blocks|key|2163941|text|if(file.getName().endsWith(".pdf"))+{
++++//it+is+a+.pdf+file!
}|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|2163942|/***/|unstyled|offset|length|style|BOLD|2163943|entityMap^0|0|1|3|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|N|8|@$G|O|H|P|I|J]]|9|@]|A|$]]|$1|K|3|-4|5|F|7|Q|8|@]|9|@]|A|$]]]|L|$]]

<pre><code>if(file.getName().endsWith(".pdf")) {
 //it is a .pdf file!
}
</code></pre>

/***/

blocks|key|3246020|text|对于经过筛选的列表，不需要通过子目录进行递归，只需执行以下操作：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3246021|directory.listFiles(new+FilenameFilter()+{
++++boolean+accept(File+dir,+String+name)+{
++++++++return+name.endsWith(".pdf");
++++}});|code-block|syntax|javascript|3246022|为了提高效率，您可以提前创建FilenameFilter，而不是为每个调用创建。|3246023|在这种情况下，因为您也想扫描子文件夹，所以没有必要过滤文件，因为您仍然需要检查子文件夹。事实上，你差点就到了：|3246024|File+directory+=+new+File(directoryName);

//+get+all+the+files+from+a+directory
File[]+fList+=+directory.listFiles();

for+(File+file+:+fList)+{
++++if+(file.isFile())+{
+++++++if+(file.getName().endsWith(".pdf"))+{
+++++++++++System.out.println(file.getAbsolutePath());
+++++++}
++++}+else+if+(file.isDirectory())+{
++++++++listf(file.getAbsolutePath());
++++}
}|3246025|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Q|8|@]|9|@]|A|$]]|$1|I|3|J|5|6|7|R|8|@]|9|@]|A|$]]|$1|K|3|L|5|D|7|S|8|@]|9|@]|A|$E|F]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

For a filtered list without needing recursion through sub directories you can just do:

<pre><code>directory.listFiles(new FilenameFilter() {
 boolean accept(File dir, String name) {
 return name.endsWith(".pdf");
 }});
</code></pre>

For efficiency you could create the FilenameFilter ahead of time rather than for each call.

In this case because you want to scan sub folders too there is no point filtering the files as you still need to check for sub folders. In fact you were very nearly there:

<pre><code>File directory = new File(directoryName);

// get all the files from a directory
File[] fList = directory.listFiles();

for (File file : fList) {
 if (file.isFile()) {
 if (file.getName().endsWith(".pdf")) {
 System.out.println(file.getAbsolutePath());
 }
 } else if (file.isDirectory()) {
 listf(file.getAbsolutePath());
 }
}
</code></pre>

blocks|key|3246046|text|使用File.listFiles(FileFilter)。|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|3246047|示例：|3246048|File[]+fList+=+directory.listFiles(new+FileFilter()+{
++++@Override
++++public+boolean+accept(File+file)+{
++++++++return+file.getName().endSwith(".pdf");
++++}
});|code-block|syntax|javascript|3246049|entityMap|0|LINK|mutability|MUTABLE|url|http://docs.oracle.com/javase/7/docs/api/java/io/File.html#listFiles%2528java.io.FileFilter%2529^0|2|Q|0|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@$A|T|B|U|1|V]]|C|$]]|$1|D|3|E|5|6|7|W|8|@]|9|@]|C|$]]|$1|F|3|G|5|H|7|X|8|@]|9|@]|C|$I|J]]|$1|K|3|-4|5|6|7|Y|8|@]|9|@]|C|$]]]|L|$M|$5|N|O|P|C|$Q|R]]]]

Use <a href="http://docs.oracle.com/javase/7/docs/api/java/io/File.html#listFiles%28java.io.FileFilter%29" rel="nofollow">File.listFiles(FileFilter)</a>.

Example:

<pre><code>File[] fList = directory.listFiles(new FileFilter() {
 @Override
 public boolean accept(File file) {
 return file.getName().endSwith(".pdf");
 }
});
</code></pre>

blocks|key|3246066|text|尝试在函数FilenameFilter中使用http://docs.oracle.com/javase/6/docs/api/java/io/FilenameFilter.html接口|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|3246067|http://www.mkyong.com/java/how-to-find-files-with-certain-extension-only/+-用于具有扩展筛选器的代码|3246068|entityMap|0|LINK|mutability|MUTABLE|url|http://docs.oracle.com/javase/6/docs/api/java/io/FilenameFilter.html|1|http://www.mkyong.com/java/how-to-find-files-with-certain-extension-only/^0|M|1W|0|0|0|21|1|0^^$0|@$1|2|3|4|5|6|7|P|8|@]|9|@$A|Q|B|R|1|S]]|C|$]]|$1|D|3|E|5|6|7|T|8|@]|9|@$A|U|B|V|1|W]]|C|$]]|$1|F|3|-4|5|6|7|X|8|@]|9|@]|C|$]]]|G|$H|$5|I|J|K|C|$L|M]]|N|$5|I|J|K|C|$L|O]]]]

Try using the FilenameFilter interface in you function
<a href="http://docs.oracle.com/javase/6/docs/api/java/io/FilenameFilter.html" rel="nofollow">http://docs.oracle.com/javase/6/docs/api/java/io/FilenameFilter.html</a>

<a href="http://www.mkyong.com/java/how-to-find-files-with-certain-extension-only/" rel="nofollow">http://www.mkyong.com/java/how-to-find-files-with-certain-extension-only/</a> - for a code that has extention filter

blocks|key|661658|text|您可以使用apache+fileUtils类。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|661659|String[]+exte=+{"xml","properties"};
Collection<File>+files+=+FileUtils.listFiles(new+File("d:\\workspace"),+exte,+true);

for(File+file:+files){
+++++System.out.println(file.getAbsolutePath());
}|code-block|syntax|javascript|661660|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

You can use apache fileUtils class

<pre><code>String[] exte= {"xml","properties"};
Collection&lt;File&gt; files = FileUtils.listFiles(new File("d:\\workspace"), exte, true);

for(File file: files){
 System.out.println(file.getAbsolutePath());
}
</code></pre>

blocks|key|3246091|text|我的建议是使用FileUtils或NIO.2。|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|3246092|NIO.2允许流以深度优先搜索，例如，您可以在一行代码中打印所有扩展名为指定的文件：|3246093|Path+path+=+Path.get("/folder");
try{
++++Files.walk(path).filter(n+->+n.toString().endsWith(".extension")).forEach(System.out::println)
}catch(IOException+e){
++++//Manage+exception
}|code-block|syntax|javascript|3246094|entityMap|0|LINK|mutability|MUTABLE|url|https://commons.apache.org/proper/commons-io/javadocs/api-2.5/org/apache/commons/io/FileUtils.html#listFiles(java.io.File,%2520java.lang.String[],%2520boolean)|1|https://docs.oracle.com/javase/8/docs/technotes/guides/io/|2^0|7|9|0|H|5|1|0|0|5|2|0|0^^$0|@$1|2|3|4|5|6|7|V|8|@]|9|@$A|W|B|X|1|Y]|$A|Z|B|10|1|11]]|C|$]]|$1|D|3|E|5|6|7|12|8|@]|9|@$A|13|B|14|1|15]]|C|$]]|$1|F|3|G|5|H|7|16|8|@]|9|@]|C|$I|J]]|$1|K|3|-4|5|6|7|17|8|@]|9|@]|C|$]]]|L|$M|$5|N|O|P|C|$Q|R]]|S|$5|N|O|P|C|$Q|T]]|U|$5|N|O|P|C|$Q|T]]]]

My advice is to use <a href="https://commons.apache.org/proper/commons-io/javadocs/api-2.5/org/apache/commons/io/FileUtils.html#listFiles(java.io.File,%20java.lang.String[],%20boolean)" rel="nofollow noreferrer">FileUtils</a> or <a href="https://docs.oracle.com/javase/8/docs/technotes/guides/io/" rel="nofollow noreferrer">NIO.2</a>. 
<a href="https://docs.oracle.com/javase/8/docs/technotes/guides/io/" rel="nofollow noreferrer">NIO.2</a> allows Stream with Depth-First search, for example you can print all files with a specified extension in one line of code:

<pre><code>Path path = Path.get("/folder");
try{
 Files.walk(path).filter(n -&gt; n.toString().endsWith(".extension")).forEach(System.out::println)
}catch(IOException e){
 //Manage exception
}
</code></pre>

I am writing a method to get specific file type such as pdf or txt from folders and subfolders but I am lacking to solve this problem. here is my code 

<pre><code> // .............list file
 File directory = new File(directoryName);

 // get all the files from a directory
 File[] fList = directory.listFiles();

 for (File file : fList) {
 if (file.isFile()) {
 System.out.println(file.getAbsolutePath());
 } else if (file.isDirectory()) {
 listf(file.getAbsolutePath());
 }
 }
</code></pre>

My current method list all files but I need specific files

find specific file type from folder and its sub folder

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我正在编写一种方法来获取特定的文件类型，例如pdf或txt，从文件夹和子文件夹获得，但我缺乏解决这个问题的方法。这是我的密码  // .............list file    File directory = new File(directoryName);    // get all the files f...

问从文件夹及其子文件夹中查找特定的文件类型
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问从文件夹及其子文件夹中查找特定的文件类型EN