blocks|key|3709398|text|我敢肯定你的正则表达式有错误。您正在寻找文本：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3709399|url+uid“href://vkontakte.ru/uid+10550933”
|blockquote|3709400|3709401|看上去是空格错误？|3709402|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|J|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|K|8|@]|9|@]|A|$]]|$1|E|3|-4|5|6|7|L|8|@]|9|@]|A|$]]|$1|F|3|G|5|6|7|M|8|@]|9|@]|A|$]]|$1|H|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|I|$]]

I'm pretty sure you have an error in your regex. You are looking for the text:

<blockquote>
 url uid" href://vkontakte.ru/id10550933"
</blockquote>

Looks like whitespace error?

blocks|key|700696|text|为什么不使用导入的bs4呢？|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|700697|如果希望使用类href和url打印a元素的uid属性，则可以使用+method+(which+accept+css+selector)。|700698|import+urllib.request

import+bs4

stringHtml+=+urllib.request.urlopen('http://forum.saransk.ru/user/2018-sergey-kalinin/').read()#.decode('utf-8')
soup+=+bs4.BeautifulSoup(stringHtml)
for+a+in+soup.select('a.url.uid'):
++++print(a.get('href'))

#+If+you+want+to+check+whether+the+a+tag+with+`href="http://vkontakte..."`+exist,
#+++use+following+lines+instead.
#+(CSS+Selector+`a.url.uid[href="..."]`+does+not+work+with+bs4.
#++bs4+supports+most+commonly-used+CSS+selectors,+not+all+of+them)
#print(any(a.get('href')+==+'http://vkontakte.ru/id10550933'
#++++++for+a+in+soup.select('a.url.uid')))|code-block|syntax|javascript|700699|产出：|700700|http://vkontakte.ru/id10550933|700701|entityMap|0|LINK|mutability|MUTABLE|url|http://www.crummy.com/software/BeautifulSoup/bs4/doc/#css-selectors^0|9|3|0|7|4|C|3|H|1|L|3|W|Z|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Y|8|@$9|Z|A|10|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|11|8|@$9|12|A|13|B|C]|$9|14|A|15|B|C]|$9|16|A|17|B|C]|$9|18|A|19|B|C]]|D|@$9|1A|A|1B|1|1C]]|E|$]]|$1|H|3|I|5|J|7|1D|8|@]|D|@]|E|$K|L]]|$1|M|3|N|5|6|7|1E|8|@]|D|@]|E|$]]|$1|O|3|P|5|J|7|1F|8|@]|D|@]|E|$K|L]]|$1|Q|3|-4|5|6|7|1G|8|@]|D|@]|E|$]]]|R|$S|$5|T|U|V|E|$W|X]]]]

Why don't you use <code>bs4</code> imported?

If you want print <code>href</code> attribute of the <code>a</code> element with class <code>uid</code> and <code>url</code>, you can use <a href="http://www.crummy.com/software/BeautifulSoup/bs4/doc/#css-selectors" rel="nofollow"><code>select</code> method (which accept css selector)</a>.

<pre><code>import urllib.request

import bs4

stringHtml = urllib.request.urlopen('http://forum.saransk.ru/user/2018-sergey-kalinin/').read()#.decode('utf-8')
soup = bs4.BeautifulSoup(stringHtml)
for a in soup.select('a.url.uid'):
 print(a.get('href'))

# If you want to check whether the a tag with `href="http://vkontakte..."` exist,
# use following lines instead.
# (CSS Selector `a.url.uid[href="..."]` does not work with bs4.
# bs4 supports most commonly-used CSS selectors, not all of them)
#print(any(a.get('href') == 'http://vkontakte.ru/id10550933'
# for a in soup.select('a.url.uid')))
</code></pre>

output:

<pre><code>http://vkontakte.ru/id10550933
</code></pre>

blocks|key|1243551|text|页面源显示|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1243552|<a+class="url+uid"+rel="external+me"+href="http://vkontakte.ru/id10550933">http://vkontakte.ru/id10550933</a>|code-block|syntax|javascript|1243553|所以你想要的是|1243554|import+bs4
import+requests

url+=+'http://forum.saransk.ru/user/2018-sergey-kalinin/'
html+=+requests.get(url).content
page+=+bs4.BeautifulSoup(html)
link+=+page.find("a",+{"class":+"url+uid"})
print(link["href"])|1243555|这给|1243556|http://vkontakte.ru/id10550933|1243557|entityMap^0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|S|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|U|8|@]|9|@]|A|$]]|$1|M|3|N|5|D|7|V|8|@]|9|@]|A|$E|F]]|$1|O|3|-4|5|6|7|W|8|@]|9|@]|A|$]]]|P|$]]

The page source shows

<pre><code>&lt;a class="url uid" rel="external me" href="http://vkontakte.ru/id10550933"&gt;http://vkontakte.ru/id10550933&lt;/a&gt;
</code></pre>

so what you want is something like

<pre><code>import bs4
import requests

url = 'http://forum.saransk.ru/user/2018-sergey-kalinin/'
html = requests.get(url).content
page = bs4.BeautifulSoup(html)
link = page.find("a", {"class": "url uid"})
print(link["href"])
</code></pre>

which gives

<pre><code>http://vkontakte.ru/id10550933
</code></pre>

please help to fix the script.

<pre><code>import urllib
import re
import os
import pprint

import requests
import bs4

stringHtml = urllib.request.urlopen('http://forum.saransk.ru/user/2018-sergey-kalinin/').read().decode('utf-8')
#print(stringHtml)
stringPattern = 'url\suid"\shref="http://vkontakte.ru/id10550933"'
result = re.search(stringPattern, stringHtml)
if result:
 print(result.group())
else:
 print('no result') 
</code></pre>

the problem is that the script displays a "no result". compiled regular expression correctly. please help find an error

how to search for a phrase using regular expressions?

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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请帮我修一下剧本。import urllibimport reimport osimport pprintimport requestsimport bs4stringHtml = urllib.request.urlopen('http://forum.saransk.ru/user/2018-sergey-kali...

问如何使用正则表达式搜索短语？
EN

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