blocks|key|4244169|text|subprocess.Popen.communicate()的文档中包含了“等待进程终止”这一短语，因此它阻塞也就不足为奇了。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|4244170|如果您只是创建了Popen对象，然后将它单独放在一边，那么它应该异步运行。然后，如果要检查，可以调用process.poll()或process.wait()。注意，在让脚本终止之前，您应该确保它已经完成，否则子进程将被草率地终止。若要让脚本退出而不杀死子进程，请参见注释中的misyuk。|4244171|entityMap|0|LINK|mutability|MUTABLE|url|http://docs.python.org/library/subprocess.html#subprocess.Popen.communicate|1|https://stackoverflow.com/questions/2602052/how-to-call-a-program-from-python-without-waiting-for-it-to-return^0|0|U|0|U|0|0|8|5|1E|E|1T|E|3U|6|1|0^^$0|@$1|2|3|4|5|6|7|R|8|@$9|S|A|T|B|C]]|D|@$9|U|A|V|1|W]]|E|$]]|$1|F|3|G|5|6|7|X|8|@$9|Y|A|Z|B|C]|$9|10|A|11|B|C]|$9|12|A|13|B|C]]|D|@$9|14|A|15|1|16]]|E|$]]|$1|H|3|-4|5|6|7|17|8|@]|D|@]|E|$]]]|I|$J|$5|K|L|M|E|$N|O]]|P|$5|K|L|M|E|$N|Q]]]]

The documentation of <a href="http://docs.python.org/library/subprocess.html#subprocess.Popen.communicate" rel="nofollow noreferrer"><code>subprocess.Popen.communicate()</code></a> includes the phrase "Wait for process to terminate," so it shouldn't be surprising that it blocks.

If you just create the <code>Popen</code> object and then leave it alone, it should run asynchronously. You can then call <code>process.poll()</code> or <code>process.wait()</code> if you want to check on it. Note you should make sure it's done before letting the script terminate, otherwise the subprocess will be unceremoniously killed. To let the script exit without killing the subprocess, see <a href="https://stackoverflow.com/questions/2602052/how-to-call-a-program-from-python-without-waiting-for-it-to-return">the question linked by @aleks_misyuk</a> in the comments.

blocks|key|4244204|text|PyQt4.QtCore.QProcess.startDetached()在后台独立执行程序：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|4244205|QProcess.startDetached('vncviewer.exe')|code-block|syntax|javascript|4244206|与单独使用的subprocess.Popen()对象as+suggested+by+Dougal不同，使用此方法启动的进程即使在调用进程结束后仍继续运行。|4244207|在PyQt4程序中，更喜欢QProcess而不是subprocess。前者集成到Qt事件循环中，允许通过Qt信号与子进程异步通信。|4244208|entityMap|0|LINK|mutability|MUTABLE|url|http://qt-project.org/doc/qt-4.8/qprocess.html#startDetached-3|1|https://stackoverflow.com/a/12099908/355252^0|0|11|0|11|0|0|0|6|I|Q|M|1|0|D|8|O|A|0^^$0|@$1|2|3|4|5|6|7|Y|8|@$9|Z|A|10|B|C]]|D|@$9|11|A|12|1|13]]|E|$]]|$1|F|3|G|5|H|7|14|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|15|8|@$9|16|A|17|B|C]]|D|@$9|18|A|19|1|1A]]|E|$]]|$1|M|3|N|5|6|7|1B|8|@$9|1C|A|1D|B|C]|$9|1E|A|1F|B|C]]|D|@]|E|$]]|$1|O|3|-4|5|6|7|1G|8|@]|D|@]|E|$]]]|P|$Q|$5|R|S|T|E|$U|V]]|W|$5|R|S|T|E|$U|X]]]]

<a href="http://qt-project.org/doc/qt-4.8/qprocess.html#startDetached-3" rel="nofollow noreferrer"><code>PyQt4.QtCore.QProcess.startDetached()</code></a> executes the program independently in background:

<pre><code>QProcess.startDetached('vncviewer.exe')
</code></pre>

Unlike a left alone <code>subprocess.Popen()</code> object <a href="https://stackoverflow.com/a/12099908/355252">as suggested by Dougal</a>, a process started with this method continues to run even after the calling process has terminated.

In PyQt4 programs, prefer <code>QProcess</code> over <code>subprocess</code>. The former integrates into the Qt event loop and allows for asynchronous communication with the sub process via Qt signals.

<blockquote>
 Possible Duplicate: 
 <a href="https://stackoverflow.com/questions/2602052/how-to-call-a-program-from-python-without-waiting-for-it-to-return">how to call a program from python without waiting for it to return</a> 
</blockquote>



I'm writing a PyQt program that needs to start an external Windows executable. At that point the Python program should continue to run, never needing any contact with the exe file it started.

I have tried several variations such as:

<pre><code>process = subprocess.Popen(["vncviewer.exe"]); process.communicate()
subprocess.call("vncviewer.exe")
os.system("vncviewer.exe")
os.system("vncviewer.exe&amp;")
os.system("start vncviewer.exe")
</code></pre>

etc.

Using most any strategy, I can run the program successfully, but the Python script is then blocked until the program completes. The GUI is frozen and unusable. 

How can I have Python start a completely separate and unrelated task, and then continue to run so that I can open other programs, and even end the Python script without affecting the programs it started?

Starting an external program in Python and returning immediately

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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