modified from this question:

<a href="https://stackoverflow.com/questions/1251999/sed-how-can-i-replace-a-newline-n">How can I replace a newline (\n) using sed?</a>

blocks|key|932576|text|tr+-s+'\r'+'\n'+<file+%7C+unix2dos|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|932577|编辑(有人指出，上面的内容完全遗漏了要点！./.)|unstyled|offset|length|style|BOLD|932578|tr+-s+'\r'+'\n'+<file+%7C+perl+-pe+'s/\s%2B$/\\r\\n/'|932579|tr消除空行和dos行结束。管道意味着两个过程|CODE|932580|entityMap^0|0|0|2|0|0|0|2|0^^$0|@$1|2|3|4|5|6|7|R|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|S|8|@$G|T|H|U|I|J]]|9|@]|A|$]]|$1|K|3|L|5|6|7|V|8|@]|9|@]|A|$B|C]]|$1|M|3|N|5|F|7|W|8|@$G|X|H|Y|I|O]]|9|@]|A|$]]|$1|P|3|-4|5|F|7|Z|8|@]|9|@]|A|$]]]|Q|$]]

<pre><code>tr -s '\r' '\n' &lt;file | unix2dos
</code></pre>

EDIT (it's been pointed out that the above misses the point entirely! •///•)

<pre><code>tr -s '\r' '\n' &lt;file | perl -pe 's/\s+$/\\r\\n/'
</code></pre>

The <code>tr</code> gets rid of empty lines and dos line endings. The pipe means two processes&mdash;good on modern hardware.

blocks|key|932589|text|awk+'{printf("%25s\\r\\n",$0)}+END+{print+""}'+file|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|932590|entityMap^0|0|1D|0^^$0|@$1|2|3|4|5|6|7|H|8|@$9|I|A|J|B|C]]|D|@]|E|$]]|$1|F|3|-4|5|6|7|K|8|@]|D|@]|E|$]]]|G|$]]

<code>awk '{printf("%s\\r\\n",$0)} END {print ""}' file</code>

I have files like

<blockquote>
 aaa
 
 bbb
 
 ccc
</blockquote>

I need them to sed into <code>aaa\r\nbbb\r\nccc</code>

It should work either for unix and windows replacing them with <code>\r</code> or <code>\r\n</code> accordingly

The problem is that <code>sed</code> adds <code>\n</code> at the end of line but keeps lines separated. How can I fix it?

sed: how to replace CR and/or LF with "\r" "\n", so any file will be in one line

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我有这样的文件 aaabbbccc我需要他们把他们转到aaa\r\nbbb\r\nccc它应该适用于unix和windows，并相应地用\r或\r\n替换它们。问题是，sed在行尾添加了\n，但保持了行之间的分隔。我怎么才能修好它？

问sed:如何将CR和/或LF替换为"\r“"\n"，以便任何文件都在一行中
EN

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问sed:如何将CR和/或LF替换为"\r“"\n"，以便任何文件都在一行中EN