我有以下几种型号:
class Volunteer(models.Model):
    first_name = models.CharField(max_length=50L)
    last_name = models.CharField(max_length=50L)    
    email = models.CharField(max_length=50L)
    gender = models.CharField(max_length=1, choices=GENDER_CHOICES)
class Department(models.Model):
    name = models.CharField(max_length=50L, unique=True)
    overseer = models.ForeignKey(Volunteer, blank=True, null=True)
    location = models.CharField(max_length=100L, null=True)
class DepartmentVolunteer(models.Model):
    volunteer = models.ForeignKey(Volunteer)
    department = models.ForeignKey(Department)
    assistant = models.BooleanField(default=False)
    keyman = models.BooleanField(default=False)
    captain = models.BooleanField(default=False)
    location = models.CharField(max_length=100L, blank=True, null=True)我想查询所有没有志愿者的部门。我可以使用以下查询来做到这一点:
SELECT 
    d.name 
FROM   
    vsp_department AS d
LEFT JOIN vsp_departmentvolunteer AS dv
ON d.id = dv.department_id  
WHERE
    dv.department_id IS NULL;是否有一种更像django的方法来这样做,或者我应该只使用原始sql?
发布于 2017-06-27 08:40:51
通过或创建自定义连接
def get_queryset(self):
    qs = super(AceViewSet, self).get_queryset()
    qs = qs.select_related('xxx')
    # construct all tables and the join dependence
    qs.query.__str__()
    qs.query.alias_map['xx_subject'].join_cols = (('xxx_id', 'uid'), ('xxx_id', 'ad_subject_id'))
    qs.query.alias_map['xx_subject'].as_sql = partial(self.as_sql, qs.query.alias_map['xx_subject'])
    return qs
@staticmethod
def as_sql(self, compiler, connection):
    sql, params = Join.as_sql(self, compiler, connection)
    or_sql = sql.replace("AND", "OR")
    return or_sql, paramsFROM "xx_ace"
  LEFT OUTER JOIN "xx_subject"
    ON ("xx_ace"."xxx_id" = "xx_subject"."uid" OR "xx_ace"."xxx_id" = "xx_subject"."ad_subject_id")https://stackoverflow.com/questions/21271835
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