视图中的2种不同搜索
视图中的2种不同搜索
提问于 2013-08-31 19:49:34
我有两个表，一个是从病历中存储信息，另一个是第二次医疗咨询，我想要的是搜索，如果病人进行了第二次医疗咨询，在我的模板中显示了第二次医疗咨询的信息，如果病人没有第二次医疗会诊，只向我显示病历的信息。我需要帮助和想法，我是Django和Python的新手，我用以下的方式进行搜索，问题是我只看到了病历，如果病人需要第二次医疗咨询来显示信息的话。
View.py
def Expediente_Detalle(request, credencial):
Expediente_Detalle = get_object_or_404(ExpedienteConsultaInicial, credencial_consultainicial=credencial)
return render(request, 'ExpedienteDetalle.html', {'Expediente_Detalle': Expediente_Detalle})Models.py
class ExpedienteConsultaInicial(models.Model):
credencial_consultainicial = models.CharField(max_length=10, null=True, blank=True)
def __unicode__(self):
return self.credencial_consultainicial
class ConsultasSubsecuentes(models.Model):
Consultasbc_credencial =models.ForeignKey(ExpedienteConsultaInicial,
related_name='csb_credencial')回答 2
Stack Overflow用户
回答已采纳
发布于 2013-09-01 12:29:21
尝试：
#Models
class ExpedienteConsultaInicial(models.Model):
#max_legth=10 might be too small
credencial_consultainicial = models.CharField(max_length=100, null=True, blank=True)
def __unicode__(self):
return self.credencial_consultainicial
class ConsultasSubsecuentes(models.Model):
#related_name is name of attribute of instance of model
#to (not from!) which ForeignKey points.
#Like:
#assuming that `related_name` is 'consultations'
#instance = ExpedienteConsultaInicial.objects.get(
# credencial_consultainicial='text text text'
#)
#instaqnce.consultations.all()
#So I suggest to change `related_name` to something that will explain what data of this model means in context of model to which it points with foreign key.
consultasbc_credencial = models.ForeignKey(ExpedienteConsultaInicial,
related_name='consultations')
#View
def expediente_detalle(request, credencial):
#Another suggestion is to not abuse CamelCase - look for PEP8
#It is Python's code-style guide.
detalle = get_object_or_404(ExpedienteConsultaInicial, credencial_consultainicial=credencial)
subsequent_consultations = detalle.csb_credencial.all()
return render(request, 'ExpedienteDetalle.html', {'Expediente_Detalle': detalle, 'consultations': subsequent_consultations})有用的链接：
- 向后跟踪关系 -这就是我建议你改变
related_name的原因 - PEP8 -这是关于CamelCase和Python的代码风格的。
Stack Overflow用户
发布于 2013-09-01 12:23:20
您需要做的就是执行另一个查询，并将结果提供给模板。
def Expediente_Detalle(request, credencial):
Expediente_Detalle = get_object_or_404(ExpedienteConsultaInicial, credencial_consultainicial=credencial)
second_consultation = ExpedienteConsultaInicial.objects.filter(..)
return render(request, 'ExpedienteDetalle.html', {'Expediente_Detalle': Expediente_Detalle, 'second_consultation': second_consultation})然后，在模板中，在second_consultation上迭代
{% for c in second_consultation %}
<p> {{ c.credencial_consultainicial }} </p>
{% endfor %}页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/18552166
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