blocks|key|614661|text|我觉得应该是这样的|type|unstyled|depth|inlineStyleRanges|entityRanges|data|614662|StoreLiquor.objects.filter(storeID=ID_Store,+liquorID__BottleSize='750+ML',+custom=False).update(StorePrice+=+liquorID__ShelfPrice)|code-block|syntax|javascript|614663|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

I think it should be something like this

<pre><code>StoreLiquor.objects.filter(storeID=ID_Store, liquorID__BottleSize='750 ML', custom=False).update(StorePrice = liquorID__ShelfPrice)
</code></pre>

blocks|key|307354|text|您不能使用liquorID.BottleSize，它是无效的。只能使用有效的变量名。：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|307355|>>>+def+func():pass
>>>+func(a.x=1)
++File+"<ipython-input-22-c75a0f520ac0>",+line+1
SyntaxError:+keyword+can't+be+an+expression|code-block|syntax|javascript|307356|使用liquorID__BottleSize代替。|307357|相关：Why+django+has+to+use+double+underscore+when+making+filter+queries?|307358|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/questions/5481682/why-django-has-to-use-double-underscore-when-making-filter-queries^0|5|J|0|0|2|K|0|3|1V|0|0^^$0|@$1|2|3|4|5|6|7|W|8|@$9|X|A|Y|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|Z|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|10|8|@$9|11|A|12|B|C]]|D|@]|E|$]]|$1|M|3|N|5|6|7|13|8|@]|D|@$9|14|A|15|1|16]]|E|$]]|$1|O|3|-4|5|6|7|17|8|@]|D|@]|E|$]]]|P|$Q|$5|R|S|T|E|$U|V]]]]

You can't use <code>liquorID.BottleSize</code>, it is invalid. You can only use valid variable names.:

<pre><code>&gt;&gt;&gt; def func():pass
&gt;&gt;&gt; func(a.x=1)
 File "&lt;ipython-input-22-c75a0f520ac0&gt;", line 1
SyntaxError: keyword can't be an expression
</code></pre>

Use <code>liquorID__BottleSize</code> instead.

Related: <a href="https://stackoverflow.com/questions/5481682/why-django-has-to-use-double-underscore-when-making-filter-queries">Why django has to use double underscore when making filter queries?</a>

blocks|key|580339|text|我认为这是因为您的命名参数的名称:您不能在其中使用点，所以python对您的liquorID.BottleSize命名参数有问题|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|580340|entityMap^0|12|J|0^^$0|@$1|2|3|4|5|6|7|H|8|@$9|I|A|J|B|C]]|D|@]|E|$]]|$1|F|3|-4|5|6|7|K|8|@]|D|@]|E|$]]]|G|$]]

I think it's because of the name of your named arguments: you can't use dots in them so python has a problem with your <code>liquorID.BottleSize</code> named argument

blocks|key|306474|text|不能在参数名称中使用点，所以这个部分liquorID.BottleSize='750+ML'导致SyntaxError|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|306475|若要在filter中使用相关模型，请使用跨越关系的查找|306476|https://docs.djangoproject.com/en/dev/topics/db/queries/#lookups-that-span-relationships|306477|Django提供了一种强大而直观的方法来“跟踪”查找中的关系，在后台为您自动处理SQL联接。要跨越关系，只需跨模型使用相关字段的字段名，以双下划线分隔，直到到达所需字段为止。
|blockquote|306478|306479|所以你的声明应该是这样的：|306480|StoreLiquor.objects.filter(storeID=ID_Store,+
+++++++++++++++++++++++++++liquorID__BottleSize='750+ML',
+++++++++++++++++++++++++++custom=False).update(StorePrice=liquorID__ShelfPrice)|code-block|syntax|javascript|306481|entityMap|0|LINK|mutability|MUTABLE|url^0|I|S|1C|B|0|3|6|0|0|2G|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|11|8|@$9|12|A|13|B|C]|$9|14|A|15|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|16|8|@$9|17|A|18|B|C]]|D|@]|E|$]]|$1|H|3|I|5|6|7|19|8|@]|D|@$9|1A|A|1B|1|1C]]|E|$]]|$1|J|3|K|5|L|7|1D|8|@]|D|@]|E|$]]|$1|M|3|-4|5|6|7|1E|8|@]|D|@]|E|$]]|$1|N|3|O|5|6|7|1F|8|@]|D|@]|E|$]]|$1|P|3|Q|5|R|7|1G|8|@]|D|@]|E|$S|T]]|$1|U|3|-4|5|6|7|1H|8|@]|D|@]|E|$]]]|V|$W|$5|X|Y|Z|E|$10|I]]]]

You can't use dot in arguments names so this part <code>liquorID.BottleSize='750 ML'</code> causes <code>SyntaxError</code>

to use related models inside <code>filter</code> use lookups that span relationships

<a href="https://docs.djangoproject.com/en/dev/topics/db/queries/#lookups-that-span-relationships" rel="noreferrer">https://docs.djangoproject.com/en/dev/topics/db/queries/#lookups-that-span-relationships</a>

<blockquote>
 Django offers a powerful and intuitive way to “follow” relationships in lookups, taking care of the SQL JOINs for you automatically, behind the scenes. To span a relationship, just use the field name of related fields across models, separated by double underscores, until you get to the field you want.
</blockquote>

So your statement should looks like this:

<pre><code>StoreLiquor.objects.filter(storeID=ID_Store, 
 liquorID__BottleSize='750 ML',
 custom=False).update(StorePrice=liquorID__ShelfPrice)
</code></pre>

I'm getting a syntax error in the following lines of code. I've imported math, but my update function still won't work. Telling me keyword can't be an expression and cites the bottom 3 lines. Any idea what I'm doing wrong?

<pre><code>StoreLiquor.objects.filter(storeID=ID_Store, liquorID.BottleSize='750 ML', custom=False).update(StorePrice = liquorID.ShelfPrice)

StoreLiquor.objects.filter(storeID=ID_Store, liquorID.BottleSize='750 ML', custom=False).update(StorePrice = (float(liquorID.OffPremisePrice)) + (float(S750Increase)))

StoreLiquor.objects.filter(storeID=ID_Store, liquorID.BottleSize='750 ML', custom=False).update(StorePrice = (float(liquorID.OffPremisePrice) * (float(S750Increase)/100)) + float(liquorID.OffPremisePrice))
</code></pre>

django SyntaxError: keyword can't be an expression

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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下面的代码行中出现了语法错误。我已经导入了数学，但是我的更新函数仍然不能工作。告诉我关键字不能是一个表达式，并引用最后3行。知道我做错什么了吗？StoreLiquor.objects.filter(storeID=ID_Store, liquorID.BottleSize='750 ML', custom=False)...

问django SyntaxError:关键字不能是表达式
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