我准备了一个sql查询,以获得一个简单论坛的最新主题,我有以下规定:
CREATE TABLE IF NOT EXISTS `f_categoria` (
`id_categoria` int(4) NOT NULL,
`name` varchar(20) NOT NULL,
`desc` varchar(50) NOT NULL,
`id_foro` int(3) NOT NULL,
`estado` int(1) NOT NULL,
`visibilidad` int(2) NOT NULL,
PRIMARY KEY (`id_categoria`),
KEY `id_categoria` (`id_categoria`),
KEY `id_foro` (`id_foro`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8;
INSERT INTO `f_categoria` (`id_categoria`, `name`, `desc`, `id_foro`, `estado`, `visibilidad`) VALUES
(1, 'Programacion', 'Programacion', 1, 1, 1),
(2, 'Modelado', 'Modeladoen 3d', 1, 1, 1);
-- --------------------------------------------------------
CREATE TABLE IF NOT EXISTS `f_comentario` (
`id_comentario` bigint(20) NOT NULL AUTO_INCREMENT,
`id_post` bigint(20) NOT NULL,
`id_user` bigint(20) NOT NULL,
`contenido` longtext NOT NULL,
`number` int(4) NOT NULL,
`fecha` timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (`id_comentario`),
KEY `id_post` (`id_post`),
KEY `id_user` (`id_user`),
) ENGINE=InnoDB DEFAULT CHARSET=utf8 AUTO_INCREMENT=4 ;
INSERT INTO `f_comentario` (`id_comentario`, `id_post`, `id_user`, `contenido`, `number`, `fecha`) VALUES
(1, 1, 1, 'Este es el primer comentario', 1, '2013-07-30 23:12:53'),
(2, 1, 1, 'Este es el comentario 2', 2, '2013-07-30 23:25:12'),
(3, 2, 1, 'cOMENTARIO EN EL POST2', 1, '2013-07-30 23:53:44');
-- --------------------------------------------------------
CREATE TABLE IF NOT EXISTS `f_foro` (
`id_foro` int(5) NOT NULL,
`name` varchar(15) NOT NULL,
`desc` varchar(50) NOT NULL,
`visibilidad` int(2) NOT NULL,
PRIMARY KEY (`id_foro`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8;
INSERT INTO `f_foro` (`id_foro`, `name`, `desc`, `visibilidad`) VALUES
(1, 'Prueba', 'Foro de prueba', 1);
-- --------------------------------------------------------
CREATE TABLE IF NOT EXISTS `f_post` (
`id_post` bigint(20) NOT NULL AUTO_INCREMENT,
`id_user` bigint(20) NOT NULL,
`titulo` varchar(50) NOT NULL,
`contenido` longtext NOT NULL,
`fecha` timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP,
`estado` int(1) NOT NULL,
`id_categoria` int(4) NOT NULL,
PRIMARY KEY (`id_post`),
KEY `id_user` (`id_user`),
KEY `id_categoria` (`id_categoria`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8 AUTO_INCREMENT=4 ;
INSERT INTO `f_post` (`id_post`, `id_user`, `titulo`, `contenido`, `fecha`, `estado`, `id_categoria`) VALUES
(1, 1, '¡Hola!', 'mensaje de prueba', '2013-07-30 23:12:05', 1, 1),
(2, 1, 'post 2', 'es el post2', '2013-07-30 23:27:25', 1, 2),
(3, 1, 'post3', 'el post3', '2013-07-31 00:04:52', 1, 1);
-- --------------------------------------------------------
CREATE TABLE IF NOT EXISTS `f_user` (
`id_user` bigint(20) NOT NULL AUTO_INCREMENT,
`name` varchar(15) NOT NULL,
`mail` varchar(50) NOT NULL,
`fecha` timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (`id_user`),
UNIQUE KEY `name` (`name`,`mail`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8 AUTO_INCREMENT=2 ;
--
-- Volcado de datos para la tabla `f_user`
--
INSERT INTO `f_user` (`id_user`, `name`, `mail`, `fecha`) VALUES
(1, 'tulipo', 'f673150@rmqkr.net', '2013-07-30 23:07:36');
ALTER TABLE `f_categoria`
ADD CONSTRAINT `f_categoria_ibfk_1` FOREIGN KEY (`id_foro`) REFERENCES `f_foro` (`id_foro`);
ALTER TABLE `f_comentario`
ADD CONSTRAINT `f_comentario_ibfk_2` FOREIGN KEY (`id_user`) REFERENCES `f_user` (`id_user`),
ADD CONSTRAINT `f_comentario_ibfk_1` FOREIGN KEY (`id_post`) REFERENCES `f_post` (`id_post`);
ALTER TABLE `f_post`
ADD CONSTRAINT `f_post_ibfk_2` FOREIGN KEY (`id_categoria`) REFERENCES `f_categoria` (`id_categoria`),
ADD CONSTRAINT `f_post_ibfk_1` FOREIGN KEY (`id_user`) REFERENCES `f_user` (`id_user`);
如何进行查询以检索最近的帖子,但考虑到最后的评论呢?
这给了我最新的评论。
select id_post,id_user,contenido,fecha from f_comentario group by id_post order by fecha DESC
最后一篇文章,
select id_post,id_user,contenido,fecha from f_post order by fecha DESC
我必须加入这两个查询,然后按最近的10个id_post (日期).
有人帮过我吗?谢谢,问候
发布于 2013-08-02 13:53:49
如果我误解了你,但你要找的是评论表中的10个最新的id_post,id_user,contenido,if,它是在什么时候被评论的,而不是帖子是什么时候发布的?
select TOP 10 f_com.id_post, f_com.id_user, f_pos.contenido, f_com.contenido, f_com.fecha
from f_comentario f_com
inner join f_post f_pos
on f_pos.id_post = f_com.id_post
order by fecha DESC
这将给出存储在f_comentario表中的值。我想这就是你想要的。要理解你想做什么有点困难,因为我不能理解表名等等。我希望这会有所帮助。
附注:同样,您可以使用类似的联接来获取用户名,而不是用户id,如果post id.
https://stackoverflow.com/questions/17988552
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