blocks|key|1639656|text|试着像|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1639657|var+hasName+=+'N';
if+(name+==+"true")+{
++++hasName+=+'Y';
}|code-block|syntax|javascript|1639658|或者甚至尝试使用ternary+operator，比如|offset|length|style|CODE|1639659|var+hasName+=+(name+==+"true")+?+"Y"+:+"N"+;|1639660|即使简单的你也可以尝试|1639661|var+hasName+=+(name)+?+"Y"+:+"N"+;|1639662|因为name有Yes或No，但我对它不确定。|1639663|entityMap^0|0|0|8|G|0|0|0|0|7|3|B|2|0^^$0|@$1|2|3|4|5|6|7|W|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|X|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Y|8|@$I|Z|J|10|K|L]]|9|@]|A|$]]|$1|M|3|N|5|D|7|11|8|@]|9|@]|A|$E|F]]|$1|O|3|P|5|6|7|12|8|@]|9|@]|A|$]]|$1|Q|3|R|5|D|7|13|8|@]|9|@]|A|$E|F]]|$1|S|3|T|5|6|7|14|8|@$I|15|J|16|K|L]|$I|17|J|18|K|L]]|9|@]|A|$]]|$1|U|3|-4|5|6|7|19|8|@]|9|@]|A|$]]]|V|$]]

Try like

<pre><code>var hasName = 'N';
if (name == "true") {
 hasName = 'Y';
}
</code></pre>

Or even try with <code>ternary operator</code> like

<pre><code>var hasName = (name == "true") ? "Y" : "N" ;
</code></pre>

Even simply you can try like

<pre><code>var hasName = (name) ? "Y" : "N" ;
</code></pre>

Since name has either <code>Yes</code> or <code>No</code> but iam not sure with it.

blocks|key|562968|text|您可以使用对象作为地图：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|562969|++var+hasName+=+({
++++++++"true"++:+"Y",
++++++++"false"+:+"N"
++})[name];|code-block|syntax|javascript|562970|对于许多选项来说，这也是很好的扩展。|562971|++var+hasName+=+({
++++++++"true"++++++++++:+"Y",
++++++++"false"+++++++++:+"N",
++++++++"fileNotFound"++:+"O"
++})[name];|562972|(获得推荐信的人加分)|562973|注意:对于指示真值的变量，您应该使用实际的布尔值而不是字符串值"true“。|562974|entityMap^0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|S|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|U|8|@]|9|@]|A|$]]|$1|M|3|N|5|6|7|V|8|@]|9|@]|A|$]]|$1|O|3|-4|5|6|7|W|8|@]|9|@]|A|$]]]|P|$]]

You can use an object as a map:

<pre><code> var hasName = ({
 "true" : "Y",
 "false" : "N"
 })[name];
</code></pre>

This also scales nicely for many options

<pre><code> var hasName = ({
 "true" : "Y",
 "false" : "N",
 "fileNotFound" : "O"
 })[name];
</code></pre>

(Bonus point for people getting the reference)

Note: you should use actual booleans instead of the string value "true" for your variables indicating truth values.

blocks|key|2960278|text|尝尝这个|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2960279|hasName+=+name+?+'Y'+:+'N';|code-block|syntax|javascript|2960280|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Try this 

<pre><code>hasName = name ? 'Y' : 'N';
</code></pre>

blocks|key|563086|text|这里的大多数答案都会很好，如果你只有two条件在你的if+-否则。要了解更多信息--我猜您想要的是什么--将使用数组。在names数组中，每个名称对应的元素都将在hasNames数组中有一个元素，该元素的索引与完全相同。那就是这四条线的问题。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|BOLD|entityRanges|data|563087|names+=+"true";
var+names+=+["true","false","1","2"];
var+hasNames+=+["Y","N","true","false"];
var+intIndex+=+names.indexOf(name);
hasName+=+hasNames[intIndex+];|code-block|syntax|javascript|563088|该方法还可以使用对象和属性作为本杰明插图来实现。|563089|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/a/18269354/903324^0|I|3|1O|5|29|8|2U|3|0|0|F|5|0|0^^$0|@$1|2|3|4|5|6|7|V|8|@$9|W|A|X|B|C]|$9|Y|A|Z|B|C]|$9|10|A|11|B|C]|$9|12|A|13|B|D]]|E|@]|F|$]]|$1|G|3|H|5|I|7|14|8|@]|E|@]|F|$J|K]]|$1|L|3|M|5|6|7|15|8|@]|E|@$9|16|A|17|1|18]]|F|$]]|$1|N|3|-4|5|6|7|19|8|@]|E|@]|F|$]]]|O|$P|$5|Q|R|S|F|$T|U]]]]

Most answers here will work fine if you have just <code>two</code> conditions in your if-else. For more which is I guess what you want, you'll be using arrays.
Every names corresponding element in <code>names</code> array you'll have an element in the <code>hasNames</code> array with the exact same index. Then it's a matter of these four lines.

<pre><code>names = "true";
var names = ["true","false","1","2"];
var hasNames = ["Y","N","true","false"];
var intIndex = names.indexOf(name);
hasName = hasNames[intIndex ];
</code></pre>

This method could also be implemented using Objects and properties as <a href="https://stackoverflow.com/a/18269354/903324">illustrated by Benjamin</a>.

blocks|key|563107|text|尝试这种方法；|type|unstyled|depth|inlineStyleRanges|entityRanges|data|563108|速记法：|563109|​|563110|let+variable1+=+'';

let+variable2+=+variable1+%7C%7C+'new'
console.log(variable2);+//+new|code-block|syntax|javascript|563111|563112|远距离法：|563113|563114|+let+variable1+=+'ya';
+let+varibale2;

+if+(variable1+!==+null+%7C%7C+variable1+!==+undefined+%7C%7C+variable1+!==+'')
+++++++variable2+=+variable1;

console.log(variable2);+//+ya|563115|563116|entityMap^0|0|0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|T|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|U|8|@]|9|@]|A|$]]|$1|D|3|E|5|6|7|V|8|@]|9|@]|A|$]]|$1|F|3|G|5|H|7|W|8|@]|9|@]|A|$I|J]]|$1|K|3|E|5|6|7|X|8|@]|9|@]|A|$]]|$1|L|3|M|5|6|7|Y|8|@]|9|@]|A|$]]|$1|N|3|E|5|6|7|Z|8|@]|9|@]|A|$]]|$1|O|3|P|5|H|7|10|8|@]|9|@]|A|$I|J]]|$1|Q|3|E|5|6|7|11|8|@]|9|@]|A|$]]|$1|R|3|-4|5|6|7|12|8|@]|9|@]|A|$]]]|S|$]]

Try this method;

Shorthand method:

<div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>let variable1 = '';

let variable2 = variable1 || 'new'
console.log(variable2); // new</code></pre>
</div>
</div>


Longhand method:

<div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code> let variable1 = 'ya';
 let varibale2;

 if (variable1 !== null || variable1 !== undefined || variable1 !== '')
 variable2 = variable1;

console.log(variable2); // ya</code></pre>
</div>
</div>

blocks|key|1639884|text|?：操作员|type|unstyled|depth|inlineStyleRanges|offset|length|style|BOLD|entityRanges|data|1639885|如果要缩短If/else，可以将?:运算符用作：|CODE|1639886|condition+?+action-on-true+:+action-on-false(else)|code-block|syntax|javascript|1639887|例如：|1639888|let+gender+=+isMale+?+'Male'+:+'Female';|1639889|在这种情况下，else部件是强制性的。|1639890|我看到这种简短的手动格式用于空/未定义检查，如下所示：|1639891|const+avatarName+=+user.firstname+?+user.firstname+:+user.lastname;|1639892|但是，在这种情况下，您可以简单地使用：|1639893|const+avatarName+=+user.firstname+??+user.lastname;|1639894|或|1639895|const+avatarName+=+user.firstname+%7C%7C+user.lastname;|1639896|要查看差异，请检查它|1639897|&&运算符|1639898|在另一种情况下，如果您只有if条件，则可以将&&运算符用作：|1639899|condition+&&+action;|1639900|1639901|!this.settings+&&+(this.settings+=+new+TableSettings());|1639902|FYI:您必须尽量避免使用if-否则，或者至少减少使用它，并尝试用多态或继承替换它。去做反If吧。|1639903|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/questions/61480993/when-should-i-use-nullish-coalescing-vs-logical-or|1|https://refactoring.guru/replace-conditional-with-polymorphism#:%257E:text=In%2520them%252C%2520create%2520a%2520shared,depending%2520on%2520the%2520object%2520class.|2|https://francescocirillo.com/pages/anti-if-campaign^0|0|5|0|5|7|G|2|0|0|0|0|7|4|0|0|0|0|0|0|0|9|1|0|0|0|5|0|D|2|M|2|0|0|0|0|X|2|1|18|3|2|0^^$0|@$1|2|3|4|5|6|7|1U|8|@$9|1V|A|1W|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|1X|8|@$9|1Y|A|1Z|B|H]|$9|20|A|21|B|H]]|D|@]|E|$]]|$1|I|3|J|5|K|7|22|8|@]|D|@]|E|$L|M]]|$1|N|3|O|5|6|7|23|8|@]|D|@]|E|$]]|$1|P|3|Q|5|K|7|24|8|@]|D|@]|E|$L|M]]|$1|R|3|S|5|6|7|25|8|@$9|26|A|27|B|H]]|D|@]|E|$]]|$1|T|3|U|5|6|7|28|8|@]|D|@]|E|$]]|$1|V|3|W|5|K|7|29|8|@]|D|@]|E|$L|M]]|$1|X|3|Y|5|6|7|2A|8|@]|D|@]|E|$]]|$1|Z|3|10|5|K|7|2B|8|@]|D|@]|E|$L|M]]|$1|11|3|12|5|6|7|2C|8|@]|D|@]|E|$]]|$1|13|3|14|5|K|7|2D|8|@]|D|@]|E|$L|M]]|$1|15|3|16|5|6|7|2E|8|@]|D|@$9|2F|A|2G|1|2H]]|E|$]]|$1|17|3|18|5|6|7|2I|8|@$9|2J|A|2K|B|C]]|D|@]|E|$]]|$1|19|3|1A|5|6|7|2L|8|@$9|2M|A|2N|B|H]|$9|2O|A|2P|B|H]]|D|@]|E|$]]|$1|1B|3|1C|5|K|7|2Q|8|@]|D|@]|E|$L|M]]|$1|1D|3|O|5|6|7|2R|8|@]|D|@]|E|$]]|$1|1E|3|1F|5|K|7|2S|8|@]|D|@]|E|$L|M]]|$1|1G|3|1H|5|6|7|2T|8|@]|D|@$9|2U|A|2V|1|2W]|$9|2X|A|2Y|1|2Z]]|E|$]]|$1|1I|3|-4|5|6|7|30|8|@]|D|@]|E|$]]]|1J|$1K|$5|1L|1M|1N|E|$1O|1P]]|1Q|$5|1L|1M|1N|E|$1O|1R]]|1S|$5|1L|1M|1N|E|$1O|1T]]]]

?: Operator
If you want to shorten <code>If/else</code> you can use <code>?:</code> operator as:
<pre><code>condition ? action-on-true : action-on-false(else)
</code></pre>
For instance:
<pre><code>let gender = isMale ? 'Male' : 'Female';
</code></pre>
In this case <code>else</code> part is mandatory.
I see this kinda short hand format use for null/undefined checking like:
<pre><code>const avatarName = user.firstname ? user.firstname : user.lastname;
</code></pre>
However in this case you can simply use:
<pre><code>const avatarName = user.firstname ?? user.lastname;
</code></pre>
or
<pre><code>const avatarName = user.firstname || user.lastname;
</code></pre>
To see the difference check <a href="https://stackoverflow.com/questions/61480993/when-should-i-use-nullish-coalescing-vs-logical-or">it</a> out
&amp;&amp; Operator
In another case, if you have only <code>if</code> condition you can use <code>&amp;&amp;</code> operator as:
<pre><code>condition &amp;&amp; action;
</code></pre>
For instance:
<pre><code>!this.settings &amp;&amp; (this.settings = new TableSettings());
</code></pre>
FYI: You have to try to avoid using if-else or at least decrease using it and try to replace it with <a href="https://refactoring.guru/replace-conditional-with-polymorphism#:%7E:text=In%20them%2C%20create%20a%20shared,depending%20on%20the%20object%20class." rel="nofollow noreferrer">Polymorphism</a> or Inheritance. Go for being <a href="https://francescocirillo.com/pages/anti-if-campaign" rel="nofollow noreferrer">Anti-If</a> guy.

blocks|key|1639956|text|试试这个|type|unstyled|depth|inlineStyleRanges|offset|length|style|BOLD|entityRanges|data|1639957|​|1639958|var+name+=+"true";
var+hashname;
+++++name
++++++?+hashname+=+"Y"
++++++:+!name
+++++++?+hashname+=+"N"
+++++++:+""

+++++console.log(hashname)|code-block|syntax|javascript|1639959|1639960|entityMap^0|0|4|0|0|0|0^^$0|@$1|2|3|4|5|6|7|P|8|@$9|Q|A|R|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|S|8|@]|D|@]|E|$]]|$1|H|3|I|5|J|7|T|8|@]|D|@]|E|$K|L]]|$1|M|3|G|5|6|7|U|8|@]|D|@]|E|$]]|$1|N|3|-4|5|6|7|V|8|@]|D|@]|E|$]]]|O|$]]

Try This
<div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>var name = "true";
var hashname;
 name
 ? hashname = "Y"
 : !name
 ? hashname = "N"
 : ""

 console.log(hashname)</code></pre>
</div>
</div>

I have some code with a lot of if/else statements similar to this:

<pre><code>var name = "true";

if (name == "true") {
 var hasName = 'Y';
} else if (name == "false") {
 var hasName = 'N';
};
</code></pre>

But is there a way to make these statements shorter? Something like <code>? "true" : "false"</code> ...

Shorthand for if-else statement

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我有一些代码，其中有很多if/ with语句，类似于以下内容：var name = "true";if (name == "true") {    var hasName = 'Y';} else if (name == "false") {    var hasName = 'N';};但有没有办法让这些陈述更简短呢...

问if- for语句的简写
EN

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问if- for语句的简写
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