blocks|key|2717044|text|我相信你应该这么做|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2717045|users.sort_by!(&:distance).includes(:photo)|code-block|syntax|javascript|2717046|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

I believe you should do 

<pre><code>users.sort_by!(&amp;:distance).includes(:photo)
</code></pre>

blocks|key|2717079|text|对我来说是这样的。我做“用户”，而不是“用户”|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2717080|User.includes(:photo).sort_by!(&:distance)|code-block|syntax|javascript|2717081|“用户”变量到底持有什么？试一试用户。|2717082|与我的例子编辑，这里我的用户查询用户和得分的距离。|2717083|++++1.9.3p385+:059+>+Enquiry.all.sort_by!(&:score).map+&:score
++++++Enquiry+Load+(0.7ms)++SELECT+`enquiries`.*+FROM+`enquiries`+
+++++=>+[1,+1,+1,+1,+1,+1,+1,+1,+1,+1,+1,+1,+1,+1,+1,+1,+1,+1,+1,+1,+1,+1,+1,+1,+1,+1,+1,+1,+1,+1,+1,+1,+1,+1,+1,+1,+1,+1,+3,+5,+5,+5,+5,+5,+5,+5,+5,+5,+5,+5,+6,+7,+8,+8,+10,+10]+

++++1.9.3p385+:060+>+Enquiry.includes(:follow_ups).sort_by!(&:score).map+&:score
++++++Enquiry+Load+(0.1ms)++SELECT+`enquiries`.*+FROM+`enquiries`+
++++++FollowUp+Load+(0.1ms)++SELECT+`follow_ups`.*+FROM+`follow_ups`+WHERE+`follow_ups`.`enquiry_id`+IN+(55,+64,+65,+67,+68,+69,+70,+71,+72,+73,+74,+75,+76,+77,+78,+79,+80,+85,+86,+89,+91,+92,+93,+95,+96,+97,+98,+99,+100,+101,+102,+103,+104,+105,+106,+107,+108,+109,+110,+111,+112,+113,+114,+115,+116,+117,+118,+119,+120,+121,+122,+123,+124,+125,+126,+127)
+++++=>+[1,+1,+1,+1,+1,+1,+1,+1,+1,+1,+1,+1,+1,+1,+1,+1,+1,+1,+1,+1,+1,+1,+1,+1,+1,+1,+1,+1,+1,+1,+1,+1,+1,+1,+1,+1,+1,+1,+3,+5,+5,+5,+5,+5,+5,+5,+5,+5,+5,+5,+6,+7,+8,+8,+10,+10]+

1.9.3p385+:057+>+enquiries+=+Enquiry.where(status_id:+[1,2,3])

++++1.9.3p385+:061+>+enquiries.includes(:follow_ups).sort_by!(&:score).map+&:score
++++++Enquiry+Load+(0.5ms)++SELECT+`enquiries`.*+FROM+`enquiries`+WHERE+`enquiries`.`status_id`+IN+(1,+2,+3)
++++++FollowUp+Load+(0.2ms)++SELECT+`follow_ups`.*+FROM+`follow_ups`+WHERE+`follow_ups`.`enquiry_id`+IN+(68,+75,+78,+91,+95,+96,+97,+98,+99,+100,+101,+102,+103,+104,+105,+106,+107,+108,+113,+114,+115,+116,+117,+120,+122,+123,+124,+125,+126,+127)
+++++=>+[1,+1,+1,+1,+1,+1,+1,+1,+1,+1,+1,+1,+1,+1,+1,+1,+1,+3,+5,+5,+5,+5,+5,+5,+5,+5,+7,+8,+8,+10]+|2717084|注意:你的问题错了，你否决了我。|2717085|entityMap^0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|S|8|@]|9|@]|A|$]]|$1|I|3|J|5|6|7|T|8|@]|9|@]|A|$]]|$1|K|3|L|5|D|7|U|8|@]|9|@]|A|$E|F]]|$1|M|3|N|5|6|7|V|8|@]|9|@]|A|$]]|$1|O|3|-4|5|6|7|W|8|@]|9|@]|A|$]]]|P|$]]

Well it does for me. I do "User", not "users"

<pre><code>User.includes(:photo).sort_by!(&amp;:distance)
</code></pre>

What does "users" variable hold, anyway?. Try User.

Edited with my example, here I user Enquiry for User and Score for Distance.

<pre><code> 1.9.3p385 :059 &gt; Enquiry.all.sort_by!(&amp;:score).map &amp;:score
 Enquiry Load (0.7ms) SELECT `enquiries`.* FROM `enquiries` 
 =&gt; [1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 3, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 6, 7, 8, 8, 10, 10] 

 1.9.3p385 :060 &gt; Enquiry.includes(:follow_ups).sort_by!(&amp;:score).map &amp;:score
 Enquiry Load (0.1ms) SELECT `enquiries`.* FROM `enquiries` 
 FollowUp Load (0.1ms) SELECT `follow_ups`.* FROM `follow_ups` WHERE `follow_ups`.`enquiry_id` IN (55, 64, 65, 67, 68, 69, 70, 71, 72, 73, 74, 75, 76, 77, 78, 79, 80, 85, 86, 89, 91, 92, 93, 95, 96, 97, 98, 99, 100, 101, 102, 103, 104, 105, 106, 107, 108, 109, 110, 111, 112, 113, 114, 115, 116, 117, 118, 119, 120, 121, 122, 123, 124, 125, 126, 127)
 =&gt; [1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 3, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 6, 7, 8, 8, 10, 10] 

1.9.3p385 :057 &gt; enquiries = Enquiry.where(status_id: [1,2,3])

 1.9.3p385 :061 &gt; enquiries.includes(:follow_ups).sort_by!(&amp;:score).map &amp;:score
 Enquiry Load (0.5ms) SELECT `enquiries`.* FROM `enquiries` WHERE `enquiries`.`status_id` IN (1, 2, 3)
 FollowUp Load (0.2ms) SELECT `follow_ups`.* FROM `follow_ups` WHERE `follow_ups`.`enquiry_id` IN (68, 75, 78, 91, 95, 96, 97, 98, 99, 100, 101, 102, 103, 104, 105, 106, 107, 108, 113, 114, 115, 116, 117, 120, 122, 123, 124, 125, 126, 127)
 =&gt; [1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 3, 5, 5, 5, 5, 5, 5, 5, 5, 7, 8, 8, 10] 
</code></pre>

Note: your question is wrong and you downvote me.

blocks|key|4312956|text|用这个：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4312957|User.includes(:photo).sort_by!(&:distance)|code-block|syntax|javascript|4312958|包含用于模型，而不是数组。因此，用户是模型名，用户是数组。|4312959|数组有“包括？”方法和|4312960|模型有“包括”方法|4312961|所以用这个|4312962|+User.includes(:photo).sort_by!(&:distance)|4312963|而不是|4312964|users.includes(:photo).sort_by!(&:distance)|4312965|entityMap^0|0|0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|W|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|X|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Y|8|@]|9|@]|A|$]]|$1|I|3|J|5|6|7|Z|8|@]|9|@]|A|$]]|$1|K|3|L|5|6|7|10|8|@]|9|@]|A|$]]|$1|M|3|N|5|6|7|11|8|@]|9|@]|A|$]]|$1|O|3|P|5|D|7|12|8|@]|9|@]|A|$E|F]]|$1|Q|3|R|5|6|7|13|8|@]|9|@]|A|$]]|$1|S|3|T|5|D|7|14|8|@]|9|@]|A|$E|F]]|$1|U|3|-4|5|6|7|15|8|@]|9|@]|A|$]]]|V|$]]

Use this:

<pre><code>User.includes(:photo).sort_by!(&amp;:distance)
</code></pre>

includes is used for Model, not for array.
so User is model name and users is array.

array have 'includes?' method and

Model have 'include' method

So use this

<pre><code> User.includes(:photo).sort_by!(&amp;:distance)
</code></pre>

instead of 

<pre><code>users.includes(:photo).sort_by!(&amp;:distance)
</code></pre>

blocks|key|252318|text|!方法中的sort_by!指示对象本身被更改，而不是返回不同的对象。当您调用users.includes(:photo)时，此方法返回一个不同的对象。所以，你实际上所做的是：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|252319|users2+=+users.includes(:photo)
users2.sort_by!(&:distance)|code-block|syntax|javascript|252320|这就是为什么在调用sort_by!之后用户对象没有排序的原因。一个更好的方法可能是|252321|users+=+users.includes(:photo).sort_by(&:distance)|252322|entityMap^0|0|1|5|8|12|M|0|0|9|8|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@$9|R|A|S|B|C]|$9|T|A|U|B|C]|$9|V|A|W|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|X|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|Y|8|@$9|Z|A|10|B|C]]|D|@]|E|$]]|$1|M|3|N|5|H|7|11|8|@]|D|@]|E|$I|J]]|$1|O|3|-4|5|6|7|12|8|@]|D|@]|E|$]]]|P|$]]

the <code>!</code> in the <code>sort_by!</code> method indicates that the object itself is changed rather than returns a different object.
When you call <code>users.includes(:photo)</code> this method returns a different object. So, what you are actually doing is like:

<pre><code>users2 = users.includes(:photo)
users2.sort_by!(&amp;:distance)
</code></pre>

This is why the users object is not sorted after you call <code>sort_by!</code>. A better way to do it might be

<pre><code>users = users.includes(:photo).sort_by(&amp;:distance)
</code></pre>

I've got a distance attribute in my User model :

<pre><code>attr_accessor :distance
</code></pre>

So when I calculate the distance for each user, and store it in the distance then I can sort them like :

<pre><code>users.sort_by!(&amp;:distance)
</code></pre>

And the users get sorted according to the distance appropriately. But when I include other associated methods i.e :

<pre><code>users.includes(:photo).sort_by!(&amp;:distance)
</code></pre>

This doesn't sort the users at all, why is this? How can I sort it with distance but include association as well?

Sort by doesn't sort when includes is used in rails

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我的用户模型中有一个距离属性：attr_accessor :distance因此，当我计算每个用户的距离，并将其存储在远处时，我可以对它们排序如下：users.sort_by!(&:distance)并根据距离对用户进行适当的排序。但当我包括其他相关方法时，即：users.includes(:photo).sort_b...

问在rails中使用包含时，Sort不排序
EN

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问在rails中使用包含时，Sort不排序EN