blocks|key|3943281|text|在我看来，首先不应该将该字符串存储在数据库中，而是使用时间戳。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3943282|如果你这样做了，你可以使用这样的东西：|3943283|$dateTime+=+new+DateTime($theTimestamp);
$date+=+array(
++++'day'+=>+$dateTime->format('j'),
++++'month'+=>+$dateTime->format('F'),
++++'year'+=>+$dateTime->format('y'),
);|code-block|syntax|javascript|3943284|如果希望在数组中灵活处理所需内容，则可以创建如下所示的函数：|3943285|function+buildDateArray($theTimestamp,+$elements)+{
++++$dateTime+=+new+DateTime($theTimestamp);
++++$date+=+array();
++++foreach($elements+as+$key+=>+$format)+{
++++++++$date[$key]+=+$dateTime->format($format);
++++}
}

$theArray+=+buildDateArray($theTimestamp,+array(
++++'day'+=>+'j',
++++'month'+=>+'F',
++++'year'+=>+'y',
));|3943286|注：DateTime可在5.2.0时使用|offset|length|style|CODE|3943287|entityMap^0|0|0|0|0|0|2|8|0^^$0|@$1|2|3|4|5|6|7|U|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|V|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|W|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|6|7|X|8|@]|9|@]|A|$]]|$1|K|3|L|5|F|7|Y|8|@]|9|@]|A|$G|H]]|$1|M|3|N|5|6|7|Z|8|@$O|10|P|11|Q|R]]|9|@]|A|$]]|$1|S|3|-4|5|6|7|12|8|@]|9|@]|A|$]]]|T|$]]

In my opinion you shouldn't store that string in the database in the first place, but use the timestamp.

If you do that you could use something like:

<pre><code>$dateTime = new DateTime($theTimestamp);
$date = array(
 'day' =&gt; $dateTime-&gt;format('j'),
 'month' =&gt; $dateTime-&gt;format('F'),
 'year' =&gt; $dateTime-&gt;format('y'),
);
</code></pre>

If you want to be flexible as to what you want in the array you could create a function like:

<pre><code>function buildDateArray($theTimestamp, $elements) {
 $dateTime = new DateTime($theTimestamp);
 $date = array();
 foreach($elements as $key =&gt; $format) {
 $date[$key] = $dateTime-&gt;format($format);
 }
}

$theArray = buildDateArray($theTimestamp, array(
 'day' =&gt; 'j',
 'month' =&gt; 'F',
 'year' =&gt; 'y',
));
</code></pre>

Note: the <code>DateTime</code> is available as of 5.2.0

blocks|key|25418|text|如果您有PHP5.3或更高版本，请使用DateTime::createFromFormat|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|25419|$date+=+DateTime::createFromFormat($inputFormat,+$gotDate);

$result+=+array(
++++'day'+=>+(int)$date->format('j'),
++++'month'+=>+$date->format('F'),
++++'year'+=>+(int)$date->format('Y')
);|code-block|syntax|javascript|25420|entityMap|0|LINK|mutability|MUTABLE|url|http://php.net/manual/en/datetime.createfromformat.php^0|J|Q|J|Q|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@$9|T|A|U|B|C]]|D|@$9|V|A|W|1|X]]|E|$]]|$1|F|3|G|5|H|7|Y|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Z|8|@]|D|@]|E|$]]]|L|$M|$5|N|O|P|E|$Q|R]]]]

If you have PHP 5.3 or later, use <a href="http://php.net/manual/en/datetime.createfromformat.php" rel="nofollow"><code>DateTime::createFromFormat</code></a>:

<pre><code>$date = DateTime::createFromFormat($inputFormat, $gotDate);

$result = array(
 'day' =&gt; (int)$date-&gt;format('j'),
 'month' =&gt; $date-&gt;format('F'),
 'year' =&gt; (int)$date-&gt;format('Y')
);
</code></pre>

blocks|key|3922326|text|已经在本机php+DateTime类中找到了答案的第一部分:只需使用date_parse(+get_date()+);。自PHP5.2以来即可获得|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|3922327|//+@example
'year'+=>+int+2012
'month'+=>+int+9
'day'+=>+int+24
'hour'+=>+boolean+false
'minute'+=>+boolean+false
'second'+=>+boolean+false
'fraction'+=>+boolean+false
'warning_count'+=>+int+0
'warnings'+=>+
+++array
+++empty
'error_count'+=>+int+0
'errors'+=>+
+++array
+++empty
'is_localtime'+=>+boolean+false|code-block|syntax|javascript|3922328|这个答案仍然没有解决问题，我不知道如何映射j到day，F到month，等等。|3922329|entityMap|0|LINK|mutability|MUTABLE|url|http://php.net/manual/en/function.date-parse.php^0|9|8|Y|P|Y|P|0|0|0|L|1|N|3|R|1|T|5|0^^$0|@$1|2|3|4|5|6|7|U|8|@$9|V|A|W|B|C]|$9|X|A|Y|B|C]]|D|@$9|Z|A|10|1|11]]|E|$]]|$1|F|3|G|5|H|7|12|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|13|8|@$9|14|A|15|B|C]|$9|16|A|17|B|C]|$9|18|A|19|B|C]|$9|1A|A|1B|B|C]]|D|@]|E|$]]|$1|M|3|-4|5|6|7|1C|8|@]|D|@]|E|$]]]|N|$O|$5|P|Q|R|E|$S|T]]]]

Already found the first part of the answer in the native php <code>DateTime</code> class: Just use <a href="http://php.net/manual/en/function.date-parse.php" rel="nofollow"><code>date_parse( get_date() );</code></a>. Available since PHP 5.2

<pre><code>// @example
'year' =&gt; int 2012
'month' =&gt; int 9
'day' =&gt; int 24
'hour' =&gt; boolean false
'minute' =&gt; boolean false
'second' =&gt; boolean false
'fraction' =&gt; boolean false
'warning_count' =&gt; int 0
'warnings' =&gt; 
 array
 empty
'error_count' =&gt; int 0
'errors' =&gt; 
 array
 empty
'is_localtime' =&gt; boolean false
</code></pre>

This answer still doesn't solve the problem, that I don't know how to map <code>j</code> to <code>day</code>, <code>F</code> to <code>month</code>, etc.

blocks|key|3922368|text|正如您现在所写的，您手头没有PHP5.3(真的很遗憾)，所以您需要解析字符串“手动”。除了PCRE正则表达式之外，还有sscanf。示例：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|3922369|$date+=+'September+24,+2012';
$result+=+sscanf($date,+'%25s+%252d,+%254d',+$month,+$day,+$year);
$parsed+=+array(
++++'day'+++=>+$day,
++++'month'+=>+$month,
++++'year'++=>+$year
);
var_dump($parsed);|code-block|syntax|javascript|3922370|输出：|3922371|array(3)+{
++'day'+=>
++int(24)
++'month'+=>
++string(9)+"September"
++'year'+=>
++int(2012)
}|3922372|这将根据您的格式解析输入日期字符串。如果您需要这种更灵活的方法，则需要动态构建模式，并将值与结果数组相关联。|3922373|我已经编写了另一个例子来实现这一点。它可能有点脆弱(我增加了一些注释)，但它确实有效。当然，我会将它包装成一个函数--更好地处理错误条件--但是我保留了原始代码，以便更好地展示它是如何工作的：|3922374|//+input+variables:
$date+=+'September+24,+2012';
$format+=+'F+j,+Y';

//+define+the+formats:
$formats+=+array(
++++'F'+=>+array('%25s',++'month'),++#+A+full+textual+representation+of+a+month,+such+as+January+or+March
++++'j'+=>+array('%252d',+'day'),++++#+Day+of+the+month,+2+digits+with+or+without+leading+zeros
++++'Y'+=>+array('%254d',+'year'),+++#+A+full+numeric+representation+of+a+year,+4+digits
++++#+NOTE:+add+more+formats+as+you+need+them
);

//+compile+the+pattern+and+order+of+values
$pattern+=+'';
$order+=+array();
for($l+=+strlen($format),+$i+=+0;+$i+<+$l;+$i%2B%2B)+{
++++$c+=+$format[$i];

++++//+handle+escape+sequences
++++if+($c+===+'\\')+{
++++++++$i%2B%2B;
++++++++$pattern+.=+($i+<+$l)+?+$format[$i]+:+$c;
++++++++continue;
++++}

++++//+handle+formats+or+if+not+a+format+string,+take+over+literally
++++if+(isset($formats[$c]))+{
++++++++$pattern+.=+$formats[$c][0];
++++++++$order[]+=+$formats[$c][1];
++++}+else+{
++++++++$pattern+.=+$c;
++++}
}

//+scan+the+string+based+on+pattern
//+NOTE:+This+does+not+do+any+error+checking
$values+=+sscanf($date,+$pattern);

//+combine+with+their+names
//+NOTE:+duplicate+array+keys+are+possible,+this+is+risky,
//+++++++write+your+own+logic+this+is+for+demonstration
$result+=+array_combine($order,+$values);

//+NOTE:+you+can+then+even+check+by+type+(string/int)+and+convert
//+++++++month+or+day+names+into+integers

var_dump($result);|3922375|在这种情况下，结果是：|3922376|array(3)+{
++'month'+=>
++string(9)+"September"
++'day'+=>
++int(24)
++'year'+=>
++int(2012)
}|3922377|注意笔记。在我编写它之前，我已经检查了PHP手册中的用户注释，但是这里提供的函数只用于解析一种特定的模式，而这个变体应该在一定程度上是可扩展的。如果您只有这一种格式，那么您可以自然地非动态地创建sscanf字符串。|3922378|另见：format+equivalent+for+PHP+5.2+(or+lower)|3922379|还要注意，由于这是wordpress，月份名称可能会被翻译。|3922380|我很肯定你也能得到一个时间戳格式的帖子的日期。对于一个插件来说，仅仅基于post+ID来提供这个值而不是解析一些字符串可能会减少一些负担。|3922381|最后请注意:只有Wordpress有一个最低的PHP版本，这不一定意味着您的插件需要精确的最低版本，也。特别是在您概述的情况下，PHP5.2不再得到任何支持(它已经死了)，您可以帮助插件用户告诉他们应该更新他们的PHP版本。|3922382|看起来Wordpress仍然没有给出关于PHP版本的警告，他们停止使用浏览器和他们自己的软件;)没有必要模仿这种糟糕的做法。告诉你的用户，他们处于危险之中，并把他们吓出地狱(或做闪亮的弹出泡泡，以一种不那么危险的方式获得信息。)为你的用户做一个善意的服务，然后有一些东西为双方赢得，做一些优雅的退步，以显示你的良好态度)。|3922383|另见：Is+there+a+Wordpress+version+that+is+incompatible+with+PHP+5.3?|3922384|如果您感兴趣，可以在PHP.net：https://wiki.php.net/rfc/releaseprocess上找到当前的PHP发布周期。|3922385|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/questions/2621433/date-create-from-format-equivalent-for-php-5-2-or-lower|1|https://wordpress.stackexchange.com/questions/28603/is-there-a-wordpress-version-that-is-incompatible-with-php-5-3|2|https://wiki.php.net/rfc/releaseprocess^0|1N|6|0|0|0|0|0|0|0|0|0|0|3|14|0|0|0|0|0|0|3|1R|1|0|I|13|2|0^^$0|@$1|2|3|4|5|6|7|1Q|8|@$9|1R|A|1S|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|1T|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|1U|8|@]|D|@]|E|$]]|$1|M|3|N|5|H|7|1V|8|@]|D|@]|E|$I|J]]|$1|O|3|P|5|6|7|1W|8|@]|D|@]|E|$]]|$1|Q|3|R|5|6|7|1X|8|@]|D|@]|E|$]]|$1|S|3|T|5|H|7|1Y|8|@]|D|@]|E|$I|J]]|$1|U|3|V|5|6|7|1Z|8|@]|D|@]|E|$]]|$1|W|3|X|5|H|7|20|8|@]|D|@]|E|$I|J]]|$1|Y|3|Z|5|6|7|21|8|@]|D|@]|E|$]]|$1|10|3|11|5|6|7|22|8|@]|D|@$9|23|A|24|1|25]]|E|$]]|$1|12|3|13|5|6|7|26|8|@]|D|@]|E|$]]|$1|14|3|15|5|6|7|27|8|@]|D|@]|E|$]]|$1|16|3|17|5|6|7|28|8|@]|D|@]|E|$]]|$1|18|3|19|5|6|7|29|8|@]|D|@]|E|$]]|$1|1A|3|1B|5|6|7|2A|8|@]|D|@$9|2B|A|2C|1|2D]]|E|$]]|$1|1C|3|1D|5|6|7|2E|8|@]|D|@$9|2F|A|2G|1|2H]]|E|$]]|$1|1E|3|-4|5|6|7|2I|8|@]|D|@]|E|$]]]|1F|$1G|$5|1H|1I|1J|E|$1K|1L]]|1M|$5|1H|1I|1J|E|$1K|1N]]|1O|$5|1H|1I|1J|E|$1K|1P]]]]

As you've now wrote that you do not have PHP 5.3 at hand (really a pity), so you need to parse the string "by hand". Next to PCRE regular expressions, there is also <code>sscanf</code>. Example:

<pre><code>$date = 'September 24, 2012';
$result = sscanf($date, '%s %2d, %4d', $month, $day, $year);
$parsed = array(
 'day' =&gt; $day,
 'month' =&gt; $month,
 'year' =&gt; $year
);
var_dump($parsed);
</code></pre>

Output:

<pre><code>array(3) {
 'day' =&gt;
 int(24)
 'month' =&gt;
 string(9) "September"
 'year' =&gt;
 int(2012)
}
</code></pre>

This will already parse the input date string according to your format. If you need this more flexible, the pattern needs to be built dynamically, as well as associating the values to the result array.

I've compiled another example that does this. It might be a little fragile (I've added some notes), however it does work. Naturally I would wrap this into a function an better deal with the error conditions but I've keep the code raw, so that it better shows how it works:

<pre><code>// input variables:
$date = 'September 24, 2012';
$format = 'F j, Y';

// define the formats:
$formats = array(
 'F' =&gt; array('%s', 'month'), # A full textual representation of a month, such as January or March
 'j' =&gt; array('%2d', 'day'), # Day of the month, 2 digits with or without leading zeros
 'Y' =&gt; array('%4d', 'year'), # A full numeric representation of a year, 4 digits
 # NOTE: add more formats as you need them
);

// compile the pattern and order of values
$pattern = '';
$order = array();
for($l = strlen($format), $i = 0; $i &lt; $l; $i++) {
 $c = $format[$i];

 // handle escape sequences
 if ($c === '\\') {
 $i++;
 $pattern .= ($i &lt; $l) ? $format[$i] : $c;
 continue;
 }

 // handle formats or if not a format string, take over literally
 if (isset($formats[$c])) {
 $pattern .= $formats[$c][0];
 $order[] = $formats[$c][1];
 } else {
 $pattern .= $c;
 }
}

// scan the string based on pattern
// NOTE: This does not do any error checking
$values = sscanf($date, $pattern);

// combine with their names
// NOTE: duplicate array keys are possible, this is risky,
// write your own logic this is for demonstration
$result = array_combine($order, $values);

// NOTE: you can then even check by type (string/int) and convert
// month or day names into integers

var_dump($result);
</code></pre>

The result in this case then is:

<pre><code>array(3) {
 'month' =&gt;
 string(9) "September"
 'day' =&gt;
 int(24)
 'year' =&gt;
 int(2012)
}
</code></pre>

Take care of the notes. Before I wrote it, I've checked the user-notes in the PHP manual, but the functions offered there are only for parsing one specific pattern, whereas this variant should be extensible to a certain degree. If you only have that one format, you can naturally create the sscanf string non dynamically.

See also: <a href="https://stackoverflow.com/questions/2621433/date-create-from-format-equivalent-for-php-5-2-or-lower">date_create_from_format equivalent for PHP 5.2 (or lower)</a>

Also take care that as this is wordpress, the month names might be translated.

And I'm pretty sure you can get the date of a post also in timestamp format. For a plugin it might be less burdensome to just aquire that value based on the post ID instead of parsing some string.

And a final note: Only Wordpress has a minimum PHP version, it must not mean your plugin needs that exact minimum version, too. Especially in the case you outline, PHP 5.2 does not get any support any longer (it's dead), and you could do your plugins users the favor to tell them that they should update their PHP version.

It looks like that Wordpress still misses to give warnings about the PHP version, they stop with browsers and their own software somehow ;) There is no need to mimic that bad practice. Tell your users that they are in danger and scare the hell out of them (or do shiny popup-bubbles to get the message over in a less threatening way. Do your users a service with good intentions, then there is something to win for both sides, do some kind of graceful fallback to show your good attitude).

See also: <a href="https://wordpress.stackexchange.com/questions/28603/is-there-a-wordpress-version-that-is-incompatible-with-php-5-3">Is there a Wordpress version that is incompatible with PHP 5.3?</a>

You find the current release cycle of PHP outlined on PHP.net: <a href="https://wiki.php.net/rfc/releaseprocess" rel="nofollow noreferrer">https://wiki.php.net/rfc/releaseprocess</a> if you're interested.

I have a string returning from a DB option, that allows the user to set her/his date format:

<pre><code>F j, Y
</code></pre>

which would (for today) then return the following value in my <code>get_date()</code> function:

<pre><code>string 'September 24, 2012' (length=18)
</code></pre>

Now I need an associative array that splits that string:

<pre><code>array( 
 'day' =&gt; 24,
 'month' =&gt; 'September',
 'year' =&gt; 2012
)
</code></pre>

As don't know how the user sets her/his date, I have the problem that I can't simply say <code>F = month, j = day, Y = year</code>. Everything that the <a href="http://php.net/manual/de/function.date.php" rel="nofollow">php <code>date()</code> function</a> allows, is allowed in the system.

<blockquote>
 Question: How can I "match" those? Is there some native function that I've overseen, that tells me if something is a month/day/year/hour/...?
</blockquote>

Edit: The max. PHP version I can use is PHP 5.2.1

Explode date/time string into assoc array

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我有一个从DB选项返回的字符串，允许用户设置她/他的日期格式：F j, Y然后在我的get_date()函数中返回以下值：string 'September 24, 2012' (length=18)现在，我需要一个分割该字符串的关联数组：array(     'day'   => 24,    'month' => ...

问在assoc数组中爆炸日期/时间字符串
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