我是PHP/MySQL的新手,但到目前为止,我还是挺过来的,但是现在我需要从两个相关的表中获取信息。我已经对我需要做的事情做了很多研究,但似乎找不出我做错了什么。
问题:如何从与shortlink_analytics?中的短链接相关的短链接表中获得链接
我得到了错误:警告: mysql_fetch_array()希望参数1是资源,布尔给定的
我的桌子如下:
短链接表
id
短链
链接
createdTime
createdBy
shortlink_analytics表
短链
推荐人
hitTime
userIP
userAgent
到目前为止,我尝试过的代码是:
$linecount = 1;
//$mostPop is where I think I have gone wrong and this is where the warning refers to
$mostPop = "SELECT shortlink, COUNT(shortlink) FROM shortlink_analytics JOIN shortlinks ON shortlink_analytics.shortlink = shortlinks.shortlink GROUP BY shortlink ORDER BY COUNT(shortlink) DESC LIMIT 10";
$loadPop = mysql_query($mostPop);
echo '<table id="middleIndex">';
echo '<tr><td class = "overFlow"><h2>Most Popular Shortlink</h2></td></tr>';
echo '<tr>';
while($row = mysql_fetch_array($loadPop))
{
echo '<td class = "overFlow">'.$row[1].' visits - <a href = "info.php?link='. $row['shortlink'] .'">hud.ac/' . $row['shortlink'] . '</a></td>';
echo '</tr>';
$linecount++;
}
echo '<tr id="indexMiddle"><td id="hand" class = "overFlow"><a onclick="indexMostPopular()">View More</a></td></tr>';
echo '</table>';
我认为,对于如何使用、join、或形成成功连接所需的参数,我还没有足够深入的了解。
发布于 2013-01-09 11:21:14
在两个表中都有shortlink
,这将造成不明确的情况。尝试以下sql语句
$mostPop = "SELECT shortlink_analytics.shortlink AS short,
COUNT(shortlink_analytics.shortlink) AS shortcount,
(SELECT link FROM shortlinks
WHERE shortlinks.shortlink = shortlink_analytics.shortlink) AS shLink
FROM shortlink_analytics
JOIN shortlinks ON shortlink_analytics.shortlink = shortlinks.shortlink
GROUP BY shortlink_analytics.shortlink
ORDER BY COUNT(shortlink_analytics.shortlink) DESC LIMIT 10";
发布于 2013-01-09 11:18:00
尝试以下操作(在mysql中运行此查询,如果正在工作,请在php脚本中添加它)
SELECT
shortlink_analytics.shortlink, COUNT(shortlink_analytics.shortlink)
FROM
shortlink_analytics
INNER JOIN
shortlinks ON shortlink_analytics.shortlink = shortlinks.shortlink
GROUP BY shortlink_analytics.shortlink
ORDER BY COUNT(shortlink_analytics.shortlink) DESC
LIMIT 10
并检查mysql_effected_rows()
函数以检查查询是否返回某一行
https://stackoverflow.com/questions/14233994
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