blocks|key|1165227|text|您可以使用电话urls调用电话应用程序为您拨一个号码。看这个参考文献。|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|1165228|缺点是，一旦通话结束，用户将在电话应用程序中持久化。但恐怕这个问题没有解决办法。由于安全和隐私的原因，iOS不允许任何应用程序直接发起呼叫。|1165229|您可以在拨号时使用逗号来引入暂停。|1165230|entityMap|0|LINK|mutability|MUTABLE|url|http://developer.apple.com/library/safari/#featuredarticles/iPhoneURLScheme_Reference/Articles/PhoneLinks.html#//apple_ref/doc/uid/TP40007893-SW1^0|U|4|0|0|0|0^^$0|@$1|2|3|4|5|6|7|P|8|@]|9|@$A|Q|B|R|1|S]]|C|$]]|$1|D|3|E|5|6|7|T|8|@]|9|@]|C|$]]|$1|F|3|G|5|6|7|U|8|@]|9|@]|C|$]]|$1|H|3|-4|5|6|7|V|8|@]|9|@]|C|$]]]|I|$J|$5|K|L|M|C|$N|O]]]]

You can use Phone urls to invoke the Phone application to dial a number for you. See this <a href="http://developer.apple.com/library/safari/#featuredarticles/iPhoneURLScheme_Reference/Articles/PhoneLinks.html#//apple_ref/doc/uid/TP40007893-SW1" rel="nofollow">reference</a>.

The downside is that once the call is finished, user will endup in the Phone application. But I am afraid there is no solution to that problem. iOS doesn't allow any application to directly initiate a call because of security and privacy reasons.

You can use comma for introducing pause(s) while dialing a number.

blocks|key|1165247|text|请遵循本教程|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1165248|http://www.makebetterthings.com/blogs/iphone/open-phone-sms-email-map-and-browser-apps-in-iphone-sdk/|offset|length|1165249|打电话给一个号码-|1165250|NSURL+*url+=+[NSURL+URLWithString:@"tel://012-4325-234"];
[[UIApplication+sharedApplication]+openURL:url];|code-block|syntax|javascript|1165251|在打完电话后打开你的应用程序-|1165252|(注:电话提示无证)|1165253|NSURL+*url+=+[NSURL+URLWithString:@"telprompt://012-4325-234"];
[[UIApplication+sharedApplication]+openURL:url];|1165254|entityMap|0|LINK|mutability|MUTABLE|url^0|0|0|2T|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Z|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|10|8|@]|9|@$D|11|E|12|1|13]]|A|$]]|$1|F|3|G|5|6|7|14|8|@]|9|@]|A|$]]|$1|H|3|I|5|J|7|15|8|@]|9|@]|A|$K|L]]|$1|M|3|N|5|6|7|16|8|@]|9|@]|A|$]]|$1|O|3|P|5|6|7|17|8|@]|9|@]|A|$]]|$1|Q|3|R|5|J|7|18|8|@]|9|@]|A|$K|L]]|$1|S|3|-4|5|6|7|19|8|@]|9|@]|A|$]]]|T|$U|$5|V|W|X|A|$Y|C]]]]

follow the tutorial

<a href="http://www.makebetterthings.com/blogs/iphone/open-phone-sms-email-map-and-browser-apps-in-iphone-sdk/" rel="nofollow noreferrer">http://www.makebetterthings.com/blogs/iphone/open-phone-sms-email-map-and-browser-apps-in-iphone-sdk/</a>

to call a number use -

<pre><code>NSURL *url = [NSURL URLWithString:@"tel://012-4325-234"];
[[UIApplication sharedApplication] openURL:url];
</code></pre>

to open your app after call finished use -

(Note: telprompt is undocumented)

<pre><code>NSURL *url = [NSURL URLWithString:@"telprompt://012-4325-234"];
[[UIApplication sharedApplication] openURL:url];
</code></pre>

blocks|key|2362072|text|您可以使用UIApplication的openURL:方法以编程方式拨打电话号码(参见下面的示例)。我不确定是否支持访问代码，但这至少是一个起点。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|2362073|NSURL+*URL+=+[NSURL+URLWithString:@"tel://900-3440-567"];
[[UIApplication+sharedApplication]+openURL:URL];|code-block|syntax|javascript|2362074|编辑：查看Apple方案参考和UIApplication类引用以获得更多信息。|BOLD|2362075|entityMap|0|LINK|mutability|MUTABLE|url|http://developer.apple.com/library/safari/#featuredarticles/iPhoneURLScheme_Reference/Articles/PhoneLinks.html#//apple_ref/doc/uid/TP40007893-SW1|1|http://developer.apple.com/library/ios/#documentation/uikit/reference/UIApplication_Class/Reference/Reference.html^0|5|D|J|8|0|0|0|3|5|9|0|F|G|1|0^^$0|@$1|2|3|4|5|6|7|X|8|@$9|Y|A|Z|B|C]|$9|10|A|11|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|12|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|13|8|@$9|14|A|15|B|M]]|D|@$9|16|A|17|1|18]|$9|19|A|1A|1|1B]]|E|$]]|$1|N|3|-4|5|6|7|1C|8|@]|D|@]|E|$]]]|O|$P|$5|Q|R|S|E|$T|U]]|V|$5|Q|R|S|E|$T|W]]]]

You can programmatically dial phone numbers using <code>UIApplication</code>'s <code>openURL:</code> method (see example below). I'm unsure if access codes are supported, but this is at least a starting point.

<pre><code>NSURL *URL = [NSURL URLWithString:@"tel://900-3440-567"];
[[UIApplication sharedApplication] openURL:URL];
</code></pre>

Edit: See the <a href="http://developer.apple.com/library/safari/#featuredarticles/iPhoneURLScheme_Reference/Articles/PhoneLinks.html#//apple_ref/doc/uid/TP40007893-SW1" rel="noreferrer">Apple URL Scheme Reference</a> and the <a href="http://developer.apple.com/library/ios/#documentation/uikit/reference/UIApplication_Class/Reference/Reference.html" rel="noreferrer">UIApplication Class Reference</a> for more information.

blocks|key|2362084|text|UIDevice+*device+=+[UIDevice+currentDevice];
if+([[device+model]+isEqualToString:@"iPhone"]+)+{
++++[[UIApplication+sharedApplication]+openURL:[NSURL+URLWithString:[NSString+stringWithFormat:@"tel:130-032-2837"]]];
}+else+{
++++UIAlertView+*notPermitted=[[UIAlertView+alloc]+initWithTitle:@"Alert"+message:@"Your+device+doesn't+support+this+feature."+delegate:nil+cancelButtonTitle:@"OK"+otherButtonTitles:nil];
++++[notPermitted+show];
++++[notPermitted+release];
}|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|2362085|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>UIDevice *device = [UIDevice currentDevice];
if ([[device model] isEqualToString:@"iPhone"] ) {
 [[UIApplication sharedApplication] openURL:[NSURL URLWithString:[NSString stringWithFormat:@"tel:130-032-2837"]]];
} else {
 UIAlertView *notPermitted=[[UIAlertView alloc] initWithTitle:@"Alert" message:@"Your device doesn't support this feature." delegate:nil cancelButtonTitle:@"OK" otherButtonTitles:nil];
 [notPermitted show];
 [notPermitted release];
}
</code></pre>

blocks|key|2362118|text|不可能以编程方式拨包含号码和访问代码.的电话号码。|type|unstyled|depth|inlineStyleRanges|offset|length|style|BOLD|entityRanges|data|2362119|Apple+Developer+Library提供了以下信息：|2362120|"...the电话应用程序支持电话系统中的大多数(但不是全部)特殊字符。特别是，如果一个URL包含*或#字符，则电话应用程序不会尝试拨相应的电话号码。“|2362121|请参阅：Apple方案参考|2362122|entityMap|0|LINK|mutability|MUTABLE|url|http://developer.apple.com/library/ios/#featuredarticles/iPhoneURLScheme_Reference/Articles/PhoneLinks.html^0|D|6|0|0|1F|3|1Q|C|0|4|9|0|0^^$0|@$1|2|3|4|5|6|7|T|8|@$9|U|A|V|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|W|8|@]|D|@]|E|$]]|$1|H|3|I|5|6|7|X|8|@$9|Y|A|Z|B|C]|$9|10|A|11|B|C]]|D|@]|E|$]]|$1|J|3|K|5|6|7|12|8|@]|D|@$9|13|A|14|1|15]]|E|$]]|$1|L|3|-4|5|6|7|16|8|@]|D|@]|E|$]]]|M|$N|$5|O|P|Q|E|$R|S]]]]

It's not possible to dial programmatically a phone number that includes number and access code.
The Apple Developer Library gives the following info:
&quot;...the Phone application supports most, but not all, of the special characters in the tel scheme. Specifically, if a URL contains the * or # characters, the Phone application does not attempt to dial the corresponding phone number.&quot;
See: <a href="http://developer.apple.com/library/ios/#featuredarticles/iPhoneURLScheme_Reference/Articles/PhoneLinks.html" rel="nofollow noreferrer">Apple URL Scheme Reference</a>

blocks|key|2722350|text|我不知道您是否真的找到了传递访问代码的解决方案，但对于我来说，这段代码起了作用：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2722351|NSString+*dialstring+=+[[NSString+alloc]+initWithFormat:@"tel:your_phonenumber,your_accessnumber"];+|code-block|syntax|javascript|2722352|这将导致具有以下值的拨号字符串：tel:9003440567,65445|offset|length|style|CODE|2722353|其余部分由iOS的电话应用程序管理，命令如下：|2722354|[[UIApplication+sharedApplication]+openURL:[NSURL+URLWithString:dialstring]];|2722355|字符串中的,会导致您的电话系统(您想进入会议室的电话系统)在拨第一个号码并建立连接之后暂停。因此，电话系统有时间向您询问访问代码(我认为它应该问您，这就是我们的系统的工作方式)。在此之后，您的访问代码应该被传递。|2722356|要注意：您的访问代码将以非保密的方式传递进来。例如:您所显示的访问代码将以如下方式显示在iPhone电话应用程序中：9003440567,65445|BOLD|2722357|entityMap^0|0|0|G|K|0|0|0|5|1|0|0|3|1M|G|0^^$0|@$1|2|3|4|5|6|7|X|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|Y|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Z|8|@$I|10|J|11|K|L]]|9|@]|A|$]]|$1|M|3|N|5|6|7|12|8|@]|9|@]|A|$]]|$1|O|3|P|5|D|7|13|8|@]|9|@]|A|$E|F]]|$1|Q|3|R|5|6|7|14|8|@$I|15|J|16|K|L]]|9|@]|A|$]]|$1|S|3|T|5|6|7|17|8|@$I|18|J|19|K|U]|$I|1A|J|1B|K|U]]|9|@]|A|$]]|$1|V|3|-4|5|6|7|1C|8|@]|9|@]|A|$]]]|W|$]]

I don't know if you actually found a solution for passing the access code, but for me this code worked:

<pre><code>NSString *dialstring = [[NSString alloc] initWithFormat:@"tel:your_phonenumber,your_accessnumber"]; 
</code></pre>

That will result in a dial string with the following values:
<code>tel:9003440567,65445</code>

The remaining parts are managed by the phone app of iOS with the following command:

<pre><code>[[UIApplication sharedApplication] openURL:[NSURL URLWithString:dialstring]];
</code></pre>

The <code>,</code> in the string causes a pause in your telephonesystem (the one where you want to access a conference room) right after the first number is dialed and a connection is established. So the telephonesystem has time to ask you for the access code (I think it should ask you, that's the way our system works). And after that your access code should be passed. 

BE AWARE: Your access code will be passed in in a non-secret way. For example: Your shown access code will be displayed in the iPhone phone app display this way: 9003440567, 65445

blocks|key|1165354|text|使用这个用户可以在呼叫时重定向，通话后他/她将自动重定向到应用程序。对我来说很管用，而且肯定是这样的。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1165355|if+([[device+model]+isEqualToString:@"iPhone"]+)+{

++++NSString+*phoneNumber+=+[@"telprompt://"+stringByAppendingString:cellNameStr];
++++[[UIApplication+sharedApplication]+openURL:[NSURL+URLWithString:phoneNumber]];

}+else+{

++++UIAlertView+*warning+=[[UIAlertView+alloc]+initWithTitle:@"Alert"+message:@"Your+device+doesn't+support+this+feature."+delegate:nil+cancelButtonTitle:@"OK"+otherButtonTitles:nil];

++++[warning+show];
}|code-block|syntax|javascript|1165356|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Using this user can redirect on Call and after the call he/she will automatically redirected to the app. It's working for me and sure about it.

<pre><code>if ([[device model] isEqualToString:@"iPhone"] ) {

 NSString *phoneNumber = [@"telprompt://" stringByAppendingString:cellNameStr];
 [[UIApplication sharedApplication] openURL:[NSURL URLWithString:phoneNumber]];

} else {

 UIAlertView *warning =[[UIAlertView alloc] initWithTitle:@"Alert" message:@"Your device doesn't support this feature." delegate:nil cancelButtonTitle:@"OK" otherButtonTitles:nil];

 [warning show];
}
</code></pre>

blocks|key|1165401|text|拨打电话号码的方法有很多，所描述的方式是：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1165402|[UIApplication+sharedApplication+openURL:NSURL：@“电话:555-555-5555”|1165403|这是一个有效的方法，但它有许多问题。首先，它没有正确地提示用户，其次，当电话呼叫完成时，它不会将用户带回到应用程序。要正确地打电话，您应该在呼叫之前提示，这样您就不会让用户感到惊讶，并且应该在呼叫完成后将用户带回应用程序。|1165404|这两种方法都可以在不使用私有API的情况下实现，正如这里的一些答案所建议的那样。推荐的方法使用telprompt，但它不使用调用的私有实例化，而是创建一个web视图，允许将来的兼容性。|1165405|%2B+(void)callWithString:(NSString+*)phoneString
{
++++[self+callWithURL:[NSURL+URLWithString:[NSString+stringWithFormat:@"tel:%25@",phoneString]]];
}
%2B+(void)callWithURL:(NSURL+*)url
{
++++static+UIWebView+*webView+=+nil;
++++static+dispatch_once_t+onceToken;
++++dispatch_once(&onceToken,+%5E{++
++++++++webView+=+[UIWebView+new];
++++});
++++[webView+loadRequest:[NSURLRequest+requestWithURL:url]];
}|code-block|syntax|javascript|1165406|这里提供了一个示例项目和其他信息：http://www.raizlabs.com/dev/2014/04/getting-the-best-behavior-from-phone-call-requests-using-tel-in-an-ios-app/|offset|length|1165407|entityMap|0|LINK|mutability|MUTABLE|url|http://www.raizlabs.com/dev/2014/04/getting-the-best-behavior-from-phone-call-requests-using-tel-in-an-ios-app/^0|0|0|0|0|0|H|33|0|0^^$0|@$1|2|3|4|5|6|7|Y|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|Z|8|@]|9|@]|A|$]]|$1|D|3|E|5|6|7|10|8|@]|9|@]|A|$]]|$1|F|3|G|5|6|7|11|8|@]|9|@]|A|$]]|$1|H|3|I|5|J|7|12|8|@]|9|@]|A|$K|L]]|$1|M|3|N|5|6|7|13|8|@]|9|@$O|14|P|15|1|16]]|A|$]]|$1|Q|3|-4|5|6|7|17|8|@]|9|@]|A|$]]]|R|$S|$5|T|U|V|A|$W|X]]]]

There are a number of ways to dial a phone number and the way described that uses:

[[UIApplication sharedApplication] openURL:[NSURL URLWithString:@"tel:555-555-5555"]

Is a valid way to do this however it has a number of issues. First it doesn't properly prompt the user and secondly it doesn't bring the user back to the application when the phone call is completed. To properly place a phone call you should both prompt before the call so you don't surprise the user and you should bring the user back to the application once the call is done. 

Both of these can be accomplished without using a private API as is suggested by some of the answers here. The recommended approach uses the telprompt api but it doesn't use the private instantiation of the call and instead creates a web view allowing for future compatibility. 

<pre><code>+ (void)callWithString:(NSString *)phoneString
{
 [self callWithURL:[NSURL URLWithString:[NSString stringWithFormat:@"tel:%@",phoneString]]];
}
+ (void)callWithURL:(NSURL *)url
{
 static UIWebView *webView = nil;
 static dispatch_once_t onceToken;
 dispatch_once(&amp;onceToken, ^{ 
 webView = [UIWebView new];
 });
 [webView loadRequest:[NSURLRequest requestWithURL:url]];
}
</code></pre>

A sample project and additional information is provided here:
<a href="http://www.raizlabs.com/dev/2014/04/getting-the-best-behavior-from-phone-call-requests-using-tel-in-an-ios-app/" rel="nofollow">http://www.raizlabs.com/dev/2014/04/getting-the-best-behavior-from-phone-call-requests-using-tel-in-an-ios-app/</a>

blocks|key|1165443|text|以下是Swift中的一种自给解决方案|type|unstyled|depth|inlineStyleRanges|offset|length|style|BOLD|entityRanges|data|1165444|private+func+callNumber(phoneNumber:String)+{
++if+let+phoneCallURL:NSURL+=+NSURL(string:+"tel://\(phoneNumber)")+{
++++let+application:UIApplication+=+UIApplication.sharedApplication()
++++if+(application.canOpenURL(phoneCallURL))+{
++++++application.openURL(phoneCallURL);
++++}
++}
}|code-block|syntax|javascript|1165445|现在您应该能够使用callNumber("7178881234")打电话了，希望这会有所帮助！|CODE|1165446|entityMap^0|3|5|0|0|9|O|0^^$0|@$1|2|3|4|5|6|7|P|8|@$9|Q|A|R|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|S|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|T|8|@$9|U|A|V|B|M]]|D|@]|E|$]]|$1|N|3|-4|5|6|7|W|8|@]|D|@]|E|$]]]|O|$]]

Here is a self-contained solution in Swift:

<pre><code>private func callNumber(phoneNumber:String) {
 if let phoneCallURL:NSURL = NSURL(string: "tel://\(phoneNumber)") {
 let application:UIApplication = UIApplication.sharedApplication()
 if (application.canOpenURL(phoneCallURL)) {
 application.openURL(phoneCallURL);
 }
 }
}
</code></pre>

Now you should be able to use <code>callNumber("7178881234")</code> to make a call; hope this helps!

blocks|key|1165448|text|SWIFT5.0：以防止有人需要更新的快速代码：|type|unstyled|depth|inlineStyleRanges|offset|length|style|BOLD|entityRanges|data|1165449|private+func+callNumber(phoneNumber:String)+{
++++if+let+phoneCallURL:NSURL+=+NSURL(string:+"tel://\(phoneNumber)")+{
++++++++let+application:UIApplication+=+UIApplication.shared
++++++++if+(application.canOpenURL(phoneCallURL+as+URL))+{
++++++++++++if+#available(iOS+10.0,+*)+{
++++++++++++++++UIApplication.shared.open(phoneCallURL+as+URL)
++++++++++++}+else+{
++++++++++++++++UIApplication.shared.openURL(phoneCallURL+as+URL)
++++++++++++}
++++++++}
++++}
}|code-block|syntax|javascript|1165450|entityMap^0|0|9|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|P|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Q|8|@]|D|@]|E|$]]]|L|$]]

Swift 5.0:
In case someone needed an updated swift code:
<pre><code>private func callNumber(phoneNumber:String) {
 if let phoneCallURL:NSURL = NSURL(string: &quot;tel://\(phoneNumber)&quot;) {
 let application:UIApplication = UIApplication.shared
 if (application.canOpenURL(phoneCallURL as URL)) {
 if #available(iOS 10.0, *) {
 UIApplication.shared.open(phoneCallURL as URL)
 } else {
 UIApplication.shared.openURL(phoneCallURL as URL)
 }
 }
 }
}
</code></pre>

How can I dial a phone number that includes a number and access code programmatically in iOS?

For example:

<blockquote>
 number: 900-3440-567 
 Access Code: 65445
</blockquote>

Dial a phone number with an access code programmatically in iOS

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

文章

问答

视频

学习中心

腾讯云实验室

直播

竞赛

腾讯云代码分析专区

腾讯iOA零信任安全管理系统专区

腾讯云架构师技术同盟交流圈

腾讯云数据库专区

腾讯云顾问专区

腾讯云原生专区

腾讯混元专区

腾讯云TCE专区

腾讯云Lighthouse专区

腾讯云HAI专区

腾讯云Edgeone专区

腾讯云存储专区

腾讯云智能专区

腾讯轻联专区 

腾讯云开发专区

TAPD专区

腾讯轻量云游戏服专区

腾讯云最具价值专家

腾讯云架构师技术同盟

腾讯云创作之星

腾讯云开发者先锋

腾讯云代码助手

云原生构建

TAPD 敏捷项目管理

Cloud Studio

SDK中心

API中心

命令行工具

涵盖代码开发、场景应用、自动测试全流程，助你从零构建专属AI助手

一站式MCP教程库，解锁AI应用新玩法

如何拨一个在iOS中以编程方式包括一个号码和访问代码的电话号码？例如：编号: 900-3440-567接入代码: 65445

问以编程方式在iOS中拨打带有访问代码的电话号码
EN

社区

活动

圈层

关于

腾讯云开发者

热门产品

热门推荐

更多推荐

问以编程方式在iOS中拨打带有访问代码的电话号码EN

社区

活动

圈层

关于

腾讯云开发者

热门产品

热门推荐

更多推荐

问以编程方式在iOS中拨打带有访问代码的电话号码
EN