blocks|key|3221768|text|我自己在Tcl手册中找到了解决方案|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|3221769|使用这样的entryconfigure()方法，该方法在单击该值后更改该值：|style|CODE|3221770|第一个参数1必须是要更改的项的索引，从1开始。|3221771|from+tkinter+import+*

root+=+Tk()
menu_bar+=+Menu(root)

def+clicked(menu):
++++menu.entryconfigure(1,+label="Clicked!")

file_menu+=+Menu(menu_bar,+tearoff=False)
file_menu.add_command(label="An+example+item",+command=lambda:+clicked(file_menu))
menu_bar.add_cascade(label="File",+menu=file_menu)

root.config(menu=menu_bar)
root.mainloop()|code-block|syntax|javascript|3221772|entityMap|0|LINK|mutability|MUTABLE|url|http://tcl.tk/man/tcl8.5/TkCmd/menu.htm#M55^0|4|5|0|0|5|G|0|5|1|0|0^^$0|@$1|2|3|4|5|6|7|W|8|@]|9|@$A|X|B|Y|1|Z]]|C|$]]|$1|D|3|E|5|6|7|10|8|@$A|11|B|12|F|G]]|9|@]|C|$]]|$1|H|3|I|5|6|7|13|8|@$A|14|B|15|F|G]]|9|@]|C|$]]|$1|J|3|K|5|L|7|16|8|@]|9|@]|C|$M|N]]|$1|O|3|-4|5|6|7|17|8|@]|9|@]|C|$]]]|P|$Q|$5|R|S|T|C|$U|V]]]]

I found the solution myself in the <a href="http://tcl.tk/man/tcl8.5/TkCmd/menu.htm#M55" rel="noreferrer">Tcl manpages</a>:

Use the <code>entryconfigure()</code> method like so, which changes the value after it has been clicked:

The first parameter <code>1</code> has to be the index of the item you want to change, starting from 1.

<pre class="lang-py prettyprint-override"><code>from tkinter import *

root = Tk()
menu_bar = Menu(root)

def clicked(menu):
 menu.entryconfigure(1, label="Clicked!")

file_menu = Menu(menu_bar, tearoff=False)
file_menu.add_command(label="An example item", command=lambda: clicked(file_menu))
menu_bar.add_cascade(label="File", menu=file_menu)

root.config(menu=menu_bar)
root.mainloop()
</code></pre>

blocks|key|649683|text|我不知道在2.7上是否有不同，但在3.4上不再起作用了。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|649684|在python3.4中，您应该开始使用0计数条目，并使用entryconfig。|offset|length|style|CODE|649685|menu.entryconfig(0,+label+=+"Clicked!")|code-block|syntax|javascript|649686|http://effbot.org/tkinterbook/menu.htm|649687|entityMap|0|LINK|mutability|MUTABLE|url^0|0|S|B|0|0|0|12|0|0^^$0|@$1|2|3|4|5|6|7|V|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|W|8|@$D|X|E|Y|F|G]]|9|@]|A|$]]|$1|H|3|I|5|J|7|Z|8|@]|9|@]|A|$K|L]]|$1|M|3|N|5|6|7|10|8|@]|9|@$D|11|E|12|1|13]]|A|$]]|$1|O|3|-4|5|6|7|14|8|@]|9|@]|A|$]]]|P|$Q|$5|R|S|T|A|$U|N]]]]

I do not know if that used to be different on 2.7, but it does not work on 3.4 anymore.

On python 3.4 you should start counting entries with 0 and use <code>entryconfig</code>.

<pre><code>menu.entryconfig(0, label = "Clicked!")
</code></pre>

<a href="http://effbot.org/tkinterbook/menu.htm" rel="noreferrer">http://effbot.org/tkinterbook/menu.htm</a>

blocks|key|2140157|text|检查这个动态菜单示例。这里的主要功能是您不需要关心菜单项的序列号(索引)。不需要跟踪菜单的索引(位置)。菜单项可以是第一个，也可以是最后一个，没关系。因此，您可以添加新的菜单，而没有索引跟踪(位置)的菜单。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2140158|代码在Python3.6上。|2140159|#+Using+lambda+keyword+and+refresh+function+to+create+a+dynamic+menu.
import+tkinter+as+tk

def+show(x):
++++"""+Show+your+choice+"""
++++global+label
++++new_label+=+'Choice+is:+'+%2B+x
++++menubar.entryconfigure(label,+label=new_label)++#+change+menu+text
++++label+=+new_label++#+update+menu+label+to+find+it+next+time
++++choice.set(x)

def+refresh():
++++"""+Refresh+menu+contents+"""
++++global+label,+l
++++if+l[0]+==+'one':
++++++++l+=+['four',+'five',+'six',+'seven']
++++else:
++++++++l+=+['one',+'two',+'three']
++++choice.set('')
++++menu.delete(0,+'end')++#+delete+previous+contents+of+the+menu
++++menubar.entryconfigure(label,+label=const_str)++#+change+menu+text
++++label+=+const_str++#+update+menu+label+to+find+it+next+time
++++for+i+in+l:
++++++++menu.add_command(label=i,+command=lambda+x=i:+show(x))

root+=+tk.Tk()
#+Set+some+variables
choice+=+tk.StringVar()
const_str+=+'Choice'
label+=+const_str
l+=+['dummy']
#+Create+some+widgets
menubar+=+tk.Menu(root)
root.configure(menu=menubar)
menu+=+tk.Menu(menubar,+tearoff=False)
menubar.add_cascade(label=label,+menu=menu)
b+=+tk.Button(root,+text='Refresh+menu',+command=refresh)
b.pack()
b.invoke()
tk.Label(root,+textvariable=choice).pack()
root.mainloop()|code-block|syntax|javascript|2140160|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|L|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|M|8|@]|9|@]|A|$G|H]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

Check this dynamic menu example. The main feature here is that you don't need to care about a serial number (index) of your menu item. No index (place) of your menu is needed to track. Menu item could be the first or the last, it doesn't matter. So you could add new menus without index tracking (position) of your menus.

The code is on Python 3.6.

<pre><code># Using lambda keyword and refresh function to create a dynamic menu.
import tkinter as tk

def show(x):
 """ Show your choice """
 global label
 new_label = 'Choice is: ' + x
 menubar.entryconfigure(label, label=new_label) # change menu text
 label = new_label # update menu label to find it next time
 choice.set(x)

def refresh():
 """ Refresh menu contents """
 global label, l
 if l[0] == 'one':
 l = ['four', 'five', 'six', 'seven']
 else:
 l = ['one', 'two', 'three']
 choice.set('')
 menu.delete(0, 'end') # delete previous contents of the menu
 menubar.entryconfigure(label, label=const_str) # change menu text
 label = const_str # update menu label to find it next time
 for i in l:
 menu.add_command(label=i, command=lambda x=i: show(x))

root = tk.Tk()
# Set some variables
choice = tk.StringVar()
const_str = 'Choice'
label = const_str
l = ['dummy']
# Create some widgets
menubar = tk.Menu(root)
root.configure(menu=menubar)
menu = tk.Menu(menubar, tearoff=False)
menubar.add_cascade(label=label, menu=menu)
b = tk.Button(root, text='Refresh menu', command=refresh)
b.pack()
b.invoke()
tk.Label(root, textvariable=choice).pack()
root.mainloop()
</code></pre>

Is it possible to change the label of an item in a menu with tkinter? 

In the following example, I'd like to change it from "An example item" (in the "File" menu) to a different value.

<pre class="lang-py prettyprint-override"><code>from tkinter import *

root = Tk()
menu_bar = Menu(root)

file_menu = Menu(menu_bar, tearoff=False)
file_menu.add_command(label="An example item", command=lambda: print('clicked!'))
menu_bar.add_cascade(label="File", menu=file_menu)

root.config(menu=menu_bar)
root.mainloop()
</code></pre>

Update label of tkinter menubar item?

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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是否可以用tkinter更改菜单中项目的标签？在下面的示例中，我希望将其从“示例项”( "File“菜单中)更改为不同的值。from tkinter import *root = Tk()menu_bar = Menu(root)file_menu = Menu(menu_bar, tearoff=False)file...

问更新tkinter菜单项目的标签？
EN

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问更新tkinter菜单项目的标签？EN