blocks|key|250214|text|从手册页：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|250215|+++-f+file
++++++++++True+if+file+exists+and+is+a+regular+file.|code-block|syntax|javascript|250216|所以：|250217|if+[+-f+someFileName+];+then+echo+'Found+some!';+fi|250218|编辑:我看到你已经得到了答案，但是为了完整，你可以使用Checking+from+shell+script+if+a+directory+contains+files中的信息-如果你想要忽略隐藏的文件，就会失去dotglob选项。|offset|length|250219|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/questions/91368/checking-if-a-directory-contains-files^0|0|0|0|0|R|1K|0|0^^$0|@$1|2|3|4|5|6|7|W|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|X|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Y|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|Z|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|10|8|@]|9|@$M|11|N|12|1|13]]|A|$]]|$1|O|3|-4|5|6|7|14|8|@]|9|@]|A|$]]]|P|$Q|$5|R|S|T|A|$U|V]]]]

From the man page:

<pre><code> -f file
 True if file exists and is a regular file.
</code></pre>

So:

<pre><code>if [ -f someFileName ]; then echo 'Found some!'; fi
</code></pre>

Edit: I see you already got the answer, but for completeness, you can use the info in <a href="https://stackoverflow.com/questions/91368/checking-if-a-directory-contains-files">Checking from shell script if a directory contains files</a> - and lose the dotglob option if you want hidden files ignored.

blocks|key|250242|text|尝尝这个|type|unstyled|depth|inlineStyleRanges|entityRanges|data|250243|if+[+-f+/tmp/foo.txt+]
then
++++echo+the+file+exists
fi|code-block|syntax|javascript|250244|参考文献：http://tldp.org/LDP/abs/html/fto.html|offset|length|250245|您可能还想检查一下：http://tldp.org/LDP/abs/html/fto.html|250246|这对于目录是否为空有何影响？|250247|$+find+"/tmp"+-type+f+-exec+echo+Found+file+{}+\;|250248|entityMap|0|LINK|mutability|MUTABLE|url|http://tldp.org/LDP/abs/html/fto.html|1^0|0|0|5|11|0|0|A|11|1|0|0|0^^$0|@$1|2|3|4|5|6|7|Z|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|10|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|11|8|@]|9|@$I|12|J|13|1|14]]|A|$]]|$1|K|3|L|5|6|7|15|8|@]|9|@$I|16|J|17|1|18]]|A|$]]|$1|M|3|N|5|6|7|19|8|@]|9|@]|A|$]]|$1|O|3|P|5|D|7|1A|8|@]|9|@]|A|$E|F]]|$1|Q|3|-4|5|6|7|1B|8|@]|9|@]|A|$]]]|R|$S|$5|T|U|V|A|$W|X]]|Y|$5|T|U|V|A|$W|X]]]]

Try this 

<pre><code>if [ -f /tmp/foo.txt ]
then
 echo the file exists
fi
</code></pre>

ref: <a href="http://tldp.org/LDP/abs/html/fto.html" rel="nofollow">http://tldp.org/LDP/abs/html/fto.html</a>

you may also want to check this out: <a href="http://tldp.org/LDP/abs/html/fto.html" rel="nofollow">http://tldp.org/LDP/abs/html/fto.html</a>

How about this for whether directory is empty or not

<pre><code>$ find "/tmp" -type f -exec echo Found file {} \;
</code></pre>

blocks|key|1607827|text|我通常只使用一个廉价的ls+-A来查看是否有响应。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1607828|伪-也许-正确-语法-示例-ahoy：|1607829|if+[[+$(ls+-A+my_directory_path_variable+)+]]+then....|code-block|syntax|javascript|1607830|编辑，这将工作：|1607831|myDir=(./*)+if+[+${#myDir[@]}+-gt+1+];+then+echo+"there's+something+down+here";+fi|offset|length|style|CODE|1607832|entityMap^0|0|0|0|0|0|2A|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|T|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|U|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|6|7|V|8|@]|9|@]|A|$]]|$1|K|3|L|5|6|7|W|8|@$M|X|N|Y|O|P]]|9|@]|A|$]]|$1|Q|3|-4|5|6|7|Z|8|@]|9|@]|A|$]]]|R|$]]

I typically just use a cheap ls -A to see if there's a response. 

Pseudo-maybe-correct-syntax-example-ahoy:

<pre><code>if [[ $(ls -A my_directory_path_variable ) ]] then....
</code></pre>

edit, this will work:

<code>myDir=(./*) if [ ${#myDir[@]} -gt 1 ]; then echo "there's something down here"; fi</code>

blocks|key|1607838|text|#!/bin/bash

if+[+-e+$1+];+then
++++++++echo+"File+exists"
else+
+++++++echo+"Files+does+not+exist"
fi+|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1607839|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>#!/bin/bash

if [ -e $1 ]; then
 echo "File exists"
else 
 echo "Files does not exist"
fi 
</code></pre>

blocks|key|219282|text|因此，可以在ls语句中使用if：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|219283|if+[[+"$(ls+-a1+%7C+egrep+-v+'%5E\.$%7C%5E\.\.$')"+=+""+]]+;+then+echo+empty+;+fi|code-block|syntax|javascript|219284|或者，多亏了池伽米|219285|if+[[+"$(ls+-A)"+=+""+]]+;+then+echo+empty+;+fi|219286|或者，甚至更短：|219287|if+[[+-z+"$(ls+-A)"+]]+;+then+echo+empty+;+fi|219288|这些文件基本上列出了当前目录中既不是.也不是..的所有文件(包括隐藏的文件)。|219289|如果该列表为空，则该目录为空。|219290|如果要对隐藏文件进行折扣，可以将其简化为：|219291|if+[[+"$(ls)"+=+""+]]+;+then+echo+empty+;+fi|219292|219293|bash-only解决方案(不调用ls或egrep之类的外部程序)可以执行以下操作：|219294|emp=Y;+for+i+in+*;+do+if+[[+$i+!=+"*"+]];+then+emp=N;+break;+fi;+done;+echo+$emp|219295|它不是世界上最漂亮的代码，它只是将emp设置为Y，然后，对于每个真正的文件，将其设置为N，并从for循环中分离出来以提高效率。如果有零个文件，它将保留为Y。|219296|entityMap^0|6|2|D|2|0|0|0|0|0|0|I|1|M|2|0|0|0|0|0|0|4|H|2|K|5|0|0|H|3|N|1|17|1|1B|3|24|1|0^^$0|@$1|2|3|4|5|6|7|19|8|@$9|1A|A|1B|B|C]|$9|1C|A|1D|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|1E|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|1F|8|@]|D|@]|E|$]]|$1|M|3|N|5|H|7|1G|8|@]|D|@]|E|$I|J]]|$1|O|3|P|5|6|7|1H|8|@]|D|@]|E|$]]|$1|Q|3|R|5|H|7|1I|8|@]|D|@]|E|$I|J]]|$1|S|3|T|5|6|7|1J|8|@$9|1K|A|1L|B|C]|$9|1M|A|1N|B|C]]|D|@]|E|$]]|$1|U|3|V|5|6|7|1O|8|@]|D|@]|E|$]]|$1|W|3|X|5|6|7|1P|8|@]|D|@]|E|$]]|$1|Y|3|Z|5|H|7|1Q|8|@]|D|@]|E|$I|J]]|$1|10|3|-4|5|6|7|1R|8|@]|D|@]|E|$]]|$1|11|3|12|5|6|7|1S|8|@$9|1T|A|1U|B|C]|$9|1V|A|1W|B|C]|$9|1X|A|1Y|B|C]]|D|@]|E|$]]|$1|13|3|14|5|H|7|1Z|8|@]|D|@]|E|$I|J]]|$1|15|3|16|5|6|7|20|8|@$9|21|A|22|B|C]|$9|23|A|24|B|C]|$9|25|A|26|B|C]|$9|27|A|28|B|C]|$9|29|A|2A|B|C]]|D|@]|E|$]]|$1|17|3|-4|5|6|7|2B|8|@]|D|@]|E|$]]]|18|$]]

You can use <code>ls</code> in an <code>if</code> statement thus:

<pre><code>if [[ "$(ls -a1 | egrep -v '^\.$|^\.\.$')" = "" ]] ; then echo empty ; fi
</code></pre>

or, thanks to ikegami,

<pre><code>if [[ "$(ls -A)" = "" ]] ; then echo empty ; fi
</code></pre>

or, even shorter:

<pre><code>if [[ -z "$(ls -A)" ]] ; then echo empty ; fi
</code></pre>

These basically list all files in the current directory (including hidden ones) that are neither <code>.</code> nor <code>..</code>.

If that list is empty, then the directory is empty.

If you want to discount hidden files, you can simplify it to:

<pre><code>if [[ "$(ls)" = "" ]] ; then echo empty ; fi
</code></pre>

<hr>

A <code>bash</code>-only solution (no invoking external programs like <code>ls</code> or <code>egrep</code>) can be done as follows:

<pre><code>emp=Y; for i in *; do if [[ $i != "*" ]]; then emp=N; break; fi; done; echo $emp
</code></pre>

It's not the prettiest code in the world, it simply sets <code>emp</code> to <code>Y</code> and then, for every real file, sets it to <code>N</code> and breaks from the <code>for</code> loop for efficiency. If there were zero files, it stays as <code>Y</code>.

blocks|key|1607861|text|我没有一个很好的纯sh/bash解决方案，但是在Perl中很容易做到：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1607862|#!/usr/bin/perl

use+strict;
use+warnings;

die+"Usage:+$0+dir\n"+if+scalar+@ARGV+!=+1+or+not+-d+$ARGV[0];
opendir+my+$DIR,+$ARGV[0]+or+die+"$ARGV[0]:+$!\n";
my+@files+=+readdir+$DIR;
closedir+$DIR;
if+(scalar+@files+==+2)+{+#+.+and+..
++++exit+0;
}
else+{
++++exit+1;
}|code-block|syntax|javascript|1607863|将其称为emptydir，并将其放在$PATH中的某个位置，然后：|offset|length|style|CODE|1607864|if+emptydir+dir+;+then
++++echo+"dir+is+empty"
else
++++echo+"dir+is+not+empty"
fi|1607865|如果您没有给出参数、两个或多个参数，或者一个不是目录的参数，那么它就会随错误消息而消失；如果您喜欢不同的行为，就很容易更改它。|1607866|entityMap^0|0|0|4|8|I|5|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|U|8|@$I|V|J|W|K|L]|$I|X|J|Y|K|L]]|9|@]|A|$]]|$1|M|3|N|5|D|7|Z|8|@]|9|@]|A|$E|F]]|$1|O|3|P|5|6|7|10|8|@]|9|@]|A|$]]|$1|Q|3|-4|5|6|7|11|8|@]|9|@]|A|$]]]|R|$]]

I don't have a good pure sh/bash solution, but it's easy to do in Perl:

<pre><code>#!/usr/bin/perl

use strict;
use warnings;

die "Usage: $0 dir\n" if scalar @ARGV != 1 or not -d $ARGV[0];
opendir my $DIR, $ARGV[0] or die "$ARGV[0]: $!\n";
my @files = readdir $DIR;
closedir $DIR;
if (scalar @files == 2) { # . and ..
 exit 0;
}
else {
 exit 1;
}
</code></pre>

Call it something like <code>emptydir</code> and put it somewhere in your <code>$PATH</code>, then:

<pre><code>if emptydir dir ; then
 echo "dir is empty"
else
 echo "dir is not empty"
fi
</code></pre>

It dies with an error message if you give it no arguments, two or more arguments, or an argument that isn't a directory; it's easy enough to change if you prefer different behavior.

blocks|key|219335|text|为了好玩：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|219336|if+(+shopt+-s+nullglob+;+perl+-e'exit+!@ARGV'+./*+)+;+then
+++echo+'Found+some!'
fi|code-block|syntax|javascript|219337|(不检查隐藏文件)|219338|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

For fun:

<pre><code>if ( shopt -s nullglob ; perl -e'exit !@ARGV' ./* ) ; then
 echo 'Found some!'
fi
</code></pre>

(Doesn't check for hidden files)

blocks|key|250397|text|#+tested+on+Linux+BASH

directory=$1

if+test+$(stat+-c+%25h+$directory)+-gt+2;
then
+++echo+"not+empty"
else
+++echo+"empty"
fi|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|250398|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code># tested on Linux BASH

directory=$1

if test $(stat -c %h $directory) -gt 2;
then
 echo "not empty"
else
 echo "empty"
fi
</code></pre>

How does one test for the existence of files in a directory using <code>bash</code>?

<pre><code>if ... ; then
 echo 'Found some!'
fi
</code></pre>

To be clear, I don't want to test for the existence of a specific file. I would like to test if a specific directory contains any files.

<hr>

I went with:

<pre><code>(
 shopt -s dotglob nullglob
 existing_files=( ./* )
 if [[ ${#existing_files[@]} -gt 0 ]] ; then
 some_command "${existing_files[@]}"
 fi
)
</code></pre>

Using the array avoids race conditions from reading the file list twice.

sh: Test for existence of files

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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如何使用bash测试目录中文件的存在if ... ; then   echo 'Found some!'fi为了明确起见，我不想测试是否存在特定的文件。我想测试一个特定的目录是否包含任何文件。我跟着：(   shopt -s dotglob nullglob   existing_files=( ./* )   if ...

问sh:测试文件是否存在
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问sh:测试文件是否存在EN