blocks|key|1370656|text|您必须将c转换为Car，而不是c.ModelName。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1370657|试着：|1370658|vehicleList.OrderBy(c+=>+((Car)c).ModelName)|code-block|syntax|javascript|1370659|entityMap^0|4|1|8|3|F|B|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@$9|P|A|Q|B|C]|$9|R|A|S|B|C]|$9|T|A|U|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|V|8|@]|D|@]|E|$]]|$1|H|3|I|5|J|7|W|8|@]|D|@]|E|$K|L]]|$1|M|3|-4|5|6|7|X|8|@]|D|@]|E|$]]]|N|$]]

You have to cast <code>c</code> into a <code>Car</code>, not <code>c.ModelName</code>.

Try :

<pre><code>vehicleList.OrderBy(c =&gt; ((Car)c).ModelName)
</code></pre>

blocks|key|1370690|text|最易读的代码是|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1370691|vehicleList.Cast<Car>().OrderBy(c+=>+c.ModelName);|code-block|syntax|javascript|1370692|当然，您也可以修复父母并编写相同的|1370693|vehicleList.OrderBy(c+=>+((Car)c).ModelName);|1370694|尽管如此，如果您的列表中有任何不是Vehicle+Car.的，则上述两种方法都会崩溃。如果这是不可能的，那为什么这不是一个List<Car>呢？|offset|length|style|BOLD|CODE|1370695|entityMap^0|0|0|0|0|H|7|P|3|U|16|H|7|P|3|1P|9|0^^$0|@$1|2|3|4|5|6|7|T|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|U|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|V|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|W|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|X|8|@$M|Y|N|Z|O|P]|$M|10|N|11|O|P]|$M|12|N|13|O|P]|$M|14|N|15|O|Q]|$M|16|N|17|O|Q]|$M|18|N|19|O|Q]]|9|@]|A|$]]|$1|R|3|-4|5|6|7|1A|8|@]|9|@]|A|$]]]|S|$]]

The most readable code that does what you want is

<pre><code>vehicleList.Cast&lt;Car&gt;().OrderBy(c =&gt; c.ModelName);
</code></pre>

while of course you could also fix the parens and write the same as

<pre><code>vehicleList.OrderBy(c =&gt; ((Car)c).ModelName);
</code></pre>

That said, both of the above will blow up if there is any <code>Vehicle</code> in your list that is not a <code>Car</code>. And if that can't happen, then why isn't that a <code>List&lt;Car&gt;</code> in the first place?

blocks|key|1575036|text|试着使用：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1575037|vehicleList.OfType<Car>().OrderBy(c=>c.ModelName)|code-block|syntax|javascript|1575038|注意:这只返回您的列表中的汽车。|1575039|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

try use:

<pre><code>vehicleList.OfType&lt;Car&gt;().OrderBy(c=&gt;c.ModelName)
</code></pre>

note: 
this returns only cars from yours list

blocks|key|1575056|text|你必须决定你想要什么：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1575057|Car实例列表或Vehicle实例列表。|offset|length|style|CODE|1575058|如果您想要一个Vehicle实例的列表，就不能按Car的属性进行排序，因为在Vehicles列表中也可能有Bus或Bicycle。|1575059|执行当前尝试的操作(转换为Car)可能会在运行时引发异常。|1575060|话虽如此，如果你坚持这样做，你必须意识到两件事：|1575061|你需要修复你的演员阵容：vehicleList.OrderBy(c+=>+((Car)c).ModelName)|ordered-list-item|1575062|需要注意的是，OrderBy没有执行就地排序。vehicleList仍将保持原来的顺序。如果希望在vehicleList中获得有序的结果，则需要将OrderBy的结果分配给它：
vehicleList+=+vehicleList.OrderBy(c+=>+((Car)c).ModelName).ToList()；|1575063|1575064|1575065|entityMap^0|0|0|3|8|7|0|7|7|O|3|12|8|1H|3|1L|7|0|D|3|0|0|C|18|0|7|7|N|B|1D|B|21|7|0|0|0^^$0|@$1|2|3|4|5|6|7|W|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|X|8|@$D|Y|E|Z|F|G]|$D|10|E|11|F|G]]|9|@]|A|$]]|$1|H|3|I|5|6|7|12|8|@$D|13|E|14|F|G]|$D|15|E|16|F|G]|$D|17|E|18|F|G]|$D|19|E|1A|F|G]|$D|1B|E|1C|F|G]]|9|@]|A|$]]|$1|J|3|K|5|6|7|1D|8|@$D|1E|E|1F|F|G]]|9|@]|A|$]]|$1|L|3|M|5|6|7|1G|8|@]|9|@]|A|$]]|$1|N|3|O|5|P|7|1H|8|@$D|1I|E|1J|F|G]]|9|@]|A|$]]|$1|Q|3|R|5|P|7|1K|8|@$D|1L|E|1M|F|G]|$D|1N|E|1O|F|G]|$D|1P|E|1Q|F|G]|$D|1R|E|1S|F|G]]|9|@]|A|$]]|$1|S|3|-4|5|6|7|1T|8|@]|9|@]|A|$]]|$1|T|3|-4|5|6|7|1U|8|@]|9|@]|A|$]]|$1|U|3|-4|5|6|7|1V|8|@]|9|@]|A|$]]]|V|$]]

You have to decide what you want to have:

A list of <code>Car</code> instances or a list of <code>Vehicle</code> instances.

If you want to have a list of <code>Vehicle</code> instances you can't order by properties of <code>Car</code>, because in a list of <code>Vehicles</code> there also could be a <code>Bus</code> or a <code>Bicycle</code>. 
Doing what you currently try (casting to <code>Car</code>) will possibly throw an exception at runtime.

Having said that, if you insist on doing it, you have to be aware of two things:

<ol>
<li>You need to fix your cast: <code>vehicleList.OrderBy(c =&gt; ((Car)c).ModelName)</code></li>
<li>You need to be aware that <code>OrderBy</code> doesn't perform an in-place sort. <code>vehicleList</code> will still be in its original ordering. If you want to have the ordered result in <code>vehicleList</code>, you need to assign the result of <code>OrderBy</code> to it:

<pre><code>vehicleList = vehicleList.OrderBy(c =&gt; ((Car)c).ModelName).ToList();
</code></pre></li>
</ol>

blocks|key|1148339|text|试试这个：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1148340|vehicleList.OrderBy(c=>((Car)c).ModelName)|code-block|syntax|javascript|1148341|但要小心，如果一件物品实际上不是一辆汽车，它就会爆炸！|1148342|一种绕过的方法是：|1148343|vehicleList.OrderBy<Vehicle,+string>(c=>
{
++++Car+car+=+c+as+Car;
++++if+(car+!=+null)
++++++++return+car.ModelName
++++else
++++++++return+"";
}|1148344|但是，如果有“非汽车”，位置将取决于空字符串相对于列表中的其他项目。|1148345|entityMap^0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|S|8|@]|9|@]|A|$]]|$1|I|3|J|5|6|7|T|8|@]|9|@]|A|$]]|$1|K|3|L|5|D|7|U|8|@]|9|@]|A|$E|F]]|$1|M|3|N|5|6|7|V|8|@]|9|@]|A|$]]|$1|O|3|-4|5|6|7|W|8|@]|9|@]|A|$]]]|P|$]]

Try this:

<pre><code>vehicleList.OrderBy(c=&gt;((Car)c).ModelName)
</code></pre>

but beware it will blow up if an item is not actually a car!

A way around that would be:

<pre><code>vehicleList.OrderBy&lt;Vehicle, string&gt;(c=&gt;
{
 Car car = c as Car;
 if (car != null)
 return car.ModelName
 else
 return "";
}
</code></pre>

But if there were 'non-cars' there position would be determined by the empty string in relation to other items in the list.

blocks|key|1148347|text|vehicleList.OfType<Car>().OrderBy(c=>c.ModelName)|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1148348|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>vehicleList.OfType&lt;Car&gt;().OrderBy(c=&gt;c.ModelName)
</code></pre>

I have classes Vehicle and class:Car is inherited from class:Vehicle as in below. I have a List which I want to sort using LINQ based on a property of Car class (not of vehicle parent class).

<pre><code>class vehicle
{
 public String Name {get; set; }
}

class Car:Vehicle
{
 public String ModelName {get; set; }
}

List&lt;Vehicle&gt; vehicleList=new List&lt;Vehicle&gt;();

Car c1 = new Car();
vechicleList.Add(c1); //s note that i am adding **Car** objects

Car c2 = new Car();
vechicleList.Add(c2);
// added 10 such Car objects
</code></pre>

Then I want to Sort vehicleList based on CarModel (which is a property of Car, not of Parent class)

I tried the below one but it does not work.

<pre><code>vehicleList.OrderBy(c =&gt; (Car)c.ModelName)
</code></pre>

Any help on how to do this?

How to cast while Sorting?

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我有类Vehicle和类:Car继承自类:Vehicle，如下所示。我有一个列表，我想使用LINQ根据Car类(而不是vehicle父类)的属性进行排序。class vehicle{    public String Name {get; set; }}class Car:Vehicle{    public Stri...

问如何在排序时进行转换？
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问如何在排序时进行转换？EN