blocks|key|1207372|text|这是从Android游戏开始的。它创建一个简单的项目列表，您可以单击该列表来打开一个新活动。当然，每个列表项也必须添加到AndroidManifest.xml中，作为一个单独的具有.ListItem#名称的活动。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1207373|public+class+MainActivity+extends+ListActivity+{
String+tests[]+=+{+"ListItem1",
+++++++++++++++++++"ListItem2",
+++++++++++++++++++"ListItem3",
+++++++++++++++++++"ListItem4"};

public+void+onCreate(Bundle+savedInstanceState)+{
++++super.onCreate(savedInstanceState);
++++setListAdapter(new+ArrayAdapter<String>(this,+android.R.layout.simple_list_item_1,+tests));
}

@Override
protected+void+onListItemClick(ListView+list,+View+view,+int+position,+long+id)+{
++++super.onListItemClick(list,+view,+position,+id);
++++String+testName+=+tests[position];

++++try+{
++++++++Class<?>+classInstance+=+Class.forName("your.package.name."+%2B+testName);
++++++++Intent+intent+=+new+Intent(this,+classInstance);
++++++++startActivity(intent);
++++}+catch+(ClassNotFoundException+e)+{
++++++++e.printStackTrace();
++++}
}|code-block|syntax|javascript|1207374|}|1207375|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

This is from Begining Android Games. It creates a simple list of items which you can click to open a new activity. Each list item of course, would have to also be added to the AndroidManifest.xml as a separate activity with a .ListItem# name.

<pre><code>public class MainActivity extends ListActivity {
String tests[] = { "ListItem1",
 "ListItem2",
 "ListItem3",
 "ListItem4"};

public void onCreate(Bundle savedInstanceState) {
 super.onCreate(savedInstanceState);
 setListAdapter(new ArrayAdapter&lt;String&gt;(this, android.R.layout.simple_list_item_1, tests));
}

@Override
protected void onListItemClick(ListView list, View view, int position, long id) {
 super.onListItemClick(list, view, position, id);
 String testName = tests[position];

 try {
 Class&lt;?&gt; classInstance = Class.forName("your.package.name." + testName);
 Intent intent = new Intent(this, classInstance);
 startActivity(intent);
 } catch (ClassNotFoundException e) {
 e.printStackTrace();
 }
}
</code></pre>

}

blocks|key|3439657|text|performClick可能是在listview填充之前调用的，在getView和performItemClick中放置断点，然后首先调用检查。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3439658|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|D|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|E|8|@]|9|@]|A|$]]]|C|$]]

The performClick is probably called before listview was filled, put breakpoint in getView and on performItemClick and check wich is called first

blocks|key|1203690|text|我试过下面的代码，它成功了。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1203691|getListView().performItemClick(null,+0,+getListAdapter().getItemId(0));|code-block|syntax|javascript|1203692|第一个参数(视图)可以是null。|1203693|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

I tried the code below and it worked.

<pre><code>getListView().performItemClick(null, 0, getListAdapter().getItemId(0));
</code></pre>

The first parameter (view) can be null.

blocks|key|3439694|text|这对我有用。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3439695|listView.performItemClick(
++++listView.getAdapter().getView(position,+null,+null),+position,+position);|code-block|syntax|javascript|3439696|使用适配器获取项目位置的视图。另外两个参数我不想要，所以我让它们为空。保留convertView+null将导致适配器呈现一个新视图。这是一个性能问题，但由于这只是偶尔发生一次，它不会有多大的影响。我不需要为任何事情指定父级，因为我没有使用它。|3439697|位置只是你的物品所在的位置。此外，在您的performItemClick之前，这两行代码创建了选择列表项的错觉。它们还确保屏幕上有合适的项目。|3439698|listView.requestFocusFromTouch();
listView.setSelection(position);|3439699|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Q|8|@]|9|@]|A|$]]|$1|I|3|J|5|6|7|R|8|@]|9|@]|A|$]]|$1|K|3|L|5|D|7|S|8|@]|9|@]|A|$E|F]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

This worked for me. 

<pre><code>listView.performItemClick(
 listView.getAdapter().getView(position, null, null), position, position);
</code></pre>

use the adapter to get the view for the position of the item. The other 2 parameters I didn't want so I left them null. Leaving convertView null causes the adapter to render a new view. It's a performance issue but since this is only happening once in a while it wont have much effect. I don't need to specify the parent for anything because I'm not using it.

position is just the spot where your item is located.
Additionally these 2 lines of code before your performItemClick create the illusion of having the list item selected. They also ensure the appropriate item is on the screen.

<pre><code>listView.requestFocusFromTouch();
listView.setSelection(position);
</code></pre>

blocks|key|3439701|text|我和你一起去|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3439702|listView.getAdapter().getView(position,+null,+null).performClick();|code-block|syntax|javascript|3439703|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

I went with

<pre><code>listView.getAdapter().getView(position, null, null).performClick();
</code></pre>

blocks|key|3423955|text|getListView().performItemClick(null,+0,+0)为我(为0职位)做了个小把戏。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|3423956|entityMap^0|0|16|1A|1|0^^$0|@$1|2|3|4|5|6|7|H|8|@$9|I|A|J|B|C]|$9|K|A|L|B|C]]|D|@]|E|$]]|$1|F|3|-4|5|6|7|M|8|@]|D|@]|E|$]]]|G|$]]

<code>getListView().performItemClick(null, 0, 0)</code> did the trick for me (for position <code>0</code>).

blocks|key|3439742|text|mList.performItemClick(
++++++++mList.getAdapter().getView(mActivePosition,+null,+null),
++++++++mActivePosition,
++++++++mList.getAdapter().getItemId(mActivePosition));|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|3439743|在哪里mActivePosition是您的点击位置！祝你一切顺利！)|unstyled|3439744|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|J|8|@]|9|@]|A|$]]|$1|G|3|-4|5|F|7|K|8|@]|9|@]|A|$]]]|H|$]]

<pre><code>mList.performItemClick(
 mList.getAdapter().getView(mActivePosition, null, null),
 mActivePosition,
 mList.getAdapter().getItemId(mActivePosition));
</code></pre>

Where mActivePosition is your click position! 
All the best! :)

blocks|key|3439758|text|这对我来说是最好的。在主线程上运行这个。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3439759|new+Handler().post(new+Runnable()+{
++++@Override
++++public+void+run()+{
++++++++mList.performItemClick(
++++++++++++++++mList.getChildAt(mActivePosition),
++++++++++++++++mActivePosition,
++++++++++++++++mList.getAdapter().getItemId(mActivePosition));
++++}
});|code-block|syntax|javascript|3439760|这类似于Arun的回答，但它会将一条消息排队到主线程，以便给ListView一些启动时间。|offset|length|style|CODE|3439761|entityMap^0|0|0|U|8|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Q|8|@$I|R|J|S|K|L]]|9|@]|A|$]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

This works best for me. Run this on the main thread.

<pre><code>new Handler().post(new Runnable() {
 @Override
 public void run() {
 mList.performItemClick(
 mList.getChildAt(mActivePosition),
 mActivePosition,
 mList.getAdapter().getItemId(mActivePosition));
 }
});
</code></pre>

This is similar to Arun Jose's answer, but it will queue a message to the main thread to give the <code>ListView</code> some time to initiate.

blocks|key|1203765|text|使用提议的代码@sulal，如果使用onLoadFinished，则可以将其放置在LoaderManager中。例如：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1203766|@Override
public+void+onLoadFinished(Loader<Cursor>+loader,+Cursor+data)+{
++++//....
++++//+mSelectedId+keeps+the+currently+selected+id
++++//+INVID+is+an+invalid+value
++++if+(mSelectedId+==+INVID)+{+//+nothing+selected
++++++++//+sulal's+code
++++++++new+Handler().post(new+Runnable()+{
++++++++++++@Override
++++++++++++public+void+run()+{
++++++++++++++++mList.performItemClick(
++++++++++++++++++++++++mList.getChildAt(mActivePosition),
++++++++++++++++++++++++mActivePosition,
++++++++++++++++++++++++mList.getAdapter().getItemId(mActivePosition));
++++++++++++++++mSelectedId+=+mList.getAdapter().getItemId(mActivePosition);
++++++++++++}
++++++++});++++++++++++
++++}|code-block|syntax|javascript|1203767|mActivePosition可以是0(在第一项上的位置)，也可以是在onPause中保持的位置。|1203768|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

Using the code @sulal proposed, you may place it in onLoadFinished, if you use a LoaderManager. Eg something like

<pre><code>@Override
public void onLoadFinished(Loader&lt;Cursor&gt; loader, Cursor data) {
 //....
 // mSelectedId keeps the currently selected id
 // INVID is an invalid value
 if (mSelectedId == INVID) { // nothing selected
 // sulal's code
 new Handler().post(new Runnable() {
 @Override
 public void run() {
 mList.performItemClick(
 mList.getChildAt(mActivePosition),
 mActivePosition,
 mList.getAdapter().getItemId(mActivePosition));
 mSelectedId = mList.getAdapter().getItemId(mActivePosition);
 }
 }); 
 }
</code></pre>

mActivePosition may be 0 (ie position on the first item) or a position kept during eg onPause

blocks|key|1203770|text|首先，我尝试在我的片段中使用这段代码(Master/Detail+->+NameListFragment)|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1203771|getListView().performItemClick(null,+0,+getListView().getAdapter().getItemId(0));|code-block|syntax|javascript|1203772|​|1203773|但没起作用。当我在片段中执行@Override+onStart()方法时，我将代码移动到onStart()中。从那以后我就能正常工作了。|offset|length|style|CODE|1203774|entityMap^0|0|0|0|E|J|18|9|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|S|8|@]|9|@]|A|$]]|$1|I|3|J|5|6|7|T|8|@$K|U|L|V|M|N]|$K|W|L|X|M|N]]|9|@]|A|$]]|$1|O|3|-4|5|6|7|Y|8|@]|9|@]|A|$]]]|P|$]]

At Firstly I tried to use this code in my Fragment(Master/Detail -> NameListFragment)

<pre><code>getListView().performItemClick(null, 0, getListView().getAdapter().getItemId(0));
</code></pre>

 But it didn't work. When I did <code>@Override onStart()</code> method in fragment and I moved my code to <code>onStart()</code>. After that it works properly for me.

blocks|key|3439816|text|如果您正在处理单元测试用例。尝试使用getInstrumentation().waitForIdleSync()，等待加载列表，并扩展ActivityInstrumentationTestCase2+(参见此answer+)。|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|3439817|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/questions/18547077/testing-a-click-on-an-android-listview-with-activityunittestcase/23895650#23895650^0|2W|6|0|0^^$0|@$1|2|3|4|5|6|7|L|8|@]|9|@$A|M|B|N|1|O]]|C|$]]|$1|D|3|-4|5|6|7|P|8|@]|9|@]|C|$]]]|E|$F|$5|G|H|I|C|$J|K]]]]

If you are working on a unit test case.
Try to use getInstrumentation().waitForIdleSync(), to wait the list be loaded, and extend the ActivityInstrumentationTestCase2 
See this <a href="https://stackoverflow.com/questions/18547077/testing-a-click-on-an-android-listview-with-activityunittestcase/23895650#23895650">answer</a>.

blocks|key|3424071|text|这对我起了作用：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3424072|listView.getAdapter().getView(1,+null,+null).performClick();|code-block|syntax|javascript|3424073|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

This worked for me:

<pre><code>listView.getAdapter().getView(1, null, null).performClick();
</code></pre>

blocks|key|3439857|text|我今天遇到了这个怪人的问题，我尽我所能去处理它。我的条件是，当我第一次输入布局时，我需要检查一些项目。但是，当我使用gridView.getChildAt(位置)时，总是返回null。我以前遇到过这个问题，因为没有完成画图布局。所以我发了个帖子。handler.postDelayed(+..)，起作用了。谢谢你提出这个例外。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3439858|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|D|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|E|8|@]|9|@]|A|$]]]|C|$]]

I just meet this freak problem today , and I try me best to deal with it. 
 My condition is , when I first init the layout , I need make some item checked.
 But when I use gridView.getChildAt(position) , always return null. I met this problem before , caused by Not finishing drawing layout . So I send a post message . handler.postDelayed( .. , ..) , It works. Thanks who motion this Exception.

blocks|key|1203832|text|这可能是旧的，但这可能会有帮助：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1203833|lvList.performItemClick(null,+index,+lvList.getItemIdAtPosition(index)+);+|code-block|syntax|javascript|1203834|注意:第一个param是空的，并且仍然可以工作，如果您有一个自定义适配器，convertView将被填充自定义布局和视图等等。|1203835|-cheers+/快乐编码。|1203836|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|6|7|P|8|@]|9|@]|A|$]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

this may be old but this may help : 

<pre><code>lvList.performItemClick(null, index, lvList.getItemIdAtPosition(index) ); 
</code></pre>

NOTE : the first param is null and will still work, if you have a custom adapter, convertView will be filled with custom layout and view and such. 

-cheers / happy codings.

blocks|key|1207573|text|mList.performItemClick(
++++mList.getChildAt(mActivePosition),
++++mActivePosition,
++++mList.getAdapter().getItemId(mActivePosition));|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1207574|其中mActivePosition是列表视图中子视图的位置。|unstyled|offset|length|style|CODE|1207575|entityMap^0|0|2|F|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|N|8|@$G|O|H|P|I|J]]|9|@]|A|$]]|$1|K|3|-4|5|F|7|Q|8|@]|9|@]|A|$]]]|L|$]]

<pre><code>mList.performItemClick(
 mList.getChildAt(mActivePosition),
 mActivePosition,
 mList.getAdapter().getItemId(mActivePosition));
</code></pre>

where <code>mActivePosition</code> is the position of the child view in List View.

blocks|key|3424226|text|放弃了一些经验，。|type|unstyled|depth|inlineStyleRanges|offset|length|style|BOLD|entityRanges|data|3424227|如果在代码中使用具有相同listview的监听器，那么使用listview1.testItemClickListener也会触发listview1.OnItemClickListener。|3424228|Hope+It+helps++|code-block|syntax|javascript|3424229|entityMap^0|0|8|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@$9|P|A|Q|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|R|8|@]|D|@]|E|$]]|$1|H|3|I|5|J|7|S|8|@]|D|@]|E|$K|L]]|$1|M|3|-4|5|6|7|T|8|@]|D|@]|E|$]]]|N|$]]

Dropping Some Experience.
using listview1.performItemClick, will also trigger your listview1.OnItemClickListener if you are using the listener with same listview in your code.
<pre><code>Hope It helps 
</code></pre>

blocks|key|3439994|text|如果在使用getView时会得到奇怪的结果，这是因为您想要的列表项在可见部分中不存在。使用如下：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|3439995|private+View+getViewFromAdapterByPosition(int+position,+ListView+listView)+
{
++++++++View+view;
++++++++int+firstVisiblePos+=+listView.getFirstVisiblePosition();
++++++++int+lastVisiblePos+=+listView.getLastVisiblePosition();

++++++++if+(position+<+firstVisiblePos+%7C%7C+position+>+lastVisiblePos)+{
++++++++++++view+=+listView.getAdapter().getView(position,+null,+listView);
++++++++}+else+{
++++++++++++view+=+listView.getChildAt(position+-+firstVisiblePos);
++++++++}
++++++++return+view;
++++}|code-block|syntax|javascript|3439996|然后,|3439997|listView.performItemClick(getViewFromAdapterByPosition(index,+listView),+index,+0);|3439998|entityMap^0|5|7|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@$9|R|A|S|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|T|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|U|8|@]|D|@]|E|$]]|$1|M|3|N|5|H|7|V|8|@]|D|@]|E|$I|J]]|$1|O|3|-4|5|6|7|W|8|@]|D|@]|E|$]]]|P|$]]

If you would get weird result when using <code>getView</code>, this is because the list item you want does not exist within visible parts. Use below:

<pre><code>private View getViewFromAdapterByPosition(int position, ListView listView) 
{
 View view;
 int firstVisiblePos = listView.getFirstVisiblePosition();
 int lastVisiblePos = listView.getLastVisiblePosition();

 if (position &lt; firstVisiblePos || position &gt; lastVisiblePos) {
 view = listView.getAdapter().getView(position, null, listView);
 } else {
 view = listView.getChildAt(position - firstVisiblePos);
 }
 return view;
 }
</code></pre>

And then,

<pre><code>listView.performItemClick(getViewFromAdapterByPosition(index, listView), index, 0);
</code></pre>

blocks|key|1203859|text|如果在使用时会得到奇怪的结果，请为我做，这是因为您想要的列表项在可见的部分中不存在。使用如下：|type|unstyled|depth|inlineStyleRanges|offset|length|style|BOLD|entityRanges|data|1203860|private+View+getViewFromAdapterByPosition(int+position,+ListView+listView)+
{
++++++++View+view;
++++++++int+firstVisiblePos+=+listView.getFirstVisiblePosition();
++++++++int+lastVisiblePos+=+listView.getLastVisiblePosition();

++++++++if+(position+<+firstVisiblePos+%7C%7C+position+>+lastVisiblePos)+{
++++++++++++view+=+listView.getAdapter().getView(position,+null,+listView);
++++++++}+else+{
++++++++++++view+=+listView.getChildAt(position+-+firstVisiblePos);
++++++++}
++++++++return+view;
++++}|code-block|syntax|javascript|1203861|然后,|1203862|listView.performItemClick(getViewFromAdapterByPosition(index,+listView),+index,+0);|1203863|entityMap^0|5|E|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@$9|R|A|S|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|T|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|U|8|@]|D|@]|E|$]]|$1|M|3|N|5|H|7|V|8|@]|D|@]|E|$I|J]]|$1|O|3|-4|5|6|7|W|8|@]|D|@]|E|$]]]|P|$]]

This work for me 
If you would get weird result when using getView, this is because the list item you want does not exist within visible parts. Use below:

<pre><code>private View getViewFromAdapterByPosition(int position, ListView listView) 
{
 View view;
 int firstVisiblePos = listView.getFirstVisiblePosition();
 int lastVisiblePos = listView.getLastVisiblePosition();

 if (position &lt; firstVisiblePos || position &gt; lastVisiblePos) {
 view = listView.getAdapter().getView(position, null, listView);
 } else {
 view = listView.getChildAt(position - firstVisiblePos);
 }
 return view;
 }
</code></pre>

And then,

<pre><code>listView.performItemClick(getViewFromAdapterByPosition(index, listView), index, 0);
</code></pre>

blocks|key|1207610|text|当使用Listview+(简单数组适配器或自定义适配器)时，定义listview和其他最终执行单击。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1207611|例如：|1207612|+//At+onCreate+function:

lv+=+(ListView)+findViewById(R.id.listView);
++++++++lv.setAdapter(new+CustomAdapter(List_item.this,+list,+images));


lv.setOnItemClickListener(new+AdapterView.OnItemClickListener()+{
++++++++++++@Override
++++++++++++public+void+onItemClick(AdapterView<?>+parent,+View+view,+int+position,+long+id)++++{
//+on+click+function+works
++++}
}


int+position+=+0;
lv.performItemClick(lv.getAdapter().getView(position,+null,+null),+position,+lv.getAdapter().getItemId(position));|code-block|syntax|javascript|1207613|注意:创建setOnItemClickListener之后，您应该调用perform。否则，它将不正确。|1207614|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|N|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|O|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|6|7|P|8|@]|9|@]|A|$]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

When using Listview (simple array adapter or custom adapter) define listview and other finally make perform click.

For example:

<pre><code> //At onCreate function:

lv = (ListView) findViewById(R.id.listView);
 lv.setAdapter(new CustomAdapter(List_item.this, list, images));


lv.setOnItemClickListener(new AdapterView.OnItemClickListener() {
 @Override
 public void onItemClick(AdapterView&lt;?&gt; parent, View view, int position, long id) {
// on click function works
 }
}


int position = 0;
lv.performItemClick(lv.getAdapter().getView(position, null, null), position, lv.getAdapter().getItemId(position));
</code></pre>

Note: After creating the setOnItemClickListener only you should call
perform click. Otherwise, it will not correctly.

blocks|key|1203879|text|这对我来说很管用：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1203880|listview.getSelectedView().performClick();|code-block|syntax|javascript|1203881|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

This works for me:

<pre><code>listview.getSelectedView().performClick();
</code></pre>

blocks|key|3424279|text|试试这个：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3424280|public+static+boolean+performClicKOnLisViewFromIndex(ListView+listView,+int+index){
++++++++if(listView+!=+null){
++++++++++++if(listView.getAdapter()!=+null+&&+listView.getAdapter().getCount()+>0+&&+listView.getAdapter().getCount()+>+index+){
++++++++++++++++listView.performItemClick(
++++++++++++++++++++++++listView.getAdapter().getView(index,+null,+null),
++++++++++++++++++++++++index,+listView.getItemIdAtPosition(index));
++++++++++++++++return+true;
++++++++++++}
++++++++}
++++++++return++false;
++++}|code-block|syntax|javascript|3424281|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Try this one:

<pre><code>public static boolean performClicKOnLisViewFromIndex(ListView listView, int index){
 if(listView != null){
 if(listView.getAdapter()!= null &amp;&amp; listView.getAdapter().getCount() &gt;0 &amp;&amp; listView.getAdapter().getCount() &gt; index ){
 listView.performItemClick(
 listView.getAdapter().getView(index, null, null),
 index, listView.getItemIdAtPosition(index));
 return true;
 }
 }
 return false;
 }
</code></pre>

blocks|key|3440064|text|myListView.getChildAt(0)返回null，因为它很快就使用了。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|3440065|用延迟来处理。|3440066|或使用以下代码：|3440067|private+class+MyAdapter+extends+BaseAdapter
{
private+final+Context+context;
private+HashMap<Integer,+View>+views;

public+MyAdapter(Context+context)
{
++++this.context+=+context;
++++views+=+new+HashMap<>();
}

@Override
public+View+getView(int+position,+View+convertView,+ViewGroup+parent)
{
++++if(convertView+==+null)
++++{
++++++++if(views.get(position)+==+null)
++++++++{
++++++++++++final+LayoutInflater+layoutInflater+=+LayoutInflater.from(context);
++++++++++++convertView+=+layoutInflater.inflate(R.layout.my_grid,+null,+false);

++++++++++++views.put(position,+convertView);
++++++++}
++++++++else
++++++++++++convertView+=+views.get(position);
++++}

++++TextView+tv+=+convertView.findViewById(R.id.langView);
++++tv.setText(languageList.get(position));

++++return+convertView;
}
}|code-block|syntax|javascript|3440068|和|3440069|adapter+=+new+MyAdapter(getActivity());
myListView.setAdapter(adapter);

Runnable+r+=+new+Runnable()
{
++++@Override
++++public+void+run()
++++{
++++++++myListView.performItemClick(adapter.getView(position,+null,+myListView),+position,+0);
++++}
};

myListView.postDelayed(r,+100);|3440070|entityMap^0|0|O|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@$9|V|A|W|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|X|8|@]|D|@]|E|$]]|$1|H|3|I|5|6|7|Y|8|@]|D|@]|E|$]]|$1|J|3|K|5|L|7|Z|8|@]|D|@]|E|$M|N]]|$1|O|3|P|5|6|7|10|8|@]|D|@]|E|$]]|$1|Q|3|R|5|L|7|11|8|@]|D|@]|E|$M|N]]|$1|S|3|-4|5|6|7|12|8|@]|D|@]|E|$]]]|T|$]]

<code>myListView.getChildAt(0)</code> returns null because used this very soon.

use a delay for it.

or use below code:

<pre><code>private class MyAdapter extends BaseAdapter
{
private final Context context;
private HashMap&lt;Integer, View&gt; views;

public MyAdapter(Context context)
{
 this.context = context;
 views = new HashMap&lt;&gt;();
}

@Override
public View getView(int position, View convertView, ViewGroup parent)
{
 if(convertView == null)
 {
 if(views.get(position) == null)
 {
 final LayoutInflater layoutInflater = LayoutInflater.from(context);
 convertView = layoutInflater.inflate(R.layout.my_grid, null, false);

 views.put(position, convertView);
 }
 else
 convertView = views.get(position);
 }

 TextView tv = convertView.findViewById(R.id.langView);
 tv.setText(languageList.get(position));

 return convertView;
}
}
</code></pre>

and

<pre><code>adapter = new MyAdapter(getActivity());
myListView.setAdapter(adapter);

Runnable r = new Runnable()
{
 @Override
 public void run()
 {
 myListView.performItemClick(adapter.getView(position, null, myListView), position, 0);
 }
};

myListView.postDelayed(r, 100);
</code></pre>

blocks|key|3440088|text|只要使用performItemClick()就行了。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|3440089|listView.performItemClick(listView.getAdapter().getView(listView.getSelectedItemId,+null,+null),+listView.getSelectedItemId,+listView.getAdapter().getItemId(listView.getSelectedItemId));|code-block|syntax|javascript|3440090|entityMap^0|4|I|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|P|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Q|8|@]|D|@]|E|$]]]|L|$]]

just should use <code>performItemClick()</code> and it's okay.

<pre><code>listView.performItemClick(listView.getAdapter().getView(listView.getSelectedItemId, null, null), listView.getSelectedItemId, listView.getAdapter().getItemId(listView.getSelectedItemId));
</code></pre>

blocks|key|1207648|text|在我的例子中，没有一个选项解决了我的问题，所以我在我的CursorAdapter类中做了一个调整。我在作用域中定义了一个全局变量，所以我只需要调用更改这个值的类，并通过传递位置值来检查光标的位置。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1207649|+mProductsAdapter.currentPosition+=+requiredPosition|code-block|syntax|javascript|1207650|在我的ProductsAdapter生成器中|1207651|++var+currentPosition+=+0|1207652|在bindView中，我做检查|1207653|+if+(cursor.position+==+currentPosition)+{
//+perform+action
}|1207654|entityMap^0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|S|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|U|8|@]|9|@]|A|$]]|$1|M|3|N|5|D|7|V|8|@]|9|@]|A|$E|F]]|$1|O|3|-4|5|6|7|W|8|@]|9|@]|A|$]]]|P|$]]

In my case, none of the options solved my problem, so I made an adaptation in my CursorAdapter class.
I defined a global variable in the scope, so I just call the class changing this value and check the cursor position by passing the position value
<pre><code> mProductsAdapter.currentPosition = requiredPosition
</code></pre>
in my ProductsAdapter builder
<pre><code> var currentPosition = 0
</code></pre>
in bindView I do the check
<pre><code> if (cursor.position == currentPosition) {
// perform action
}
</code></pre>

I'm facing some difficults when I try to use the performItemClick funcion of the ListView.

All I want to do is to perform a click programatically in the first item of the list.

How can I do that? I looked up that function in the documentation, but I didn't really understand its parameters.

I tried something like:

<pre><code> myListView.performItemClick(myListView.getChildAt(0), 0, myListView.getChildAt(0).getId());
</code></pre>

But it didn't work <code>(myListView.getChildAt(0) returns null)</code>

Thank you in advance!

Android - ListView - performItemClick

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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当我尝试使用performItemClick的ListView功能时，我面临着一些困难。我所要做的就是在列表的第一项中以编程方式执行单击。我怎么能这么做？我在文档中查找了这个函数，但是我并不真正理解它的参数。我试过这样的方法： myListView.performItemClick(myListView.getChil...

问安卓- ListView - performItemClick
EN

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