blocks|key|1067363|text|您应该根据ids给出一个"+on“。像这样|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1067364|inner+join+users+on+users.id+=+totals.idseller+|code-block|syntax|javascript|1067365|否则，sql服务器将合并表中所有可能的行，这在大多数情况下都不是您所希望的。|1067366|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

You should give an "on" based on the ids. Such as like

<pre><code>inner join users on users.id = totals.idseller 
</code></pre>

Otherways the sql server will combine all possible rows in the tables, which is most cases not what you wish.

blocks|key|2101680|text|当您内部连接到另一个表时，返回的数据集将被修改为只包含两个表中存在的行。在这种情况下，“总计”中可能有在用户中没有匹配行的行--+totals.idseller字段可能接受空值，或者当匹配的用户被删除或编辑时，数据变成孤儿。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2101681|如果您想要“总计”中的所有数据，而不管是否匹配用户，您将在ms-sql中使用一个左联接，我怀疑类似的方法将在my-sql中工作。|2101682|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|F|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|G|8|@]|9|@]|A|$]]|$1|D|3|-4|5|6|7|H|8|@]|9|@]|A|$]]]|E|$]]

When you INNER JOIN to another table, the returned data set is modified to only include rows that exist in both tables. In this case it is likely that there are rows in 'totals' that do not have a matching row in users - either the totals.idseller field might accept null values, or data has become orphaned when matching users have been deleted or edited.

If you want all data in 'totals' regardless of matching user you would user a LEFT JOIN instead in ms-sql, I suspect a similar approach will work in my-sql

blocks|key|2132820|text|因为当您在SQL查询中添加内部联接时，这意味着您要选择两个表中常见的数据。例：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2132821|SELECT+*+FROM+TABLE_A
INNER+JOIN+TABLE_B+
ON+TABLE_A.ID+=+TABLE_B.ID|code-block|syntax|javascript|2132822|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Because when you are adding inner join in your SQL Query, it means you are selecting the data which is common in both the tables.
EX:

<pre><code>SELECT * FROM TABLE_A
INNER JOIN TABLE_B 
ON TABLE_A.ID = TABLE_B.ID
</code></pre>

blocks|key|2132850|text|如果要加入users表，其中包含5条记录。通过连接表，因为没有任何列映射，这个汇总5次，这是显示不同值的原因。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2132851|请让我知道里面有什么问题。|2132852|谢谢，乌梅斯|2132853|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|H|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|I|8|@]|9|@]|A|$]]|$1|D|3|E|5|6|7|J|8|@]|9|@]|A|$]]|$1|F|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|G|$]]

If you are joining users table which contains 5 records. By joining table, as there is no any column mapping, this sum-up 5 times and this is reason for showing different values.

Please let me know something wrong in it.

Thanks,
Umehs

blocks|key|2132886|text|$sql+=+mysql_query("SELECT+totals.*,+sum(totals.payments)+as+total_payments+FROM+totals
INNER+JOIN+users+ON+totals.idseller+=+users.idseller
GROUP+BY+users.UserName;");|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|2132887|利用这个希望这会帮你的。|unstyled|2132888|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|J|8|@]|9|@]|A|$]]|$1|G|3|-4|5|F|7|K|8|@]|9|@]|A|$]]]|H|$]]

<pre><code>$sql = mysql_query("SELECT totals.*, sum(totals.payments) as total_payments FROM totals
INNER JOIN users ON totals.idseller = users.idseller
GROUP BY users.UserName;");
</code></pre>

Use this Hope this will help you.

<pre><code> $sql = mysql_query("SELECT totals.*, sum(totals.payments) as total_payments
FROM totals
 INNER JOIN users
 GROUP BY totals.idseller;");
</code></pre>

When i add the INNER JOIN the sum value is changed. Why?

In my SQL table i have one record in totals width this value: 8943.09 but when i do the some the result is giving me this value: 44715.45

What i am doing wrong?

SUM value from query changes when i add inner join to the query

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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    $sql = mysql_query("SELECT totals.*, sum(totals.payments) as total_paymentsFROM totals    INNER JOIN users    GROUP BY totals.idseller;");当我添加内部联接时，和值将被更改。为...

问当我向查询中添加内部联接时，查询中的和值将发生更改。
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问当我向查询中添加内部联接时，查询中的和值将发生更改。EN