如何使物体掉头而向相反的方向移动？
如何使物体掉头而向相反的方向移动？
提问于 2013-09-18 11:39:37
考虑到出界位置是6和-6。
我想让这艘船掉头朝相反的方向移动。
这是我的密码..。它仍然不能百分之百地发挥我想要的效果。我很好奇，想看看有没有人想过如何改进。这是我的代码的逻辑。
//If the ship hits a boundary it turns around and moves in the opp.
//direction. To do this, the ship's velocty should be flipped from a
//negative into a positive number, or from pos to neg if boundary
//is hit.
//if ship position is -5 at velocity -1 new ship pos is -6
//if ship position is -6 at velocity -1 new ship velocity is +1
// new ship position is +5这是我的代码：
public void move()
{
position = velocity + position;
if (position > 5)
{
velocity = -velocity;
}
else if (position < -5)
{
velocity = +velocity;
}
}回答 5
Stack Overflow用户
回答已采纳
发布于 2013-09-18 11:52:02
代码velocity = +velocity;不会将负速度改变为正速度。这相当于将速度与+1相乘，它不会改变符号。
当超出边界时，要翻转速度的符号，您需要总是乘以-1。
它不太清楚的界限是这么低，我假设他们是6和-6。
position += velocity;
//make sure the ship cannot go further than the bounds
//but also make sure that the ship doesn't stand still with large velocities
if (position > 6)
{
velocity = -velocity;
position = 6;
}
if (position < -6)
{
velocity = -velocity;
position = -6;
}Stack Overflow用户
发布于 2013-09-18 11:51:41
你可以这样做：
public void move()
{
//first check where the next move will be:
if ((position + velocity) > 5 || (position + velocity) < -5){
// Here we change direction (the velocity is multiplied for -1)
velocity *= -1;
}
position += velocity;
}Stack Overflow用户
发布于 2013-09-18 11:47:44
当它到达一个边界时，将速度乘以-1。
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/18871247
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