按父消息原始消息分组的消息答案
按父消息原始消息分组的消息答案
提问于 2013-06-13 15:01:47
我需要按以下消息的答案对消息进行分组：
- 消息id =1
- 消息应答id =2/父消息id =1
- 消息应答id =3/父消息id =1
- 消息应答id =4/父消息id =1
- 消息id =5
- 消息应答id =6/父消息id =5
- 消息应答id =7/父消息id =5
- 消息应答id =8/父消息id =5
信息模型：
public class Message
{
// Primary properties
public int Id { get; set; }
public string NameFrom { get; set; }
public string EmailFrom { get; set; }
public string TelephoneFrom { get; set; }
public string NameTo { get; set; }
public string EmailTo { get; set; }
public string TelephoneTo { get; set; }
public string Title { get; set; }
public string MessageText { get; set; }
public bool? Approved { get; set; }
public DateTime DateCreated { get; set; }
public DateTime? DateRead { get; set; }
// Navigation properties
public Member MemberFrom { get; set; }
public Member MemberTo { get; set; }
public MessageType MessageType { get; set; }
public Message MessageParent { get; set; }
public Ad Ad { get; set; }
public Ask Ask { get; set; }
}若要在视图中显示它，请执行以下操作：
@foreach (var item in Model)
{
<div class="message_link_container" id="linkmessage_@item.Id">
<ul class="estr_message" id="estrmessage_@item.Id">
<li id="email_@item.Id">
<p>@if(item.MessageParent_Id == 0){ if(string.IsNullOrEmpty(item.NameFrom)) { @item.EmailFrom } else { @item.NameFrom } }</p>
</li>
<li id="title_@item.Id">
<p>@item.Title</p>
</li>
<li id="date_@item.Id">
<p>@item.DateCreated</p>
</li>
</ul>
</div>
}回答 1
Stack Overflow用户
回答已采纳
发布于 2013-06-18 21:24:46
var model=Messages
.OrderBy(o=>o.MessageParent_Id==0?Id:o.MessageParent_Id)
.ThenBy(o=>o.Id);页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/17090454
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