C# XMLNS复杂的反序列化
C# XMLNS复杂的反序列化
提问于 2013-10-27 14:35:54
我正在尝试反序列化XMLNS文件。
<feed xmlns:live="http://www.live.com/marketplace" xmlns="http://www.w3.org/2005/Atom">
<live:totalItems>1177</live:totalItems>
<live:numItems>1</live:numItems>
<title>FindGames Results</title>
<updated>2013-09-19T09:28:02.77Z</updated>
<entry live:itemNum="34" live:detailView="3">
<id>urn:uuid:66ACD000-77FE-1000-9115-D802555308C3</id>
<updated>2013-09-19T09:28:02.77Z</updated>
<title>Rayman® Legends</title>
<content type="text">game content</content>
<live:media>
<live:mediaType>1</live:mediaType>
<live:gameTitleMediaId>urn:uuid:66ACD000-77FE-1000-9115-D802555308C3</live:gameTitleMediaId>
<live:reducedTitle>Rayman® Legends</live:reducedTitle>
<live:reducedDescription>The Glade of Dreams is in trouble once again! During a 100-year nap, nightmares have multiplied and spread, creating new monsters even scarier than before!</live:reducedDescription>
<live:availabilityDate>2013-06-11T00:00:00</live:availabilityDate>
<live:releaseDate>2013-08-29T00:00:00</live:releaseDate>
<live:ratingId>20</live:ratingId>
<live:developer>Ubisoft</live:developer>
<live:publisher>Ubisoft</live:publisher>
<live:newestOfferStartDate>2013-09-13T09:00:00Z</live:newestOfferStartDate>
<live:totalOfferCount>1</live:totalOfferCount>
<live:titleId>1431505091</live:titleId>
<live:effectiveTitleId>1431505091</live:effectiveTitleId>
<live:gameReducedTitle>Rayman® Legends</live:gameReducedTitle>
<live:ratingAggregate>4.50</live:ratingAggregate>
<live:numberOfRatings>1193</live:numberOfRatings>
</live:media>
</entry>
</feed>我的当前代码:反序列化类：
[XmlRoot("feed", Namespace = "http://www.w3.org/2005/Atom")]
public class entry
{
public string title { get; set; }
public string totalItems { get; set; }
public string reducedDescription{ get; set; }
public string ratingId { get; set; }
public string developer { get; set; }
public string publisher { get; set; }
public string tittleId { get; set; }
public string ratingAggregate { get; set; }
public string numberOfRatings { get; set; }
public string boxImage { get; set; }
public string categories { get; set; }
}
class deserializeXML
{
public static void deserialize()
{
using (StreamReader reader = new StreamReader("Query.xml"))
{
XmlSerializer serializer = new XmlSerializer(typeof(entry));
entry x1 = serializer.Deserialize(reader) as entry;
}
}
}我刚收到标题(FindGames结果而不是Rayman传奇)。我需要获得参数后的“输入”和“实时:媒体”，我不知道如何接收参数与“现场：”在开始。
编辑：
[XmlElement(Namespace = "http://www.live.com/marketplace")]
public int numItems { get; set; }
[XmlElement(Namespace = "http://www.live.com/marketplace")]
public int totalItems { get; set; }效果很好，但是：
[XmlElement("media" Namespace="http://www.live.com/marketplace")]
public media media{ get; set; }返回空媒体类:/
回答 1
Stack Overflow用户
回答已采纳
发布于 2013-10-27 15:00:27
您需要显式地将那些不在atom命名空间中的类型和属性映射到它们各自的命名空间。XmlRoot中的命名空间声明只是指定根元素的命名空间。如果文档中有多个名称空间，则需要显式地调用它们。
例如，要正确映射itemNum属性，在entry类中尝试这样做：
[XmlRoot("feed", Namespace = "http://www.w3.org/2005/Atom")]
public class entry
{
[XmlAttribute("itemNum", Namespace = "http://www.live.com/marketplace")]
public int itemNum { get; set; }
public string title { get; set; }
public string totalItems { get; set; }
public string reducedDescription { get; set; }
public string ratingId { get; set; }
public string developer { get; set; }
public string publisher { get; set; }
public string tittleId { get; set; }
public string ratingAggregate { get; set; }
public string numberOfRatings { get; set; }
public string boxImage { get; set; }
public string categories { get; set; }
}然后，您需要声明其他类型，以映射到媒体节点之类的内容中。
class media
{
public int mediaType{ get; set; }
public string reducedDescription{ get; set; }
etc. etc.
}然后，您需要将所有这些“活动”属性从条目类移到新媒体类中，留下一个条目类，如下所示：
[XmlRoot("feed", Namespace = "http://www.w3.org/2005/Atom")]
public class entry
{
[XmlAttribute("itemNum", Namespace = "http://www.live.com/marketplace")]
public int itemNum { get; set; }
public string title { get; set; }
[XmlElement("media" Namespace="http://www.live.com/marketplace")]
public media media{ get; set; }
}您的类层次结构不需要与xml层次结构完全匹配，您可以使用System.Xml.Serialization中的各种属性对C#进行一些重要的重新映射和转换，但是，如果C#类将1:1映射到Xml结构上，那么实现、理解和维护这类东西就更容易了。
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/19619232
复制相关文章
相似问题
腾讯云开发者
