如何以最快的方式从当前日期中选择周数据(更准确地说,是持续7天的数据),因为我在表中有数百万或行。我在sql表中有一个created_date的时间戳。
我试过这个
SELECT Created_Date
FROM Table_Name
WHERE Created_Date >= DATEADD(day,-7, GETDATE())我有两个问题:
发布于 2016-06-03 02:50:20
选择过去7天的记录
SELECT * FROM [TableName]
WHERE Created_Date >= DATEADD(day, -7, GETDATE())选择当前周的记录
SET DATEFIRST 1 -- Define beginning of week as Monday
SELECT * FROM [TableName]
WHERE CreatedDate >= DATEADD(day, 1 - DATEPART(WEEKDAY, GETDATE()), CONVERT(DATE, GETDATE()))
AND CreatedDate < DATEADD(day, 8 - DATEPART(WEEKDAY, GETDATE()), CONVERT(DATE, GETDATE()))如果您想选择上周的记录,而不是最后7天的记录
SET DATEFIRST 1 -- Define beginning of week as Monday
SELECT * FROM [TableName]
WHERE CreatedDate >= DATEADD(day, -(DATEPART(WEEKDAY, GETDATE()) + 6), CONVERT(DATE, GETDATE()))
AND CreatedDate < DATEADD(day, 1 - DATEPART(WEEKDAY, GETDATE()), CONVERT(DATE, GETDATE()))https://stackoverflow.com/questions/13266130
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