blocks|key|188047|text|检查解压缩任务。|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|188048|entityMap|0|LINK|mutability|MUTABLE|url|http://ant.apache.org/manual/Tasks/unzip.html^0|2|5|0|0^^$0|@$1|2|3|4|5|6|7|L|8|@]|9|@$A|M|B|N|1|O]]|C|$]]|$1|D|3|-4|5|6|7|P|8|@]|9|@]|C|$]]]|E|$F|$5|G|H|I|C|$J|K]]]]

Check <a href="http://ant.apache.org/manual/Tasks/unzip.html" rel="nofollow">Unzip Task</a>.

blocks|key|2226555|text|尝试"zip“而不是"jar"：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2226556|<property+url="zip:file:/D:/testing.zip!/testing/ant-contrib.jar"+/>|offset|length|style|CODE|2226557|entityMap^0|0|0|1W|0^^$0|@$1|2|3|4|5|6|7|J|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|K|8|@$D|L|E|M|F|G]]|9|@]|A|$]]|$1|H|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|I|$]]

try "zip" instead of "jar":

<code>&lt;property url="zip:file:/D:/testing.zip!/testing/ant-contrib.jar" /&gt;</code>

blocks|key|403905|text|property标记用于包含属性，属性将位于属性文件中。jar文件不是属性文件。财产文档非常清楚。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|403906|您需要将该文件添加到类路径中，然后将其实际添加到类路径中:请参阅解拉链文档。不过，这不只是一种财产。|403907|entityMap|0|LINK|mutability|MUTABLE|url|http://ant.apache.org/manual/Tasks/property.html|1|http://ant.apache.org/manual/Tasks/unzip.html^0|0|8|14|4|0|0|W|3|1|0^^$0|@$1|2|3|4|5|6|7|R|8|@$9|S|A|T|B|C]]|D|@$9|U|A|V|1|W]]|E|$]]|$1|F|3|G|5|6|7|X|8|@]|D|@$9|Y|A|Z|1|10]]|E|$]]|$1|H|3|-4|5|6|7|11|8|@]|D|@]|E|$]]]|I|$J|$5|K|L|M|E|$N|O]]|P|$5|K|L|M|E|$N|Q]]]]

The <code>property</code> tag is for including properties, which would be in a property file. A jar file isn't a property file. The <a href="http://ant.apache.org/manual/Tasks/property.html" rel="nofollow">property docs</a> are pretty clear. 

You need to <a href="http://ant.apache.org/manual/Tasks/unzip.html" rel="nofollow">unzip</a> the file in order to add it to a classpath, and then actually add it to a classpath: see the <a href="http://ant.apache.org/manual/using.html#path" rel="nofollow">path-like structures</a> documentation. It's not just a property, though.

blocks|key|403933|text|不完全确定您在做什么，但是URL总是有两个正斜杠作为分隔符。例如，在Subversion中，您会执行file://D:/testing.zip!/testing/ant-contrib.jar。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|403934|现在，<property>任务中的URL规范应该指向一个javaspec‘s属性文件，所以我认为jar不能工作。|403935|我可以告诉您的是，Java是编写的，这样它就可以读取zip和jars中的文件，而无需首先解压缩它们。如果您将testing.zip解压缩到一个名为testing.zip的目录中并从那里访问文件，或者将其保存为you文件，那么Java就没有什么区别了。您应该能够将其包含在路径名称(sans感叹号)中：|403936|<path+id="classpath>
++++<pathelement+path="D:/testing.zip/testing/ant-contrib.jar"/>
++++<yadda,+yadda,+yadda/>
</path>|code-block|syntax|javascript|403937|那应该管用。|403938|您可以尝试的是将testing.zip解压缩到同名目录中，并查看是否可以访问ant-contrib.jar中的文件。然后，尝试压缩testing.zip，看看是否有什么不同。不应该有。|403939|entityMap|0|LINK|mutability|MUTABLE|url|http://docs.oracle.com/javase/7/docs/api/java/util/Properties.html#load%2528java.io.Reader%2529^0|1E|1A|0|3|A|S|E|0|0|1I|B|21|B|0|0|0|12|F|0^^$0|@$1|2|3|4|5|6|7|10|8|@$9|11|A|12|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|13|8|@$9|14|A|15|B|C]]|D|@$9|16|A|17|1|18]]|E|$]]|$1|H|3|I|5|6|7|19|8|@$9|1A|A|1B|B|C]|$9|1C|A|1D|B|C]]|D|@]|E|$]]|$1|J|3|K|5|L|7|1E|8|@]|D|@]|E|$M|N]]|$1|O|3|P|5|6|7|1F|8|@]|D|@]|E|$]]|$1|Q|3|R|5|6|7|1G|8|@$9|1H|A|1I|B|C]]|D|@]|E|$]]|$1|S|3|-4|5|6|7|1J|8|@]|D|@]|E|$]]]|T|$U|$5|V|W|X|E|$Y|Z]]]]

Not entirely sure what you're doing, but URLs always have two forward slashes as a delimiter. For example, in Subversion you'd do <code>file://D:/testing.zip!/testing/ant-contrib.jar</code>.

Now a URL spec in a <code>&lt;property&gt;</code> task should point to a <a href="http://docs.oracle.com/javase/7/docs/api/java/util/Properties.html#load%28java.io.Reader%29" rel="nofollow">javaspec'd property file</a>, so I don't think a jar will work.

What I can tell you is that Java is written so that it can read files inside zips and jars without first unzipping them. There should be no difference in Java if you unzipped <code>testing.zip</code> into a directory called <code>testing.zip</code> and accessed files from there, or kept it as a zipfile. You should be able to include it in the path name (sans exclamation point):

<pre><code>&lt;path id="classpath&gt;
 &lt;pathelement path="D:/testing.zip/testing/ant-contrib.jar"/&gt;
 &lt;yadda, yadda, yadda/&gt;
&lt;/path&gt;
</code></pre>

That should work.

What you can try is to unzip testing.zip into a directory of the same name, and see if you can access the files in <code>ant-contrib.jar</code>. Then, try zipping up testing.zip and see if there's any difference. There shouldn't be.

I want to include a jar file (ant-contrib.jar) in my ant build.xml from within a zip. 
How can i do that without unzipping the zip file.
I have tried to use the jarURLConnect.

<pre><code>&lt;property url="jar:file:/D:/testing.zip!/testing/ant-contrib.jar" /&gt;
</code></pre>

But this gives me a 

<blockquote>
 java.lang.IllegalArgumentException: Malformed \uxxxx encoding.
</blockquote>

There is no error if I replace "ant-contrib.jar" with a "test.properties" file.

Can anybody please help..

Ant - Import jar from within a zip file

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我想从zip中将一个jar文件(ant-contrib.jar)包含在我的ant build.xml中。我如何做到这一点，而不解压缩的压缩文件。我试过使用jarURLConnect。<property url="jar:file:/D:/testing.zip!/testing/ant-contrib.jar" />但...

问从zip文件中导入jar
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