blocks|key|3719435|text|两个cut命令可能是最简单的(尽管不一定是最好的)：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|3719436|DSCL+%7C+cut+-d,+-f1+%7C+cut+-d=+-f2|code-block|syntax|javascript|3719437|首先，在逗号上拆分DSCL的输出，然后打印第一个字段("CN=First+Last")；然后在等号上拆分输出，然后打印第二个字段。|3719438|entityMap^0|2|3|0|0|9|4|0^^$0|@$1|2|3|4|5|6|7|O|8|@$9|P|A|Q|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|R|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|S|8|@$9|T|A|U|B|C]]|D|@]|E|$]]|$1|M|3|-4|5|6|7|V|8|@]|D|@]|E|$]]]|N|$]]

Two <code>cut</code> commands is probably the simplest (although not necessarily the best):

<pre><code>DSCL | cut -d, -f1 | cut -d= -f2
</code></pre>

First, split the output from <code>DSCL</code> on commas and print the first field ("CN=First Last"); then split that on equal signs and print the second field.

blocks|key|3719500|text|使用sed：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3719501|sed+'s/%5ECN=$[%5E,]*$.*/\1/'+input_file|code-block|syntax|javascript|3719502|%5E匹配行开始的CN=文字字符串匹配(%5E，*)所有内容，直到逗号.*+rest|blockquote|3719503|3719504|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|I|7|O|8|@]|9|@]|A|$]]|$1|J|3|-4|5|6|7|P|8|@]|9|@]|A|$]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

Using sed:

<pre><code>sed 's/^CN=$[^,]*$.*/\1/' input_file
</code></pre>

<blockquote>
<pre><code>^ matches start of line 
CN= literal string match
$[^,]*$ everything until a comma
.* rest
</code></pre>
</blockquote>

blocks|key|2858963|text|http://www.gnu.org/software/gawk/manual/gawk.html#Field-Separators|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|2858964|awk+-v+RS=','+-v+FS='='+'$1=="CN"{print+$2}'+foo.txt|code-block|syntax|javascript|2858965|entityMap|0|LINK|mutability|MUTABLE|url^0|0|1U|0|0|0^^$0|@$1|2|3|4|5|6|7|P|8|@]|9|@$A|Q|B|R|1|S]]|C|$]]|$1|D|3|E|5|F|7|T|8|@]|9|@]|C|$G|H]]|$1|I|3|-4|5|6|7|U|8|@]|9|@]|C|$]]]|J|$K|$5|L|M|N|C|$O|4]]]]

<a href="http://www.gnu.org/software/gawk/manual/gawk.html#Field-Separators" rel="nofollow">http://www.gnu.org/software/gawk/manual/gawk.html#Field-Separators</a> 

<pre><code>awk -v RS=',' -v FS='=' '$1=="CN"{print $2}' foo.txt
</code></pre>

blocks|key|2838991|text|我也喜欢awk，所以我从第四个字符中打印子字符串：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2838992|DSCL+%7C+awk+'{FS=","};+{print+substr($1,4)}'+>+filterednames.txt|offset|length|style|CODE|2838993|entityMap^0|0|0|1R|0^^$0|@$1|2|3|4|5|6|7|J|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|K|8|@$D|L|E|M|F|G]]|9|@]|A|$]]|$1|H|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|I|$]]

I like awk too, so I print the substring from the fourth char:

<code>DSCL | awk '{FS=","}; {print substr($1,4)}' &gt; filterednames.txt</code>

blocks|key|2839172|text|我认为到目前为止提供的所有正则表达式的答案都是错误的，因为它们没有正确处理普通名称中引用的'，‘字符。例如，考虑像这样的distinguishedName：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2839173|CN=Doe\,+John,CN=Users,DC=example,DC=local|code-block|syntax|javascript|2839174|最好使用真正的库来解析distinguishedName的组件。如果您想在命令行中快速查找内容，请尝试将DN连接到如下命令：|2839175|++++echo+"CN=Doe\,+John,CN=Users,DC=activedir,DC=local"+%7C+python+-c+'import+ldap;+import+sys;+print+ldap.dn.explode_dn(sys.stdin.read().strip(),+notypes=1)[0]'|2839176|(取决于是否安装了python库)。您可以用PHP的内置ldap_explode_dn()函数编写类似的内容。|2839177|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Q|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|S|8|@]|9|@]|A|$]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

I think all of the regular expression answers provided so far are buggy, insofar as they do not properly handle quoted ',' characters in the common name. For example, consider a distinguishedName like:

<pre><code>CN=Doe\, John,CN=Users,DC=example,DC=local
</code></pre>

Better to use a real library able to parse the components of a distinguishedName. If you're looking for something quick on the command line, try piping your DN to a command like this:

<pre><code> echo "CN=Doe\, John,CN=Users,DC=activedir,DC=local" | python -c 'import ldap; import sys; print ldap.dn.explode_dn(sys.stdin.read().strip(), notypes=1)[0]'
</code></pre>

(depends on having the python-ldap library installed). You could cook up something similar with PHP's built-in ldap_explode_dn() function.

blocks|key|3719666|text|这个regex将解析一个可分辨的名称，为每个匹配的name和val提供一个捕获组。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|3719667|当DN字符串包含逗号时，它们将被引用--此正则表达式正确地处理引号字符串和未引号字符串，并处理引用字符串中的转义引号：|3719668|(?:%5E%7C,\s?)(?:(?<name>[A-Z]%2B)=(?<val>"(?:[%5E"]%7C"")%2B"%7C[%5E,]%2B))%2B|3719669|这里的格式很好：|3719670|(?:%5E%7C,\s?)
(?:
++++(?<name>[A-Z]%2B)=
++++(?<val>"(?:[%5E"]%7C"")%2B"%7C[%5E,]%2B)
)%2B|code-block|syntax|javascript|3719671|下面是一个链接，您可以看到它的作用：https://regex101.com/r/zfZX3f/2|3719672|如果您希望regex只获得CN，那么这个经过改编的版本将完成以下操作：|3719673|(?:%5E%7C,\s?)(?:CN=(?<val>"(?:[%5E"]%7C"")%2B"%7C[%5E,]%2B))|3719674|entityMap|0|LINK|mutability|MUTABLE|url|https://regex101.com/r/zfZX3f/2^0|P|4|U|3|0|0|0|1N|0|0|0|I|V|0|0|0|0|19|0^^$0|@$1|2|3|4|5|6|7|14|8|@$9|15|A|16|B|C]|$9|17|A|18|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|19|8|@]|D|@]|E|$]]|$1|H|3|I|5|6|7|1A|8|@$9|1B|A|1C|B|C]]|D|@]|E|$]]|$1|J|3|K|5|6|7|1D|8|@]|D|@]|E|$]]|$1|L|3|M|5|N|7|1E|8|@]|D|@]|E|$O|P]]|$1|Q|3|R|5|6|7|1F|8|@]|D|@$9|1G|A|1H|1|1I]]|E|$]]|$1|S|3|T|5|6|7|1J|8|@]|D|@]|E|$]]|$1|U|3|V|5|6|7|1K|8|@$9|1L|A|1M|B|C]]|D|@]|E|$]]|$1|W|3|-4|5|6|7|1N|8|@]|D|@]|E|$]]]|X|$Y|$5|Z|10|11|E|$12|13]]]]

This regex will parse a distinguished name, giving <code>name</code> and <code>val</code> a capture groups for each match.

When DN strings contain commas, they are meant to be quoted - this regex correctly handles both quoted and unquotes strings, and also handles escaped quotes in quoted strings:

<code>(?:^|,\s?)(?:(?&lt;name&gt;[A-Z]+)=(?&lt;val&gt;"(?:[^"]|"")+"|[^,]+))+</code>

Here is is nicely formatted:

<pre><code>(?:^|,\s?)
(?:
 (?&lt;name&gt;[A-Z]+)=
 (?&lt;val&gt;"(?:[^"]|"")+"|[^,]+)
)+
</code></pre>

Here's a link so you can see it in action:
<a href="https://regex101.com/r/zfZX3f/2" rel="nofollow noreferrer">https://regex101.com/r/zfZX3f/2</a>

If you want a regex to get only the CN, then this adapted version will do it:

<code>(?:^|,\s?)(?:CN=(?&lt;val&gt;"(?:[^"]|"")+"|[^,]+))</code>

I am attempting to parse (with <code>sed</code>) just <code>First Last</code> from the following DN(s) returned by the <code>DSCL</code> command in OSX terminal bash environment...

<code>CN=First Last,OU=PCS,OU=guests,DC=domain,DC=edu</code>

I have tried multiple regexs from this site and others with questions very close to what I wanted... mainly <a href="https://stackoverflow.com/questions/97113/regular-expression-to-parse-ldap-dn">this question</a>... I have tried following the advice to the best of my ability (I don't necessarily consider myself a newbie...but definitely a newbie to regex..)

<code>DSCL</code> returns a list of DNs, and I would like to only have <code>First Last</code> printed to a text file. I have attempted using <code>sed</code>, but I can't seem to get the correct function. I am open to other commands to parse the output. Every line begins with <code>CN=</code> and then there is a comma between <code>Last</code> and <code>OU=</code>.

Thank you very much for your help!

Regular Expression to parse Common Name from Distinguished Name

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我试图从OSX终端sed First Last环境中的DSCL命令返回的DN(s)中解析(用).CN=First Last,OU=PCS,OU=guests,DC=domain,DC=edu我尝试过从这个网站和其他与我想要的问题非常接近的多个规则.主要是。我已经尽我最大的能力遵循这个建议(我不一定认为自己是newbie...

问解析公共名称和区分名称的正则表达式
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