如何动态地将sql结果转换为多维数组？
如何动态地将sql结果转换为多维数组？
提问于 2013-09-14 05:22:24
这里是查询字符串.
$query = "SELECT t.id, t.assignee, t.owner,
d.code, d.status, d.target_completion_date,
d.target_extension_date, d.submission_date, d.approval_date,
d.revision_start_date, d.revision_completion_date, d.message,
ty.name, f.orig_name, f.new_name,
b.payment_date, b.discount, b.total_cost, b.amount_payed, b.edit_level,
b.billing_type, b.pages, b.words
FROM tasks t
INNER JOIN details d ON t.detail_id = d.id
INNER JOIN billing b ON t.billing_id = b.id
INNER JOIN TYPE ty ON d.document_type_id = ty.id
INNER JOIN files f ON t.file_id = f.id
WHERE t.assignee = 'argie1234'";，这是我希望查询结果转化为.的数组。
$user = array('allTask'=>array(array('taskid' => 1,
'assignee'=>'argie1234',
'owner'=>'austral1000',
'details' => array( 'code' => 'E',
'status'=>'TC',
'targetCompletionDateUTC'=>'1379401200',
'targetExtentionDateUTC'=>'1379401200',
'submissionDateUTC'=>'1379401200',
'approvalDateUTC'=>'1379401200',
'revisionStartDateUTC'=>'1379401200',
'revisionCompletionDateUTC'=>'1379401200',
'messageToEditor'=>'Please work on it asap.',
'documentType' => 'Thesis'),
'file' => array('orig_name' =>'originalname.docx',
'new_name' => 'newname.docx'),
'billing'=>array('paymentDate'=>'July 26,2013 12:40',
'discount' => '0',
'totalRevisionCharge' => '$20.00',
'totalAmountPayed' => '$20.00',
'revisionLevel' => '1',
'chargeType'=> '1',
'numPages' => '60',
'numWords' => '120,000' ) ),
array('taskid' => 12,
'assignee'=>'argie1234',
'owner'=>'usaroberto',
'details' => array( 'code' => 'E',
'status'=>'TC',
'targetCompletionDateUTC'=>'1379401200',
'targetExtentionDateUTC'=>'1379401200',
'submissionDateUTC'=>'1379401200',
'approvalDateUTC'=>'1379401200',
'revisionStartDateUTC'=>'1379401200',
'revisionCompletionDateUTC'=>'1379401200',
'messageToEditor'=>'Please work on it asap.',
'documentType' => 'Thesis'),
'file' => array('orig_name' => 'originalname.docx',
'new_name' => 'newname.docx'),
'billing'=>array('paymentDate'=>'July 26,2013 12:40',
'discount' => '0',
'totalRevisionCharge' => '$20.00',
'totalAmountPayed' => '$20.00',
'revisionLevel' => '1',
'chargeType'=> '1',
'numPages' => '60',
'numWords' => '120,000' ) ),
'account' => array( 'username' => 'marooon55',
'emailadd' => 'marooon@yahoo.com',
'firstname' => 'Maroon',
'initial' => 'E',
'lastname' => 'Young',
'country' => 'Australia',
'gender' => 'M',
'password' =>'360e2801190744a2af74ef6cbfdb963078b59709',
'activationDate' => '2013-09-13 14:30:34') );如何创建上面的数组？我确实知道如何定义多维数组，但遗憾的是，我很难动态地创建这个复杂的数组。作为一个初学者，我甚至不知道从哪里开始。
回答 3
Stack Overflow用户
发布于 2013-09-14 05:31:10
下面是一个可以帮助你解决问题的例子。尝试从简单的多维数组开始，一旦你掌握了它，你就可以开始构建复杂的数组了。然后你会发现你想要构建的数组并不比你最初想象的那么困难。
$mycomplexarray =数组(‘key1’=>数组(‘val1’，'val2')，'key2‘=>数组(’val3‘，'val4’=>数组(‘val5’，'val6') )；
Stack Overflow用户
发布于 2013-09-14 06:04:02
您可以像这里一样创建数组。我不会把整件事都写出来，但像这样的事.
$result = $mysqli->query($query); // however you query the db is up to you.
$row = $result->fetch_assoc(); //same as query use your prefered method to fetch
$user = array('allTask'=>array(array('taskid' => $row['id'],
'assignee'=>$row['assignee'],
'owner'=>$row['owner'],
'details' => array( 'code' => $row['code'],
'status'=>$row['status'],...etc，希望这对你有意义。
Stack Overflow用户
发布于 2013-09-14 06:10:09
首先设置一个结构数组，该数组定义将存储在以下子数组中的列
$struc=array('Id'->0, 'assignee'->0, 'owner'->0,
'code'->'detail', 'status'->'detail', 'target_completion_date'->'detail',
'target_extension_date'->'detail', 'submission_date'->'detail', 'approval_date'->'detail',
'revision_start_date'->'detail', 'revision_completion_date'->'detail', 'message'->'detail',
'name'->'file', 'orig_name'->'file', 'new_name'->'file',
'payment_date'->'billing', 'discount'->'billing', 'total_cost'->'billing', 'amount_payed'->'billing', 'edit_level'->'billing', 'billing_type'->'billing', 'words');在while ($a=mysqli_fetch_assoc($res))循环中，您现在可以使用此结构来决定是否要将元素直接存储在目标数组中，或者是否要将其放置在此结构数组中命名的子数组中。喜欢
$res=mysqli_query($con,$sql);
$arr=array();
while($a=mysqli_fetch_assoc($res)) {
// within result loop: $a is result from mysqli_fetch_assoc()
$ta=array(); // temp array ...
foreach ($a as $k => $v){
if ($struc[$k]) $ta[struc[$k]][$k]=$v;
else $ta[$k]=$v;
}
$arr[]=$ta; // add to target array
}这是完整的代码，不需要更多。它是在我的iPod上输入的，所以还没有经过测试。
生成的数组应该与您的$user['allTask']数组等效。
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/18798605
复制相关文章
相似问题
腾讯云开发者
