在此字符串操作代码中获取out_of_range错误
在此字符串操作代码中获取out_of_range错误
提问于 2012-06-20 04:56:53
嗨，我在下面的代码中点击std::out_of_range: basic_string::substr。一直在努力想办法解决问题，但却做不到。
std::string orig_str = "1-1,2-3,4-4,56-75,77-77";
size_t number_digits;
for (size_t i = 0; i < orig_str.size(); ++i)
{
number_digits = orig_str.find_first_of(",", i) - i - 1;
if(orig_str.find("-", i) != std::string::npos)
if (orig_str.substr(i - number_digits, i - 1) == orig_str.substr(i + 1, i + number_digits))
orig_str.erase(i-number_digits, number_digits + 1);
}基本上，这段代码正在操作字符串以删除某些范围，预期的行为是：输入字符串： "0-0,2-7,88-88“输出字符串： "0,2-7,88”
回答 3
Stack Overflow用户
回答已采纳
发布于 2012-06-20 06:13:44
AJ，这是我们在聊天中讨论的伪代码：
input_string = "1-1,2-3,4-4,56-75,77-77"
output_string = ""
while (input_string is not empty)
sub = input_string.substr(up to first comma)
input_string = input_string.substr(after first comma)
if (sub.substr(up to dash) == sub.substr(after dash))
output_string += sub.substr(up to dash)
else
output_string += sub
if (input_string is not empty)
output_string += ","Stack Overflow用户
发布于 2012-06-20 06:02:15
您将遍历原始字符串的长度，并对其进行修改并在此更改长度。编译器可能优化对orig_str.size()的调用，这意味着它将获取一次长度，并允许您迭代字符串的新长度。
您可能应该更改以保持orig_str从一开始就保持不变(否则它的命名非常糟糕)，并将结果放入一个新的字符串中。
Stack Overflow用户
发布于 2012-06-20 06:43:25
int flag = 0;
int num_ch;
char * fnum = NULL, * snum = NULL;
int numOfLoop = orig_str.size();
for(int i = 0; i < numOfLoop; i++)
{
if(orig_str[i] == '-')
{
flag = 1;
}
else if(orig_str[i] == ',')
{
int ret = strcmp(fnum, snum);
if(ret == 0)
{
int sizeOfNUM = strlen(fnum);
int numOfChToReplace = sizeOfNUM + sizeOfNUM + 1;
orig_str.replace(i - numOfChToReplace,numOfChToReplace, fnum);
numOfLoop = numOfLoop - (sizeOfNUM + 1);
i = i - (sizeOfNUM + 1);
}
flag = 0;
delete [] fnum;
delete [] snum;
fnum = NULL;
snum = NULL;
}
else
{
if(flag == 1)
{
if(snum == NULL)
{
snum = new char[2];
snum[0] = orig_str[i];
snum[1] = '\0';
}
else
{
int size = strlen(snum);
char * tmp = snum;
snum = new char[size + 2];
for( int j = 0; j < size; j++)
snum[j] = tmp[j];
snum[size] = orig_str[i];
snum[size + 1] = '\0';
}
}
else
{
if(fnum == NULL)
{
fnum = new char[2];
fnum[0] = orig_str[i];
fnum[1] = '\0';
}
else
{
int size = strlen(fnum);
char * tmp = fnum;
fnum = new char[size + 2];
for( int j = 0; j < size; j++)
fnum[j] = tmp[j];
fnum[size] = orig_str[i];
fnum[size + 1] = '\0';
}
}
}
}
int ret = strcmp(fnum, snum);
if(ret == 0)
{
int sizeOfNUM = strlen(fnum);
int numOfChToReplace = sizeOfNUM + sizeOfNUM + 1;
orig_str.replace(i - numOfChToReplace,numOfChToReplace, fnum);
numOfLoop = numOfLoop - (sizeOfNUM + 1);
i = i - (sizeOfNUM + 1);
}
flag = 0;
delete [] fnum;
delete [] snum;
fnum = NULL;
snum = NULL;
std::cout << orig_str.c_str() << std::endl;页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/11113050
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