entityMap|0|type|LINK|mutability|MUTABLE|data|url|https://github.com/konradhalas/dacite|blocks|key|9b7k9|text|您可能想看看dacite+library。|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|cmnv5|from+dacite+import+from_dict

def+create_objects(**kwargs):
++++obj1+=+from_dict(data_class=Object1,+data=kwargs)
++++obj2+=+from_dict(data_class=Object2,+data=kwargs)|code-block|syntax|javascript|1kh6g|只要将Config.strict设置为False+(这是默认选项)，它就会自动忽略其他字典键。|style|CODE|esdek^0|6|E|0|0|0|3|D|J|5|0^^$0|$1|$2|3|4|5|6|$7|8]]]|9|@$A|B|C|D|2|E|F|U|G|@]|H|@$I|V|J|W|A|X]]|6|$]]|$A|K|C|L|2|M|F|Y|G|@]|H|@]|6|$N|O]]|$A|P|C|Q|2|E|F|Z|G|@$I|10|J|11|R|S]|$I|12|J|13|R|S]]|H|@]|6|$]]|$A|T|C|-4|2|E|F|14|G|@]|H|@]|6|$]]]]

You might want to take a look at the <a href="https://github.com/konradhalas/dacite" rel="nofollow noreferrer">dacite library</a>.

<pre><code>from dacite import from_dict

def create_objects(**kwargs):
 obj1 = from_dict(data_class=Object1, data=kwargs)
 obj2 = from_dict(data_class=Object2, data=kwargs)
</code></pre>

As long as <code>Config.strict</code> is set to <code>False</code>, which is the default option, it will automatically ignore additional dictionary keys.

entityMap|blocks|key|a208f|text|我目前实现的解决方案是下面的helper函数，在函数内部(kwargs在闭包中)：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4si29|def+get_kwargs_for_class(cls):
++++return+{
++++++++k:+v
++++++++for+k,+v+in+kwargs.items()
++++++++if+k+in+[f.name+for+f+in+dataclasses.fields(cls)]
++++}|code-block|syntax|javascript|82e7j|这使我能够做到这一点：|b2c3u|++++obj1+=+Class1(**get_kwargs_for_class(Class1))
++++obj2+=+Class2(**get_kwargs_for_class(Class2))|armk|在我看来还不算太糟。|86ab6^0|0|0|0|0|0^^$0|$]|1|@$2|3|4|5|6|7|8|O|9|@]|A|@]|B|$]]|$2|C|4|D|6|E|8|P|9|@]|A|@]|B|$F|G]]|$2|H|4|I|6|7|8|Q|9|@]|A|@]|B|$]]|$2|J|4|K|6|E|8|R|9|@]|A|@]|B|$F|G]]|$2|L|4|M|6|7|8|S|9|@]|A|@]|B|$]]|$2|N|4|-4|6|7|8|T|9|@]|A|@]|B|$]]]]

Current solution I've implemented is the following helper function, inside the function (kwargs is in the closure):

<pre><code>def get_kwargs_for_class(cls):
 return {
 k: v
 for k, v in kwargs.items()
 if k in [f.name for f in dataclasses.fields(cls)]
 }
</code></pre>

which enables me to do this:

<pre><code> obj1 = Class1(**get_kwargs_for_class(Class1))
 obj2 = Class2(**get_kwargs_for_class(Class2))
</code></pre>

which doesn't look too bad to me.

entityMap|0|type|LINK|mutability|MUTABLE|data|url|https://docs.python.org/3.5/library/operator.html#operator.itemgetter|blocks|key|94tqo|text|一种解决方案是使用operator.itemgetter。|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|b35ji|例如：|e5is7|from+operator+import+itemgetter
from+dataclasses+import+dataclass

@dataclass
class+Object1:
++++name:+str
++++price:+float

@dataclass
class+Object2:
++++name:+str
++++title:+str

d+=+{'name':'some+name',+'price':+42,+'title':+'some+title'}

def+create_objects(d):
++++i1+=+itemgetter(*Object1.__dataclass_fields__)
++++i2+=+itemgetter(*Object2.__dataclass_fields__)

++++obj1+=+Object1(*i1(d))
++++obj2+=+Object2(*i2(d))

++++print(obj1)
++++print(obj2)

create_objects(d)|code-block|syntax|javascript|5qopc|打印：|9762a|Object1(name='some+name',+price=42)
Object2(name='some+name',+title='some+title')|6no7p^0|9|J|9|J|0|0|0|0|0|0^^$0|$1|$2|3|4|5|6|$7|8]]]|9|@$A|B|C|D|2|E|F|Y|G|@$H|Z|I|10|J|K]]|L|@$H|11|I|12|A|13]]|6|$]]|$A|M|C|N|2|E|F|14|G|@]|L|@]|6|$]]|$A|O|C|P|2|Q|F|15|G|@]|L|@]|6|$R|S]]|$A|T|C|U|2|E|F|16|G|@]|L|@]|6|$]]|$A|V|C|W|2|Q|F|17|G|@]|L|@]|6|$R|S]]|$A|X|C|-4|2|E|F|18|G|@]|L|@]|6|$]]]]

One solution is to use <a href="https://docs.python.org/3.5/library/operator.html#operator.itemgetter" rel="nofollow noreferrer"><code>operator.itemgetter</code></a>.

For example:

<pre><code>from operator import itemgetter
from dataclasses import dataclass

@dataclass
class Object1:
 name: str
 price: float

@dataclass
class Object2:
 name: str
 title: str

d = {'name':'some name', 'price': 42, 'title': 'some title'}

def create_objects(d):
 i1 = itemgetter(*Object1.__dataclass_fields__)
 i2 = itemgetter(*Object2.__dataclass_fields__)

 obj1 = Object1(*i1(d))
 obj2 = Object2(*i2(d))

 print(obj1)
 print(obj2)

create_objects(d)
</code></pre>

Prints:

<pre><code>Object1(name='some name', price=42)
Object2(name='some name', title='some title')
</code></pre>

I'm facing the following problem. I have a bunch of inputs and need to write a function that instantiates several objects (dataclass instances) that need a subset of these inputs. 

So I've got something like: 

<pre class="lang-py prettyprint-override"><code>def create_objects(**kwargs):
 # as you can see some attrs are used in different objects.
 obj1 = Object1(attr1=kwargs.get("attr1"), attr2=kwargs.get("attr2"))
 obj2 = Object2(attr3=kwargs.get("attr3"), attr2=kwargs.get("attr2"))
</code></pre>

Since all these dataclasses require multiple (between 2 and 10) attributes passed on to them, I would like to do some magic like, to check if the Object1 class has a certain property defined in the dataclass:

<pre class="lang-py prettyprint-override"><code> obj1 = Object1(**{k: v for k, v in kwargs.items() if hasattr(Object1, k)})
</code></pre>

Obviously this doesn't work. Is there a way to do this pythonically? 

Or is there a better approach?

What's the pythonic way to instantiate multiple objects from **kwargs?

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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 我正面临着以下问题。我有一堆输入，需要编写一个函数来实例化几个需要这些输入的子集的对象(数据类实例)。 所以我得到了一些类似的东西： def create_objects(**kwargs):    # as you can see some attrs are used in different objects. ...

问从**kwargs实例化多个对象的pythonic方法是什么？
EN

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问从**kwargs实例化多个对象的pythonic方法是什么？EN