Json解码PHP中从返回的响应
Json解码PHP中从返回的响应
提问于 2013-09-28 17:32:10
我试着向这个网址提出一个关于披萨的定义.http://www.google.com/dictionary/json?callback=a&client=p&sl=en&tl=en&q=pizza
我最初的反应是这样的……
a({"query":"pizza","sourceLanguage":"en","targetLanguage":"en","primaries":[{"type":"headword","terms":[{"type":"text","text":"piz·za","language":"en","labels":[{"text":"Noun","title":"Part-of-speech"}]},{"type":"phonetic","text":"/ˈpÄ“tsÉ™/","language":"und"},{"type":"sound","text":"http://www.gstatic.com/dictionary/static/sounds/de/0/pizza.mp3","language":"und"}],"entries":[{"type":"related","terms":[{"type":"text","text":"pizzas","language":"und","labels":[{"text":"plural"}]}]},{"type":"meaning","terms":[{"type":"text","text":"A dish of Italian origin consisting of a flat, round base of dough baked with a topping of tomato sauce and cheese, typically with added meat or vegetables","language":"en"}]}]}]},200,null) 在搜索完互联网和stackovrflow (例如decode for Google Dictionary API)上类似的问题之后，我使用下面的代码来清理它，然后尝试解码它.
$rawdata = preg_replace("/\\\x[0-9a-f]{2}/", "", $rawdata);
$raw = explode("{",$rawdata);
unset($raw[0]);
$rawdata = implode($raw);
$raw = explode("}", $rawdata);
unset($raw[count($raw)-1]);
$rawdata = implode($raw);
$rawdata = "{". $rawdata ."}";这给了我下面那条看起来很像.
{"query":"pizza","sourceLanguage":"en","targetLanguage":"en","primaries":["type":"headword","terms":["type":"text","text":"piz·za","language":"en","labels":["text":"Noun","title":"Part-of-speech"],"type":"phonetic","text":"/ˈpÄ“tsÉ™/","language":"und","type":"sound","text":"http://www.gstatic.com/dictionary/static/sounds/de/0/pizza.mp3","language":"und"],"entries":["type":"related","terms":["type":"text","text":"pizzas","language":"und","labels":["text":"plural"]],"type":"meaning","terms":["type":"text","text":"A dish of Italian origin consisting of a flat, round base of dough baked with a topping of tomato sauce and cheese, typically with added meat or vegetables","language":"en"]]]} 但它还是不能正确解码，我很困惑.
我一直在用这个工具，http://json.parser.online.fr/说.SyntaxError:意外令牌：
我现在在想，我最初对json响应的所有黑客攻击只是让问题变得更糟，并且可能有一种更好的方法来处理最初的响应。
有人能解释一下我的问题吗？
预先感谢:D
回答 1
Stack Overflow用户
回答已采纳
发布于 2013-09-28 18:33:16
我认为这是一种过度复杂的情况。greediness的regex默认属性使得在第一个和最后一个{}之间提取完整的json主体变得很简单。
<?php
$str = 'a({"query":"pizza","sourceLanguage":"en","targetLanguage":"en","primaries":[{"type":"headword","terms":[{"type":"text","text":"piz·za","language":"en","labels":[{"text":"Noun","title":"Part-of-speech"}]},{"type":"phonetic","text":"/ˈpētsə/","language":"und"},{"type":"sound","text":"http://www.gstatic.com/dictionary/static/sounds/de/0/pizza.mp3","language":"und"}],"entries":[{"type":"related","terms":[{"type":"text","text":"pizzas","language":"und","labels":[{"text":"plural"}]}]},{"type":"meaning","terms":[{"type":"text","text":"A dish of Italian origin consisting of a flat, round base of dough baked with a topping of tomato sauce and cheese, typically with added meat or vegetables","language":"en"}]}]}]},200,null)';
if (preg_match('/\{.*\}/', $str, $matches)) {
$json = json_decode($matches[0], true);
var_dump($json);
}返回您：
array(4) {
["query"]=>
string(5) "pizza"
["sourceLanguage"]=>
string(2) "en"
["targetLanguage"]=>
string(2) "en"
["primaries"]=>
array(1) {
[0]=>
array(3) {
["type"]=>
string(8) "headword"
["terms"]=>
array(3) {
[0]=>
array(4) {
["type"]=>
string(4) "text"
["text"]=>
string(9) "piz·za"
["language"]=>
string(2) "en"
["labels"]=>
array(1) {
[0]=>
array(2) {
["text"]=>
string(4) "Noun"
["title"]=>
string(14) "Part-of-speech"
}
}
}
[1]=>
array(3) {
["type"]=>
string(8) "phonetic"
["text"]=>
string(19) "/ˈpētsə/"
["language"]=>
string(3) "und"
}
[2]=>
array(3) {
["type"]=>
string(5) "sound"
["text"]=>
string(62) "http://www.gstatic.com/dictionary/static/sounds/de/0/pizza.mp3"
["language"]=>
string(3) "und"
}
}
["entries"]=>
array(2) {
[0]=>
array(2) {
["type"]=>
string(7) "related"
["terms"]=>
array(1) {
[0]=>
array(4) {
["type"]=>
string(4) "text"
["text"]=>
string(6) "pizzas"
["language"]=>
string(3) "und"
["labels"]=>
array(1) {
[0]=>
array(1) {
["text"]=>
string(6) "plural"
}
}
}
}
}
[1]=>
array(2) {
["type"]=>
string(7) "meaning"
["terms"]=>
array(1) {
[0]=>
array(3) {
["type"]=>
string(4) "text"
["text"]=>
string(155) "A dish of Italian origin consisting of a flat, round base of dough baked with a topping of tomato sauce and cheese, typically with added meat or vegetables"
["language"]=>
string(2) "en"
}
}
}
}
}
}
}页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/19069756
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