blocks|key|3125366|text|它可能失败的原因之一是您的业务规则是“至少6个字符”，但是regex强制执行的正是6个字符。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3125367|另外:这会很有帮助的，你说了哪些条件失败了。我表面上的测试表明你很好，除了我上面提到的警告。如果你能把你的问题弄清楚，指出我没有想到的非表面测试失败了，那将是有帮助的。|3125368|在现实世界中，我也希望你认为哪些标点符号是有效的。你的名单有点短。但这与你目前的问题无关。|3125369|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|H|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|I|8|@]|9|@]|A|$]]|$1|D|3|E|5|6|7|J|8|@]|9|@]|A|$]]|$1|F|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|G|$]]

One reason why it might be failing is your business rule is "at least six characters", but your regex enforces exactly six characters.

Also: it'd be helpful it you stated which conditions it fails on. My superficial testing suggests you're fine except for the caveat I mention above. If you could finetune your question to point out what non-superficial testing that I'm not thinking about is failing, that'd be helpful.

In the real world, I'd also expect what punctuation characters you consider valid, too. Your list is a bit short. But that's nowt to do with you current problem.

blocks|key|2269022|text|尝尝这个。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2269023|%5E(？=.A-Z)(？=.！@##\$&_)(？=.0-9)(？=.*a-z).{6，}$|2269024|在6后面添加逗号，因为您希望允许超过6个字符，$必须用\$转义|2269025|更新|offset|length|style|BOLD|2269026|在下面尝试，%5E和$从上面移除|2269027|(？=.A-Z)(？=.！@##$&_)(？=.0-9)(？=.*a-z).{6，}|2269028|entityMap^0|0|0|0|0|2|0|0|0^^$0|@$1|2|3|4|5|6|7|R|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|S|8|@]|9|@]|A|$]]|$1|D|3|E|5|6|7|T|8|@]|9|@]|A|$]]|$1|F|3|G|5|6|7|U|8|@$H|V|I|W|J|K]]|9|@]|A|$]]|$1|L|3|M|5|6|7|X|8|@]|9|@]|A|$]]|$1|N|3|O|5|6|7|Y|8|@]|9|@]|A|$]]|$1|P|3|-4|5|6|7|Z|8|@]|9|@]|A|$]]]|Q|$]]

Try this.

^(?=.[A-Z])(?=.[!@##\$&amp;])(?=.[0-9])(?=.*[a-z]).{6,}$

Add comma after six since you want to allow more than 6 characters and $ must be escaped with \$

Update

Try below, ^ and $ removed from above one

(?=.[A-Z])(?=.[!@##$&amp;])(?=.[0-9])(?=.*[a-z]).{6,}

blocks|key|3125429|text|好吧，你试着测试的标准是很糟糕的。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3125430|例如，Pa$5word符合标准，但是一个糟糕的选择，而my+name+%7Cz+NOT+Fr£d强得多，但失败了(没有数字，不同的符号)。|offset|length|style|CODE|3125431|理想情况下，您应该寻找和现有的密码强度检查(虽然我不知道是否有任何现有的/好的)。|3125432|无论如何，对于您所要求的内容的简单解决方案，详细说明正在检查的内容，只需这样做：|3125433|<cfif+NOT+
++++(+len(myPassword)+GTE+6
++++AND+refind('[A-Z]',myPassword)
++++AND+refind('[a-z]',myPassword)
++++AND+refind('[0-9]',myPassword)
++++AND+refind('[!@##$&*]',myPassword)
+++++)>|code-block|syntax|javascript|3125434|把所有的东西都弄成一个正则表达式是没有必要的/好处的。|3125435|entityMap^0|0|3|8|R|J|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|V|8|@$D|W|E|X|F|G]|$D|Y|E|Z|F|G]]|9|@]|A|$]]|$1|H|3|I|5|6|7|10|8|@]|9|@]|A|$]]|$1|J|3|K|5|6|7|11|8|@]|9|@]|A|$]]|$1|L|3|M|5|N|7|12|8|@]|9|@]|A|$O|P]]|$1|Q|3|R|5|6|7|13|8|@]|9|@]|A|$]]|$1|S|3|-4|5|6|7|14|8|@]|9|@]|A|$]]]|T|$]]

Ok, well the set of criteria you're trying to test on are bad.

For example, <code>Pa$5word</code> meets the criteria but is a bad choice, whilst <code>my name |z NOT Fr£d</code> is much stronger but fails (no numbers; different symbols).

Ideally you should look for and existing password strength checker (although I've no idea if there are any existing/good ones out there).

 
Anyhow, for a simple solution to what you've asked, that spells out exactly what is being checked, just do:

<pre><code>&lt;cfif NOT 
 ( len(myPassword) GTE 6
 AND refind('[A-Z]',myPassword)
 AND refind('[a-z]',myPassword)
 AND refind('[0-9]',myPassword)
 AND refind('[!@##$&amp;*]',myPassword)
 )&gt;
</code></pre>

There is no need/benefit to smushing it all into a single regex.

blocks|key|2269083|text|fwiw分离出不同的字符失败：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2269084|<cfscript>+raRe=[["[a-z]","lowercase"],["[A-Z]","uppercase"],["[\W]","non-alphanumeric"],["[\d]","numeric"]];</cfscript>
<cfoutput>
+<cfloop+from=1+to=4+index="idxRe">
++#idxRe#:+refind(raRe[idxRe][1],+myPassword):#refind(raRe[idxRe][1],+myPassword)#+myPassword:#myPassword#;+re:#raRe[idxRe][1]#;+<br+/>
++<cfif+refind(raRe[idxRe][1],+myPassword)+eq+0>Your+password+must+include+at+least+one+#raRe[idxRe][2]#+character<br+/></cfif>
+</cfloop>
</cfoutput>|code-block|syntax|javascript|2269085|当然，如果还需要>=6的话：|2269086|<cfif+Len(myPassword)+lte+6>Your+password+must+be+at+least+6+characters+long</cfif>|2269087|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

fwiw to separate out the different character failures:

<pre><code>&lt;cfscript&gt; raRe=[["[a-z]","lowercase"],["[A-Z]","uppercase"],["[\W]","non-alphanumeric"],["[\d]","numeric"]];&lt;/cfscript&gt;
&lt;cfoutput&gt;
 &lt;cfloop from=1 to=4 index="idxRe"&gt;
 #idxRe#: refind(raRe[idxRe][1], myPassword):&lt;b&gt;#refind(raRe[idxRe][1], myPassword)#&lt;/b&gt; myPassword:&lt;b&gt;#myPassword#&lt;/b&gt;; re:&lt;b&gt;#raRe[idxRe][1]#&lt;/b&gt;; &lt;br /&gt;
 &lt;cfif refind(raRe[idxRe][1], myPassword) eq 0&gt;&lt;b&gt;Your password must include at least one #raRe[idxRe][2]# character&lt;/b&gt;&lt;br /&gt;&lt;/cfif&gt;
 &lt;/cfloop&gt;
&lt;/cfoutput&gt;
</code></pre>

And of course if >=6 is also required:

<pre><code>&lt;cfif Len(myPassword) lte 6&gt;&lt;b&gt;Your password must be at least 6 characters long&lt;/b&gt;&lt;/cfif&gt;
</code></pre>

I'm using this to (try) to validate a 'strong' password in ColdFusion 7.

<pre><code>if ( REFind("^(?=.*[A-Z])(?=.*[!@##$&amp;*])(?=.*[0-9])(?=.*[a-z]).{6}$", myPassword, 1) EQ 0 )
</code></pre>

However, it is failing. Can someone point out my error?

The criteria I think I'm testing is:

<ul>
<li>1 upper</li>
<li>1 lower</li>
<li>1 number</li>
<li>1 special char</li>
<li>6 digit min</li>
</ul>

Footnotes for non-CF people:

<ul>
<li>the double hash is to escape the CF hash;</li>
<li>ColdFusion uses Jakarta ORO 2.0.6 as its regex engine</li>
</ul>

Coldfusion RegEx to check strength of password

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我正在使用这个来验证ColdFusion 7中的“强”密码。if ( REFind("^(?=.*[A-Z])(?=.*[!@##$&*])(?=.*[0-9])(?=.*[a-z]).{6}$", myPassword, 1) EQ 0 )然而，它正在失败。有人能指出我的错误吗？我认为我测试的标准是：1上1下1数字1...

问Coldfusion RegEx检查密码的强度
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