blocks|key|56257|text|这个函数按你的要求做。它假定没有使用负数，否则需要进行一些更改来支持这种情况。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|56258|def+mixrange(s):
++++r+=+[]
++++for+i+in+s.split(','):
++++++++if+'-'+not+in+i:
++++++++++++r.append(int(i))
++++++++else:
++++++++++++l,h+=+map(int,+i.split('-'))
++++++++++++r%2B=+range(l,h%2B1)
++++return+r


print+mixrange('1-3,6,8-10')|code-block|syntax|javascript|56259|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

This function does what you asked. It assumes no negative numbers are used, otherwise it needs some changes to support that case.

<pre><code>def mixrange(s):
 r = []
 for i in s.split(','):
 if '-' not in i:
 r.append(int(i))
 else:
 l,h = map(int, i.split('-'))
 r+= range(l,h+1)
 return r


print mixrange('1-3,6,8-10')
</code></pre>

blocks|key|2037104|text|一种使用列表理解的方法：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2037105|s+=+"1-3,6,8-10"
x+=+[ss.split('-')+for+ss+in+s.split(',')]
x+=+[range(int(i[0]),int(i[1])%2B1)+if+len(i)+==+2+else+i+for+i+in+x]
print([int(item)+for+sublist+in+x+for+item+in+sublist])|code-block|syntax|javascript|2037106|产出：|2037107|[1,+2,+3,+6,+8,+9,+10]|2037108|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

One way using list comprehensions:

<pre><code>s = "1-3,6,8-10"
x = [ss.split('-') for ss in s.split(',')]
x = [range(int(i[0]),int(i[1])+1) if len(i) == 2 else i for i in x]
print([int(item) for sublist in x for item in sublist])
</code></pre>

Outputs:

<pre><code>[1, 2, 3, 6, 8, 9, 10]
</code></pre>

blocks|key|56268|text|没有内置功能，但可以使用xrange和生成器来完成：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|56269|from+itertools+import+chain

s+=+"1-3,6,8-10"
spans+=+(el.partition('-')[::2]+for+el+in+s.split(','))
ranges+=+(xrange(int(s),+int(e)+%2B+1+if+e+else+int(s)+%2B+1)+for+s,+e+in+spans)
all_nums+=+chain.from_iterable(ranges)+#+loop+over,+or+materialse+using+`list`
#+[1,+2,+3,+6,+8,+9,+10]|code-block|syntax|javascript|56270|entityMap^0|C|6|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|P|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Q|8|@]|D|@]|E|$]]]|L|$]]

No builtin function as such, but can be done using <code>xrange</code> and generators:

<pre><code>from itertools import chain

s = "1-3,6,8-10"
spans = (el.partition('-')[::2] for el in s.split(','))
ranges = (xrange(int(s), int(e) + 1 if e else int(s) + 1) for s, e in spans)
all_nums = chain.from_iterable(ranges) # loop over, or materialse using `list`
# [1, 2, 3, 6, 8, 9, 10]
</code></pre>

blocks|key|56435|text|s+=+'1-3,6,8-10,13-16'
temp+=+[x.split('-')+if+'-'+in+x+else+x+for+x+in+s.split(',')]
#+temp+=+[['1',+'3'],+'6',+['8',+'10'],+['13',+'16']]
res+=+[]
for+l+in+temp:
++++if+isinstance(l,+list):
++++++++a,+b+=+map(int,+l)
++++++++res+%2B=+list(range(a,+b+%2B+1))
++++else:
++++++++res.append(int(l))

+#+res+=+[1,+2,+3,+6,+8,+9,+10,+13,+14,+15,+16]|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|56436|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>s = '1-3,6,8-10,13-16'
temp = [x.split('-') if '-' in x else x for x in s.split(',')]
# temp = [['1', '3'], '6', ['8', '10'], ['13', '16']]
res = []
for l in temp:
 if isinstance(l, list):
 a, b = map(int, l)
 res += list(range(a, b + 1))
 else:
 res.append(int(l))

 # res = [1, 2, 3, 6, 8, 9, 10, 13, 14, 15, 16]
</code></pre>

blocks|key|56416|text|我刚刚创建了一个小函数：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|56417|def+expand(st):
++++res+=+[]
++++for+item+in+st.split(','):
++++++++if+'-'+in+item:
++++++++++++temp+=+map(int,+item.split('-'))
++++++++++++res.extend(range(temp[0],+temp[1]%2B1))
++++++++else:
++++++++++++res.append(int(item))
++++return+res

s+=+'1-3,6,8-10'
print+expand(s)|code-block|syntax|javascript|56418|返回：|56419|[1,+2,+3,+6,+8,+9,+10]|56420|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

A little function I just created:

<pre><code>def expand(st):
 res = []
 for item in st.split(','):
 if '-' in item:
 temp = map(int, item.split('-'))
 res.extend(range(temp[0], temp[1]+1))
 else:
 res.append(int(item))
 return res

s = '1-3,6,8-10'
print expand(s)
</code></pre>

Returns:

<pre><code>[1, 2, 3, 6, 8, 9, 10]
</code></pre>

blocks|key|56243|text|def+parseIntSet(nputstr=""):
++selection+=+set()
++invalid+=+set()
++#+tokens+are+comma+seperated+values
++tokens+=+[x.strip()+for+x+in+nputstr.split(',')]
++for+i+in+tokens:
+++++try:
++++++++#+typically+tokens+are+plain+old+integers
++++++++selection.add(int(i))
+++++except:
++++++++#+if+not,+then+it+might+be+a+range
++++++++try:
+++++++++++token+=+[int(k.strip())+for+k+in+i.split('-')]
+++++++++++if+len(token)+>+1:
++++++++++++++token.sort()
++++++++++++++#+we+have+items+seperated+by+a+dash
++++++++++++++#+try+to+build+a+valid+range
++++++++++++++first+=+token[0]
++++++++++++++last+=+token[len(token)-1]
++++++++++++++for+x+in+range(first,+last%2B1):
+++++++++++++++++selection.add(x)
++++++++except:
+++++++++++#+not+an+int+and+not+a+range...
+++++++++++invalid.add(i)
++#+Report+invalid+tokens+before+returning+valid+selection
++print+"Invalid+set:+"+%2B+str(invalid)
++return+selection|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|56244|Via：解析Python中的数字列表|unstyled|offset|length|56245|entityMap|0|LINK|mutability|MUTABLE|url|http://thoughtsbyclayg.blogspot.com/2008/10/parsing-list-of-numbers-in-python.html^0|0|4|E|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|R|8|@]|9|@$G|S|H|T|1|U]]|A|$]]|$1|I|3|-4|5|F|7|V|8|@]|9|@]|A|$]]]|J|$K|$5|L|M|N|A|$O|P]]]]

<pre><code>def parseIntSet(nputstr=""):
 selection = set()
 invalid = set()
 # tokens are comma seperated values
 tokens = [x.strip() for x in nputstr.split(',')]
 for i in tokens:
 try:
 # typically tokens are plain old integers
 selection.add(int(i))
 except:
 # if not, then it might be a range
 try:
 token = [int(k.strip()) for k in i.split('-')]
 if len(token) &gt; 1:
 token.sort()
 # we have items seperated by a dash
 # try to build a valid range
 first = token[0]
 last = token[len(token)-1]
 for x in range(first, last+1):
 selection.add(x)
 except:
 # not an int and not a range...
 invalid.add(i)
 # Report invalid tokens before returning valid selection
 print "Invalid set: " + str(invalid)
 return selection
</code></pre>

Via: <a href="http://thoughtsbyclayg.blogspot.com/2008/10/parsing-list-of-numbers-in-python.html" rel="nofollow">Parsing a list of numbers in Python</a>

blocks|key|2037130|text|啊哈，有一个概念的证明吗？|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2037131|编辑:改进版本|2037132|import+itertools
s+=+"1-3,6,8-10"

print(list(itertools.chain.from_iterable(range(int(ranges[0]),+int(ranges[1])%2B1)+for+ranges+in+((el%2B[el[0]])[:2]+for+el+in+(miniRange.split('-')+for+miniRange+in+s.split(','))))))|code-block|syntax|javascript|2037133|现在，为了提高可读性，可以在几行代码中拆分：|2037134|print(list(itertools.chain.from_iterable(
++++range(
++++++++int(ranges[0]),
++++++++int(ranges[1])%2B1
++++)
++++for+ranges+in+
++++++++(
++++++++++++(el%2B[el[0]])[:2]+#+Allows+to+get+rid+of+the+ternary+condition+by+always+adding+a+duplicate+of+the+first+element+if+it+is+alone
++++++++++++for+el+in
++++++++++++(miniRange.split('-')+for+miniRange+in+s.split(','))
++++++++)
)))|2037135|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|P|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|Q|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|6|7|R|8|@]|9|@]|A|$]]|$1|K|3|L|5|F|7|S|8|@]|9|@]|A|$G|H]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

Aha, one line proof of concept anyone?

EDIT: Improved version

<pre><code>import itertools
s = "1-3,6,8-10"

print(list(itertools.chain.from_iterable(range(int(ranges[0]), int(ranges[1])+1) for ranges in ((el+[el[0]])[:2] for el in (miniRange.split('-') for miniRange in s.split(','))))))
</code></pre>

Now split on several lines for readability:

<pre><code>print(list(itertools.chain.from_iterable(
 range(
 int(ranges[0]),
 int(ranges[1])+1
 )
 for ranges in 
 (
 (el+[el[0]])[:2] # Allows to get rid of the ternary condition by always adding a duplicate of the first element if it is alone
 for el in
 (miniRange.split('-') for miniRange in s.split(','))
 )
)))
</code></pre>

I am trying to add an option to my program which allow the user to choose which steps of the program he wants to do.

I would like to be able to parse a string like <code>"1-3,6,8-10"</code> and get <code>[1, 2, 3, 6, 8, 9, 10]</code>.

Do you know if something in Python which is doing that already exists ?

Expand a range which looks like: "1-3,6,8-10" to [1,2,3, 6, 8,9,10]

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我试图在我的程序中添加一个选项，允许用户选择他想要做的程序的步骤。我希望能够解析像"1-3,6,8-10"这样的字符串并获得[1, 2, 3, 6, 8, 9, 10]。您知道Python中是否已经存在这样的东西了吗？

问扩大如下范围："1-3, 6，8-10“到[1,2,3，6，8,9,10]
EN

回答 7

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问扩大如下范围："1-3, 6，8-10“到[1,2,3，6，8,9,10]EN

回答 7

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问扩大如下范围："1-3, 6，8-10“到[1,2,3，6，8,9,10]
EN