向字符串中添加空格
向字符串中添加空格
提问于 2013-05-01 10:02:34
我试图在每个空间中添加一个空格，直到column = 0。我不知道该怎么做。
问题如下。如果你看一份报纸，你就会发现这篇文章是合情合理的。编写一个程序，读取报纸上列的宽度，然后是一行文本。对文本行进行对齐，使之与该宽度的列相匹配。当程序运行时，屏幕应该如下所示：
Enter the width of the column: 40
Enter a line of text: Good morning how are you?
12345678901234567890123456789012345678901234567890...
Good morning how are you?理由是通过计算案文中的空白数目来完成的。在上面的例子中，有4个空白。那么每个空隙都必须加上空格。额外空间的数量必须尽可能平均地分配。在上面的例子中，前三个间隙各有5个空格，最后一个间隙有4个空格。
备注：
- 如果文本比列长，则必须报告错误--不要尝试将其拆分为两行！
- 假设文本中包含多个单词。
- 注意由123456789012345678组成的标题行.这对于检查您的结果非常有用。你可以让这个标题行，只要你愿意-70个空格将是一个有用的长度。
谢谢
#include <stdio.h>
int clear_input_buffer(void);
int column;
int c;
int g;
int e;
int space;
int length;
char line[40];
int main(){
g = 0;
printf("enter width of column\n");
scanf("%d", &column);
printf("enter line of text\n");
clear_input_buffer();
gets(line);
c = 0;
while(c <= column){
if(g <= 9)
{
printf("%d", g);
g = g + 1;
c = c + 1;
}
else
{
g = 0;
printf("%d", g);
g = g + 1;
c = c + 1;
}
}
printf("\n%s", line);
space = 0;
length = 0;
for( e = 0; line[e] != '\0'; e++ )
{
length = length + 1;
if( line[e] == ' ' )
space = space + 1;
}
column = column - length;
for( e = 0; line[e] != '\0'; e++ )
{
if((line[e] == ' ') && (column > 0))
{
add space to here
column = column - 1;
}
}
printf("%d\n", space);
printf("%d", length);
printf("%s", line);
}
int clear_input_buffer(void) {
int ch;
while (((ch = getchar()) != EOF) && (ch != '\n')) /* void */;
return ch;
}回答 2
Stack Overflow用户
发布于 2013-05-01 11:11:13
这就是我做的。这远非理想，但你明白重点。您只需要输入条件，比如输入的字符串大于或等于40个字符，就可以跳过这个过程。
#include<stdio.h>
#include<string.h>
#include<stdlib.h>
int main(void)
{
int i = 0; // first just initialiaze stuff
char ch[40]; // memset the arrays, get the string
memset(ch, '\0', 40);
gets(ch);
int diff = 40 - strlen(ch);
int spaces = 0;
while(i<strlen(ch))
{
if(*(ch + i++) == ' ') // count the number of words/spaces between words
spaces++;
}
char finalt[40];
memset(finalt, '\0', 40);
i = 0;
diff /= spaces; // diff is the number of spaces to be added between every word
i = 0;
int j = 0; // j is for the finalt array
int k = 0; // k counts through the while, to put in spaces
printf("%d\n", diff);
while(i<40) // just squeeze in the spaces
{
if(ch[i] == ' ') {while(k<diff){ finalt[j++] = ' '; k++;} k = 0;}
else {finalt[j] = ch[i]; j++;}
i++;
}
printf("%s\n", finalt); // print the result
return 0;
}Stack Overflow用户
发布于 2013-05-01 11:52:54
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#define WIDTH 70
#define _(x) #x
#define str(x) _(x)
void ruler_print(int n){
char ruler[] = "1234567890";
while(n>9){
printf(ruler);
n -= 10;
}
ruler[n] = '\0';
printf("%s\n", ruler);
}
int count_word(const char *text, size_t *count_char){
int i;
char *wk, *p;
p=wk=strdup(text);
*count_char=0;
for(i=0;p=strtok(p, " ");++i,p=NULL){
*count_char+=strlen(p);
}
free(wk);
return i;
}
int main(void){
int column, len, word_count;
int i, spaces, between, remain;
size_t count_char;
char text[WIDTH + 1];
char *p = text;
printf("Enter the width of the column: ");scanf("%d%*c", &column);
printf("Enter a line of text: ");scanf("%" str(WIDTH) "[^\n]", text);
len=strlen(text);
if(len > column || len > WIDTH){
fprintf(stderr, "too long text!\n");
return -1;
}
ruler_print(WIDTH);
word_count = count_word(text, &count_char);
spaces = column - count_char;
between = spaces / (word_count -1);
remain = spaces - (word_count -1)*between;
strtok(text, " ");
for(i=0;i<word_count-1;++i){
printf("%s%*s", p, between + (remain ? 1 : 0), " ");
if(remain) --remain;
p=strtok(NULL, " ");
}
printf("%s\n", p);
return 0;
}页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/16316144
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