blocks|key|2077747|text|请检查您的查询|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2077748|尝试下面的一行并检查错误|2077749|$sql=+mysql_query("SELECT+*+FROM+food+ORDER+BY+id")+or+mysql_error();|code-block|syntax|javascript|2077750|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|L|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|M|8|@]|9|@]|A|$G|H]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

Do check your query 

Try the below line and check for the error

<pre><code>$sql= mysql_query("SELECT * FROM food ORDER BY id") or mysql_error();
</code></pre>

blocks|key|2077766|text|试一试|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2077767|$query+=+"SELECT+`food`,`calories`+FROM+`food`+ORDER+BY+'id'";|code-block|syntax|javascript|2077768|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

try 

<pre><code>$query = "SELECT `food`,`calories` FROM `food` ORDER BY 'id'";
</code></pre>

blocks|key|1001386|text|将查询更改为不带单引号：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1001387|$query+=+"SELECT+food,+calories+FROM+food+ORDER+BY+id";|code-block|syntax|javascript|1001388|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Change your query to this without single quotes:

<pre><code>$query = "SELECT food, calories FROM food ORDER BY id";
</code></pre>

blocks|key|77159|text|这是因为在查询中使用单引号(')。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|77160|$query+=+"SELECT+'food',+'calories'+FROM+food+ORDER+BY+'id'";|code-block|syntax|javascript|77161|此查询将提供输出如下：|77162|food+%7C+calories
-----%7C---------
food+%7C+calories
food+%7C+calories|77163|SQLFiddle|77164|单引号(')用于字符串文本。如果要转义列名，请使用backticks(`)+instesd。|77165|$query+=+"SELECT+`food`,+`calories`+FROM+food+ORDER+BY+`id`";|77166|77167|注意：请对列名和表名使用不同的名称。目前，您正在使用food作为列和表名。请避免这样做。|BOLD|77168|entityMap|0|LINK|mutability|MUTABLE|url|http://sqlfiddle.com/#!2/77997/1|1|http://sqlfiddle.com/#!2/77997/2^0|E|1|0|0|0|0|0|9|0|0|0|0|0|9|1|0|0|3|Q|4|0^^$0|@$1|2|3|4|5|6|7|18|8|@$9|19|A|1A|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|1B|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|1C|8|@]|D|@]|E|$]]|$1|M|3|N|5|H|7|1D|8|@]|D|@]|E|$I|J]]|$1|O|3|P|5|6|7|1E|8|@]|D|@$9|1F|A|1G|1|1H]]|E|$]]|$1|Q|3|R|5|6|7|1I|8|@]|D|@]|E|$]]|$1|S|3|T|5|H|7|1J|8|@]|D|@]|E|$I|J]]|$1|U|3|P|5|6|7|1K|8|@]|D|@$9|1L|A|1M|1|1N]]|E|$]]|$1|V|3|W|5|6|7|1O|8|@$9|1P|A|1Q|B|X]|$9|1R|A|1S|B|C]]|D|@]|E|$]]|$1|Y|3|-4|5|6|7|1T|8|@]|D|@]|E|$]]]|Z|$10|$5|11|12|13|E|$14|15]]|16|$5|11|12|13|E|$14|17]]]]

This is because you are using single quotes (<code>'</code>) in your query

<pre><code>$query = "SELECT 'food', 'calories' FROM food ORDER BY 'id'";
</code></pre>

This query will give output as:

<pre><code>food | calories
-----|---------
food | calories
food | calories
</code></pre>

<a href="http://sqlfiddle.com/#!2/77997/1" rel="nofollow">SQLFiddle</a>

Single quote (') is used for string literals. If you want to escape your column names use backticks(`) instesd.

<pre><code>$query = "SELECT `food`, `calories` FROM food ORDER BY `id`";
</code></pre>

<a href="http://sqlfiddle.com/#!2/77997/2" rel="nofollow">SQLFiddle</a>

Note: Please use different names for column and table name. Currently you are using <code>food</code> as column and table name. Please avoid this.

blocks|key|1001461|text|对列名和表名使用单引号(')。使用backticks(`)代替，一切都会好起来的。单引号用于php中的字符串。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1001462|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|D|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|E|8|@]|9|@]|A|$]]]|C|$]]

You are using single quote (') for column and table names. Use backticks(`) instead and everything will be fine. Single quotes are used for strings in php.

blocks|key|1001475|text|在列名和表名中使用‘而不是’，如下所示：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1001476|query=+"SELECT+`food`,+`calories`+FROM+`food`+ORDER+BY+`id`";|code-block|syntax|javascript|1001477|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Use ` instead of ' in column and table names, like this:

<pre><code>query= "SELECT `food`, `calories` FROM `food` ORDER BY `id`";
</code></pre>

I'm new to PHP and I'm trying to learn how to display data I select from a mysql database (phpmyadmin). My current php code consists of 2 files connect.inc.php and connecting.php:

conncet.inc.php is the file used to establish connection with the database:

<pre><code>&lt;?php
//Varialbles
//MYSQL details
$mysql_server='localhost';
$mysql_user='root';
$mysql_user_pass='12345678';
$mysql_db='test';

//Messages
$db_conn_error='Could not connect to database';

if(mysql_connect($mysql_server, $mysql_user, $mysql_user_pass)
and mysql_select_db($mysql_db)){
echo 'Connection is ok'.'&lt;br&gt;';
}
else
{
echo 'Connection is not ok';
}
?&gt;
</code></pre>

while the other file (connecting.php) should display any records in the particular table called food :

<pre><code>&lt;?php
require 'connect.inc.php';

$query = "SELECT 'food', 'calories' FROM food ORDER BY 'id'";


if ($query_run = mysql_query($query)){

 while($query_row = mysql_fetch_assoc($query_run)){
 $food = $query_row['food'];
 $calories = $query_row['calories'];

 echo $food . ' has '.$calories.' calories.&lt;br&gt;';
 }

}
else
{
echo 'Query Failed';
}
?&gt;
</code></pre>

Additional details:

<ul>
<li>server name : localhost</li>
<li>user : root</li>
<li>password : 12345678</li>
<li>database name : test</li>
<li>table name : food</li>
<li>field names : id, food, calories, healthy_unhealthy</li>
</ul>

Ths issue is that whenever i execute code in the file connecting.php i always get the following:

<ul>
<li>Connection is ok</li>
<li>food has calories calories.</li>
<li>food has calories calories.</li>
</ul>

When it should say

<ul>
<li>Connection is ok</li>
<li>Pizza has 1000 calories</li>
<li>Salad has 200 calories</li>
</ul>

Help is highly appreciated :)

Thanks in advance,

Joe :)

PHP - mysql_fetch_assoc() issue

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我是PHP新手，我正在学习如何显示从mysql数据库(phpmyadmin)中选择的数据。我当前的php代码由2个文件connect.inc.php和connecting.php组成：conncet.inc.php是用来与数据库建立连接的文件：<?php//Varialbles//MYSQL details$mysql...

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